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Calculate the total force of the atmosphere acting on the top of a table that measures $\SI{1.6}{m}\times\SI{2.9}{m}$. What is the total foce acting upward on the underside of the table?
$\SI{4.64e5}{N}$
The force acting on this table is: \begin{align} F &= p \cdot A\\ &= \SI{e5}{Pa} \cdot \SI{4.64}{\meter\squared}\\ &= \SI{4.64e5}{N} \end{align} This force acts on both sides of the table  up and downwards. Hence the two forces cancel each other out. Of course, this needs to be like this. If a netforce would act on the table, it would either move upwards or being crashed to the floor.
11:21, 17. May 2017  si  Urs Zellweger (urs)  Current Version 