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Auf welche Höhe über dem Erdboden müsste man einen Kubikmeter Wasser bringen, damit seine potentielle Energie $\SI{5.1e2}{kJ}$ beträgt?
\begin{align} h &= \frac{\Epot}{mg}\\ &= \frac{\SI{5.1e5}{J}}{\SI{1000}{kg}\cdot\SI{10}{\meter\per\second\squared}}\\ &= \SI{5.1e1}{m} \end{align}
21:05, 25. June 2018 | Initial Version. | Urs Zellweger (urs) | Current Version |