Top Flop Lack Kack
About points...
We associate a certain number of points with each exercise.
When you click an exercise into a collection, this number will be taken as points for the exercise, kind of "by default".
But once the exercise is on the collection, you can edit the number of points for the exercise in the collection independently, without any effect on "points by default" as represented by the number here.
That being said... How many "default points" should you associate with an exercise upon creation?
As with difficulty, there is no straight forward and generally accepted way.
But as a guideline, we tend to give as many points by default as there are mathematical steps to do in the exercise.
Again, very vague... But the number should kind of represent the "work" required.
When you click an exercise into a collection, this number will be taken as points for the exercise, kind of "by default".
But once the exercise is on the collection, you can edit the number of points for the exercise in the collection independently, without any effect on "points by default" as represented by the number here.
That being said... How many "default points" should you associate with an exercise upon creation?
As with difficulty, there is no straight forward and generally accepted way.
But as a guideline, we tend to give as many points by default as there are mathematical steps to do in the exercise.
Again, very vague... But the number should kind of represent the "work" required.
About difficulty...
We associate a certain difficulty with each exercise.
When you click an exercise into a collection, this number will be taken as difficulty for the exercise, kind of "by default".
But once the exercise is on the collection, you can edit its difficulty in the collection independently, without any effect on the "difficulty by default" here.
Why we use chess pieces? Well... we like chess, we like playing around with \(\LaTeX\)-fonts, we wanted symbols that need less space than six stars in a table-column... But in your layouts, you are of course free to indicate the difficulty of the exercise the way you want.
That being said... How "difficult" is an exercise? It depends on many factors, like what was being taught etc.
In physics exercises, we try to follow this pattern:
Level 1 - One formula (one you would find in a reference book) is enough to solve the exercise. Example exercise
Level 2 - Two formulas are needed, it's possible to compute an "in-between" solution, i.e. no algebraic equation needed. Example exercise
Level 3 - "Chain-computations" like on level 2, but 3+ calculations. Still, no equations, i.e. you are not forced to solve it in an algebraic manner. Example exercise
Level 4 - Exercise needs to be solved by algebraic equations, not possible to calculate numerical "in-between" results. Example exercise
Level 5 -
Level 6 -
When you click an exercise into a collection, this number will be taken as difficulty for the exercise, kind of "by default".
But once the exercise is on the collection, you can edit its difficulty in the collection independently, without any effect on the "difficulty by default" here.
Why we use chess pieces? Well... we like chess, we like playing around with \(\LaTeX\)-fonts, we wanted symbols that need less space than six stars in a table-column... But in your layouts, you are of course free to indicate the difficulty of the exercise the way you want.
That being said... How "difficult" is an exercise? It depends on many factors, like what was being taught etc.
In physics exercises, we try to follow this pattern:
Level 1 - One formula (one you would find in a reference book) is enough to solve the exercise. Example exercise
Level 2 - Two formulas are needed, it's possible to compute an "in-between" solution, i.e. no algebraic equation needed. Example exercise
Level 3 - "Chain-computations" like on level 2, but 3+ calculations. Still, no equations, i.e. you are not forced to solve it in an algebraic manner. Example exercise
Level 4 - Exercise needs to be solved by algebraic equations, not possible to calculate numerical "in-between" results. Example exercise
Level 5 -
Level 6 -
Question
Solution
Short
Video
\(\LaTeX\)
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Exercise:
abcliste abc Ut enim ad minim veniam pq quis nostrud exercitation ullamco laboris nisi ut pqm? abc Auf einem bestimmten Himmelskörper wiege ein Körper der Masse pq.kg nur pqN. Berechne den Ortsfaktor dieses Himmelskörpers. abc Berechne die Masse eines Körpers vom Volumen pq.mm^ wenn dieser eine Dichte von pqgpcmk hat. abc Welche Last Gewichtskraft könnte mit einem Faktorenflaschenzug an welchem du neun trage Seile zählst mit einer Kraft von pqN hochgezogen werden? abc Wie stark Kraft müsste man an einem Potenzflaschenzug mit fünf losen Rollen ziehen um eine Last von pqN anzuheben? abc Welches Drehmoment wirkt wenn eine Kraft von pq.kN mit einem Hebelarm von pqcm wirkt? abcliste
Solution:
abcliste abc Die Zeit um die gegebene Strecke zurückzulegen beträgt: t fracsv fracpqmpq. pq.s abc Der Ortsfaktor ist: g fracFm fracpqNpq.kg pq.Npkg abc Die Masse des Körpers beträgt: m rho V pqkgpmk pq.m^ pq.kg abc Die maximale Lastkraft beträgt: F_L F_Z N pqN pq.eN abc Die nötige Zugkraft ist: F_Z fracF_L^N fracpqN^ pq.eN abc Das Drehmoment beträgt: M Fl pqNpq.m pq.eNm abcliste
abcliste abc Ut enim ad minim veniam pq quis nostrud exercitation ullamco laboris nisi ut pqm? abc Auf einem bestimmten Himmelskörper wiege ein Körper der Masse pq.kg nur pqN. Berechne den Ortsfaktor dieses Himmelskörpers. abc Berechne die Masse eines Körpers vom Volumen pq.mm^ wenn dieser eine Dichte von pqgpcmk hat. abc Welche Last Gewichtskraft könnte mit einem Faktorenflaschenzug an welchem du neun trage Seile zählst mit einer Kraft von pqN hochgezogen werden? abc Wie stark Kraft müsste man an einem Potenzflaschenzug mit fünf losen Rollen ziehen um eine Last von pqN anzuheben? abc Welches Drehmoment wirkt wenn eine Kraft von pq.kN mit einem Hebelarm von pqcm wirkt? abcliste
Solution:
abcliste abc Die Zeit um die gegebene Strecke zurückzulegen beträgt: t fracsv fracpqmpq. pq.s abc Der Ortsfaktor ist: g fracFm fracpqNpq.kg pq.Npkg abc Die Masse des Körpers beträgt: m rho V pqkgpmk pq.m^ pq.kg abc Die maximale Lastkraft beträgt: F_L F_Z N pqN pq.eN abc Die nötige Zugkraft ist: F_Z fracF_L^N fracpqN^ pq.eN abc Das Drehmoment beträgt: M Fl pqNpq.m pq.eNm abcliste
Meta Information
Exercise:
abcliste abc Ut enim ad minim veniam pq quis nostrud exercitation ullamco laboris nisi ut pqm? abc Auf einem bestimmten Himmelskörper wiege ein Körper der Masse pq.kg nur pqN. Berechne den Ortsfaktor dieses Himmelskörpers. abc Berechne die Masse eines Körpers vom Volumen pq.mm^ wenn dieser eine Dichte von pqgpcmk hat. abc Welche Last Gewichtskraft könnte mit einem Faktorenflaschenzug an welchem du neun trage Seile zählst mit einer Kraft von pqN hochgezogen werden? abc Wie stark Kraft müsste man an einem Potenzflaschenzug mit fünf losen Rollen ziehen um eine Last von pqN anzuheben? abc Welches Drehmoment wirkt wenn eine Kraft von pq.kN mit einem Hebelarm von pqcm wirkt? abcliste
Solution:
abcliste abc Die Zeit um die gegebene Strecke zurückzulegen beträgt: t fracsv fracpqmpq. pq.s abc Der Ortsfaktor ist: g fracFm fracpqNpq.kg pq.Npkg abc Die Masse des Körpers beträgt: m rho V pqkgpmk pq.m^ pq.kg abc Die maximale Lastkraft beträgt: F_L F_Z N pqN pq.eN abc Die nötige Zugkraft ist: F_Z fracF_L^N fracpqN^ pq.eN abc Das Drehmoment beträgt: M Fl pqNpq.m pq.eNm abcliste
abcliste abc Ut enim ad minim veniam pq quis nostrud exercitation ullamco laboris nisi ut pqm? abc Auf einem bestimmten Himmelskörper wiege ein Körper der Masse pq.kg nur pqN. Berechne den Ortsfaktor dieses Himmelskörpers. abc Berechne die Masse eines Körpers vom Volumen pq.mm^ wenn dieser eine Dichte von pqgpcmk hat. abc Welche Last Gewichtskraft könnte mit einem Faktorenflaschenzug an welchem du neun trage Seile zählst mit einer Kraft von pqN hochgezogen werden? abc Wie stark Kraft müsste man an einem Potenzflaschenzug mit fünf losen Rollen ziehen um eine Last von pqN anzuheben? abc Welches Drehmoment wirkt wenn eine Kraft von pq.kN mit einem Hebelarm von pqcm wirkt? abcliste
Solution:
abcliste abc Die Zeit um die gegebene Strecke zurückzulegen beträgt: t fracsv fracpqmpq. pq.s abc Der Ortsfaktor ist: g fracFm fracpqNpq.kg pq.Npkg abc Die Masse des Körpers beträgt: m rho V pqkgpmk pq.m^ pq.kg abc Die maximale Lastkraft beträgt: F_L F_Z N pqN pq.eN abc Die nötige Zugkraft ist: F_Z fracF_L^N fracpqN^ pq.eN abc Das Drehmoment beträgt: M Fl pqNpq.m pq.eNm abcliste
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