Ausgekuppeltes Auto
About points...
We associate a certain number of points with each exercise.
When you click an exercise into a collection, this number will be taken as points for the exercise, kind of "by default".
But once the exercise is on the collection, you can edit the number of points for the exercise in the collection independently, without any effect on "points by default" as represented by the number here.
That being said... How many "default points" should you associate with an exercise upon creation?
As with difficulty, there is no straight forward and generally accepted way.
But as a guideline, we tend to give as many points by default as there are mathematical steps to do in the exercise.
Again, very vague... But the number should kind of represent the "work" required.
When you click an exercise into a collection, this number will be taken as points for the exercise, kind of "by default".
But once the exercise is on the collection, you can edit the number of points for the exercise in the collection independently, without any effect on "points by default" as represented by the number here.
That being said... How many "default points" should you associate with an exercise upon creation?
As with difficulty, there is no straight forward and generally accepted way.
But as a guideline, we tend to give as many points by default as there are mathematical steps to do in the exercise.
Again, very vague... But the number should kind of represent the "work" required.
About difficulty...
We associate a certain difficulty with each exercise.
When you click an exercise into a collection, this number will be taken as difficulty for the exercise, kind of "by default".
But once the exercise is on the collection, you can edit its difficulty in the collection independently, without any effect on the "difficulty by default" here.
Why we use chess pieces? Well... we like chess, we like playing around with \(\LaTeX\)-fonts, we wanted symbols that need less space than six stars in a table-column... But in your layouts, you are of course free to indicate the difficulty of the exercise the way you want.
That being said... How "difficult" is an exercise? It depends on many factors, like what was being taught etc.
In physics exercises, we try to follow this pattern:
Level 1 - One formula (one you would find in a reference book) is enough to solve the exercise. Example exercise
Level 2 - Two formulas are needed, it's possible to compute an "in-between" solution, i.e. no algebraic equation needed. Example exercise
Level 3 - "Chain-computations" like on level 2, but 3+ calculations. Still, no equations, i.e. you are not forced to solve it in an algebraic manner. Example exercise
Level 4 - Exercise needs to be solved by algebraic equations, not possible to calculate numerical "in-between" results. Example exercise
Level 5 -
Level 6 -
When you click an exercise into a collection, this number will be taken as difficulty for the exercise, kind of "by default".
But once the exercise is on the collection, you can edit its difficulty in the collection independently, without any effect on the "difficulty by default" here.
Why we use chess pieces? Well... we like chess, we like playing around with \(\LaTeX\)-fonts, we wanted symbols that need less space than six stars in a table-column... But in your layouts, you are of course free to indicate the difficulty of the exercise the way you want.
That being said... How "difficult" is an exercise? It depends on many factors, like what was being taught etc.
In physics exercises, we try to follow this pattern:
Level 1 - One formula (one you would find in a reference book) is enough to solve the exercise. Example exercise
Level 2 - Two formulas are needed, it's possible to compute an "in-between" solution, i.e. no algebraic equation needed. Example exercise
Level 3 - "Chain-computations" like on level 2, but 3+ calculations. Still, no equations, i.e. you are not forced to solve it in an algebraic manner. Example exercise
Level 4 - Exercise needs to be solved by algebraic equations, not possible to calculate numerical "in-between" results. Example exercise
Level 5 -
Level 6 -
Question
Solution
Short
Video
\(\LaTeX\)
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Don't forget to subscribe to our channel, like the videos and leave comments!
Exercise:
Ein Auto mO fährt auf gerader Strecke vO. Anschliess kuppelt der Fahrer aus und lässt das Auto einfach enquoteauslaufen. Der dabei wirke Luftwiderstand beträgt anfänglich FaO und nimmt dann entlang der Strecke gemäss Fskv_^texte^-frackms ab. Welche Geschwindigkeit hat das Auto nach sO Strecke noch?
Solution:
Am Anfang bei s gilt für die Kraft Fs kv_^texte^-frackms F_ F kv_^texte^-frackm kv_^ &mustbe Fa womit für die Konstante k k fracF_v_^ k folgt. Die vom Luftwiderstand am Auto verrichtete Arbeit beträgt demnach W _s_^s_ Fs dds _^s_ kv_^ texte^-frackmsdds left-kv_^ fracmk texte^-frackm s right_^s_ fracmv_^ lefttexte^-frackms_ right W. So viel Energie geht auf der Strecke verloren womit die neue kinetische Energie sscEkin' sscEkin-W fracmv_^ - W Ekb beträgt und die neue Geschwindigkeit v_ sqrtfrac sscEkin'm sqrtv_^left-texte^-frackms_right vb approx vbP vbkP ist. v_ sqrtv_^left-texte^-frackms_right vbP vbkP
Ein Auto mO fährt auf gerader Strecke vO. Anschliess kuppelt der Fahrer aus und lässt das Auto einfach enquoteauslaufen. Der dabei wirke Luftwiderstand beträgt anfänglich FaO und nimmt dann entlang der Strecke gemäss Fskv_^texte^-frackms ab. Welche Geschwindigkeit hat das Auto nach sO Strecke noch?
Solution:
Am Anfang bei s gilt für die Kraft Fs kv_^texte^-frackms F_ F kv_^texte^-frackm kv_^ &mustbe Fa womit für die Konstante k k fracF_v_^ k folgt. Die vom Luftwiderstand am Auto verrichtete Arbeit beträgt demnach W _s_^s_ Fs dds _^s_ kv_^ texte^-frackmsdds left-kv_^ fracmk texte^-frackm s right_^s_ fracmv_^ lefttexte^-frackms_ right W. So viel Energie geht auf der Strecke verloren womit die neue kinetische Energie sscEkin' sscEkin-W fracmv_^ - W Ekb beträgt und die neue Geschwindigkeit v_ sqrtfrac sscEkin'm sqrtv_^left-texte^-frackms_right vb approx vbP vbkP ist. v_ sqrtv_^left-texte^-frackms_right vbP vbkP
Meta Information
Exercise:
Ein Auto mO fährt auf gerader Strecke vO. Anschliess kuppelt der Fahrer aus und lässt das Auto einfach enquoteauslaufen. Der dabei wirke Luftwiderstand beträgt anfänglich FaO und nimmt dann entlang der Strecke gemäss Fskv_^texte^-frackms ab. Welche Geschwindigkeit hat das Auto nach sO Strecke noch?
Solution:
Am Anfang bei s gilt für die Kraft Fs kv_^texte^-frackms F_ F kv_^texte^-frackm kv_^ &mustbe Fa womit für die Konstante k k fracF_v_^ k folgt. Die vom Luftwiderstand am Auto verrichtete Arbeit beträgt demnach W _s_^s_ Fs dds _^s_ kv_^ texte^-frackmsdds left-kv_^ fracmk texte^-frackm s right_^s_ fracmv_^ lefttexte^-frackms_ right W. So viel Energie geht auf der Strecke verloren womit die neue kinetische Energie sscEkin' sscEkin-W fracmv_^ - W Ekb beträgt und die neue Geschwindigkeit v_ sqrtfrac sscEkin'm sqrtv_^left-texte^-frackms_right vb approx vbP vbkP ist. v_ sqrtv_^left-texte^-frackms_right vbP vbkP
Ein Auto mO fährt auf gerader Strecke vO. Anschliess kuppelt der Fahrer aus und lässt das Auto einfach enquoteauslaufen. Der dabei wirke Luftwiderstand beträgt anfänglich FaO und nimmt dann entlang der Strecke gemäss Fskv_^texte^-frackms ab. Welche Geschwindigkeit hat das Auto nach sO Strecke noch?
Solution:
Am Anfang bei s gilt für die Kraft Fs kv_^texte^-frackms F_ F kv_^texte^-frackm kv_^ &mustbe Fa womit für die Konstante k k fracF_v_^ k folgt. Die vom Luftwiderstand am Auto verrichtete Arbeit beträgt demnach W _s_^s_ Fs dds _^s_ kv_^ texte^-frackmsdds left-kv_^ fracmk texte^-frackm s right_^s_ fracmv_^ lefttexte^-frackms_ right W. So viel Energie geht auf der Strecke verloren womit die neue kinetische Energie sscEkin' sscEkin-W fracmv_^ - W Ekb beträgt und die neue Geschwindigkeit v_ sqrtfrac sscEkin'm sqrtv_^left-texte^-frackms_right vb approx vbP vbkP ist. v_ sqrtv_^left-texte^-frackms_right vbP vbkP
Contained in these collections:
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Arbeitsintegrale 3 by uz
Asked Quantity:
Arbeit \(W\)
in
Joule \(\rm J\)
Physical Quantity
Kraft mal Weg
\( W = \vec F \cdot \vec s\)
Unit
Joule (\(\rm J\))
Base?
SI?
Metric?
Coherent?
Imperial?
\(\rm1\,J\): Herzschlag
\(\rm1\,J\): Schokolade einen Meter anheben

