Exercise
https://texercises.com/exercise/ersatzwiderstand-15/
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The following quantities appear in the problem: elektrischer Widerstand \(R\) / Federkonstante \(D\) /
The following formulas must be used to solve the exercise: \(\frac{1}{R} = \frac{1}{R_1} + \frac{1}{R_2} \quad \) \(\frac{1}{D} = \frac{1}{D_1} + \frac{1}{D_2} \quad \) \(R = R_1 + R_2 \quad \)
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Exercise:
Berechne die Ersatzwiderstände der folgen beiden Schaltungen. Für beide Schaltungen gilt: R_ohm R_ohm R_ohm R_ohm R_ohm center circuitikz scopexshiftcm yshiftcm draw to european resistor l^R_ ; draw to european resistor l^R_ ; draw - to european resistor l^R_ -; draw - to european resistor l^R_ -; draw -. to european resistor l^R_ -.; draw .--; draw ---; draw ---; draw ---.; draw --.; scope scopexshiftcm yshift-cm draw to european resistor l^R_ ; draw to european resistor l^R_ ; draw to european resistor l^R_ ; draw --; draw to european resistor l^R_ ; draw to european resistor l^R_ ; draw --; scope circuitikz center

Solution:
R_ .ohm R_ .ohm
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\(\LaTeX\)-Code
Exercise:
Berechne die Ersatzwiderstände der folgen beiden Schaltungen. Für beide Schaltungen gilt: R_ohm R_ohm R_ohm R_ohm R_ohm center circuitikz scopexshiftcm yshiftcm draw to european resistor l^R_ ; draw to european resistor l^R_ ; draw - to european resistor l^R_ -; draw - to european resistor l^R_ -; draw -. to european resistor l^R_ -.; draw .--; draw ---; draw ---; draw ---.; draw --.; scope scopexshiftcm yshift-cm draw to european resistor l^R_ ; draw to european resistor l^R_ ; draw to european resistor l^R_ ; draw --; draw to european resistor l^R_ ; draw to european resistor l^R_ ; draw --; scope circuitikz center

Solution:
R_ .ohm R_ .ohm
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Attributes & Decorations
Branches
Direct Current
Tags
elektrizität, elektrizitätslehre, ersatzwiderstand, gleichstrom, gleichstromlehre, parallelschaltung, physik, serieschaltung, widerstand
Content image
Difficulty
(1, default)
Points
2 (default)
Language
GER (Deutsch)
Type
Calculative / Quantity
Creator uz
Decoration
File
Link