Gauss's Law for Gravitation
About points...
We associate a certain number of points with each exercise.
When you click an exercise into a collection, this number will be taken as points for the exercise, kind of "by default".
But once the exercise is on the collection, you can edit the number of points for the exercise in the collection independently, without any effect on "points by default" as represented by the number here.
That being said... How many "default points" should you associate with an exercise upon creation?
As with difficulty, there is no straight forward and generally accepted way.
But as a guideline, we tend to give as many points by default as there are mathematical steps to do in the exercise.
Again, very vague... But the number should kind of represent the "work" required.
When you click an exercise into a collection, this number will be taken as points for the exercise, kind of "by default".
But once the exercise is on the collection, you can edit the number of points for the exercise in the collection independently, without any effect on "points by default" as represented by the number here.
That being said... How many "default points" should you associate with an exercise upon creation?
As with difficulty, there is no straight forward and generally accepted way.
But as a guideline, we tend to give as many points by default as there are mathematical steps to do in the exercise.
Again, very vague... But the number should kind of represent the "work" required.
About difficulty...
We associate a certain difficulty with each exercise.
When you click an exercise into a collection, this number will be taken as difficulty for the exercise, kind of "by default".
But once the exercise is on the collection, you can edit its difficulty in the collection independently, without any effect on the "difficulty by default" here.
Why we use chess pieces? Well... we like chess, we like playing around with \(\LaTeX\)-fonts, we wanted symbols that need less space than six stars in a table-column... But in your layouts, you are of course free to indicate the difficulty of the exercise the way you want.
That being said... How "difficult" is an exercise? It depends on many factors, like what was being taught etc.
In physics exercises, we try to follow this pattern:
Level 1 - One formula (one you would find in a reference book) is enough to solve the exercise. Example exercise
Level 2 - Two formulas are needed, it's possible to compute an "in-between" solution, i.e. no algebraic equation needed. Example exercise
Level 3 - "Chain-computations" like on level 2, but 3+ calculations. Still, no equations, i.e. you are not forced to solve it in an algebraic manner. Example exercise
Level 4 - Exercise needs to be solved by algebraic equations, not possible to calculate numerical "in-between" results. Example exercise
Level 5 -
Level 6 -
When you click an exercise into a collection, this number will be taken as difficulty for the exercise, kind of "by default".
But once the exercise is on the collection, you can edit its difficulty in the collection independently, without any effect on the "difficulty by default" here.
Why we use chess pieces? Well... we like chess, we like playing around with \(\LaTeX\)-fonts, we wanted symbols that need less space than six stars in a table-column... But in your layouts, you are of course free to indicate the difficulty of the exercise the way you want.
That being said... How "difficult" is an exercise? It depends on many factors, like what was being taught etc.
In physics exercises, we try to follow this pattern:
Level 1 - One formula (one you would find in a reference book) is enough to solve the exercise. Example exercise
Level 2 - Two formulas are needed, it's possible to compute an "in-between" solution, i.e. no algebraic equation needed. Example exercise
Level 3 - "Chain-computations" like on level 2, but 3+ calculations. Still, no equations, i.e. you are not forced to solve it in an algebraic manner. Example exercise
Level 4 - Exercise needs to be solved by algebraic equations, not possible to calculate numerical "in-between" results. Example exercise
Level 5 -
Level 6 -
Question
Solution
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\(\LaTeX\)
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Exercise:
Because of the formal analogy between the gravitational and the electrostatic force Gauss's law can also be used for gravitational fields. We know that the gravitational field outside a spherical mass e.g. a star or a planet is given by gr G fracMr^ where G is the gravitational constant M the object's total mass and r the distance of a po from the object's centre of mass. abcliste abc Show that Gauss's law for gravitational fields can be written as Phi_G pi G sscMenclosed where Phi_G is the flux of the gravitational field through a closed surface and sscMenclosed the mass contained in that surface. abc Derive an expression for the gravitational field on the inside of a sphere with uniform mass distribution. Graph the gravitational field vs. the distance from a sphere with radius R for r R. abcliste
Solution:
abcliste abc For a spherical mass distribution we choose a concentric spherical shell as the Gaussian surface. The gravitational flux through this surface is Phi_G gr Ar G fracMr^ pi r^ pi G M quad square This result is true for any mass distribution and any closed surface as it is the case for the electric field. abc In order to find the gravitational field on the inside of a spherical mass we choose a concentric spherical shell with radius rR as the Gaussian surface. For a uniform mass distribution i.e. a constant density the enclosed mass we find fracsscMenclosedM fracsscVenclosedsscVtot fracr^R^ left fracrR right^ It follows for the gravitational flux Phi_G gr Ar gr pi r^ pi G sscMenclosed pi G M left fracrR right^ Solving for gr yields gr fracG MR^ r On the outside of the sphere we have the standard expression for the gravitational field gr fracG Mr^ On the surface of the sphere the two expresions yield the same value. The figure below displays the gravitational field for rR. The field on the surface is g_gR. center includegraphicswidthtextwidth#image_path:gauss-gravitation-# center abcliste
Because of the formal analogy between the gravitational and the electrostatic force Gauss's law can also be used for gravitational fields. We know that the gravitational field outside a spherical mass e.g. a star or a planet is given by gr G fracMr^ where G is the gravitational constant M the object's total mass and r the distance of a po from the object's centre of mass. abcliste abc Show that Gauss's law for gravitational fields can be written as Phi_G pi G sscMenclosed where Phi_G is the flux of the gravitational field through a closed surface and sscMenclosed the mass contained in that surface. abc Derive an expression for the gravitational field on the inside of a sphere with uniform mass distribution. Graph the gravitational field vs. the distance from a sphere with radius R for r R. abcliste
Solution:
abcliste abc For a spherical mass distribution we choose a concentric spherical shell as the Gaussian surface. The gravitational flux through this surface is Phi_G gr Ar G fracMr^ pi r^ pi G M quad square This result is true for any mass distribution and any closed surface as it is the case for the electric field. abc In order to find the gravitational field on the inside of a spherical mass we choose a concentric spherical shell with radius rR as the Gaussian surface. For a uniform mass distribution i.e. a constant density the enclosed mass we find fracsscMenclosedM fracsscVenclosedsscVtot fracr^R^ left fracrR right^ It follows for the gravitational flux Phi_G gr Ar gr pi r^ pi G sscMenclosed pi G M left fracrR right^ Solving for gr yields gr fracG MR^ r On the outside of the sphere we have the standard expression for the gravitational field gr fracG Mr^ On the surface of the sphere the two expresions yield the same value. The figure below displays the gravitational field for rR. The field on the surface is g_gR. center includegraphicswidthtextwidth#image_path:gauss-gravitation-# center abcliste
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Exercise:
Because of the formal analogy between the gravitational and the electrostatic force Gauss's law can also be used for gravitational fields. We know that the gravitational field outside a spherical mass e.g. a star or a planet is given by gr G fracMr^ where G is the gravitational constant M the object's total mass and r the distance of a po from the object's centre of mass. abcliste abc Show that Gauss's law for gravitational fields can be written as Phi_G pi G sscMenclosed where Phi_G is the flux of the gravitational field through a closed surface and sscMenclosed the mass contained in that surface. abc Derive an expression for the gravitational field on the inside of a sphere with uniform mass distribution. Graph the gravitational field vs. the distance from a sphere with radius R for r R. abcliste
Solution:
abcliste abc For a spherical mass distribution we choose a concentric spherical shell as the Gaussian surface. The gravitational flux through this surface is Phi_G gr Ar G fracMr^ pi r^ pi G M quad square This result is true for any mass distribution and any closed surface as it is the case for the electric field. abc In order to find the gravitational field on the inside of a spherical mass we choose a concentric spherical shell with radius rR as the Gaussian surface. For a uniform mass distribution i.e. a constant density the enclosed mass we find fracsscMenclosedM fracsscVenclosedsscVtot fracr^R^ left fracrR right^ It follows for the gravitational flux Phi_G gr Ar gr pi r^ pi G sscMenclosed pi G M left fracrR right^ Solving for gr yields gr fracG MR^ r On the outside of the sphere we have the standard expression for the gravitational field gr fracG Mr^ On the surface of the sphere the two expresions yield the same value. The figure below displays the gravitational field for rR. The field on the surface is g_gR. center includegraphicswidthtextwidth#image_path:gauss-gravitation-# center abcliste
Because of the formal analogy between the gravitational and the electrostatic force Gauss's law can also be used for gravitational fields. We know that the gravitational field outside a spherical mass e.g. a star or a planet is given by gr G fracMr^ where G is the gravitational constant M the object's total mass and r the distance of a po from the object's centre of mass. abcliste abc Show that Gauss's law for gravitational fields can be written as Phi_G pi G sscMenclosed where Phi_G is the flux of the gravitational field through a closed surface and sscMenclosed the mass contained in that surface. abc Derive an expression for the gravitational field on the inside of a sphere with uniform mass distribution. Graph the gravitational field vs. the distance from a sphere with radius R for r R. abcliste
Solution:
abcliste abc For a spherical mass distribution we choose a concentric spherical shell as the Gaussian surface. The gravitational flux through this surface is Phi_G gr Ar G fracMr^ pi r^ pi G M quad square This result is true for any mass distribution and any closed surface as it is the case for the electric field. abc In order to find the gravitational field on the inside of a spherical mass we choose a concentric spherical shell with radius rR as the Gaussian surface. For a uniform mass distribution i.e. a constant density the enclosed mass we find fracsscMenclosedM fracsscVenclosedsscVtot fracr^R^ left fracrR right^ It follows for the gravitational flux Phi_G gr Ar gr pi r^ pi G sscMenclosed pi G M left fracrR right^ Solving for gr yields gr fracG MR^ r On the outside of the sphere we have the standard expression for the gravitational field gr fracG Mr^ On the surface of the sphere the two expresions yield the same value. The figure below displays the gravitational field for rR. The field on the surface is g_gR. center includegraphicswidthtextwidth#image_path:gauss-gravitation-# center abcliste
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