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Todesspirale

About points...

We associate a certain number of points with each exercise.
When you click an exercise into a collection, this number will be taken as points for the exercise, kind of "by default".
But once the exercise is on the collection, you can edit the number of points for the exercise in the collection independently, without any effect on "points by default" as represented by the number here.

That being said... How many "default points" should you associate with an exercise upon creation?
As with difficulty, there is no straight forward and generally accepted way.
But as a guideline, we tend to give as many points by default as there are mathematical steps to do in the exercise.
Again, very vague... But the number should kind of represent the "work" required.

About difficulty...

We associate a certain difficulty with each exercise.
When you click an exercise into a collection, this number will be taken as difficulty for the exercise, kind of "by default".
But once the exercise is on the collection, you can edit its difficulty in the collection independently, without any effect on the "difficulty by default" here.
Why we use chess pieces? Well... we like chess, we like playing around with \(\LaTeX\)-fonts, we wanted symbols that need less space than six stars in a table-column... But in your layouts, you are of course free to indicate the difficulty of the exercise the way you want.

That being said... How "difficult" is an exercise? It depends on many factors, like what was being taught etc.
In physics exercises, we try to follow this pattern:

Level 1 - One formula (one you would find in a reference book) is enough to solve the exercise. Example exercise

Level 2 - Two formulas are needed, it's possible to compute an "in-between" solution, i.e. no algebraic equation needed. Example exercise

Level 3 - "Chain-computations" like on level 2, but 3+ calculations. Still, no equations, i.e. you are not forced to solve it in an algebraic manner. Example exercise

Level 4 - Exercise needs to be solved by algebraic equations, not possible to calculate numerical "in-between" results. Example exercise

Level 5 -
Level 6 -

Exercise

https://texercises.com/exercise/todesspirale-1/

Question

Solution

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The following quantities appear in the problem: Masse \(m\) / Kraft \(F\) / Energie \(E\) / Geschwindigkeit \(v\) / Ortsfaktor \(g\) / Höhe \(h\) / Radius \(r\) /

The following formulas must be used to solve the exercise: \(F = mg \quad \) \(E_{\rm \scriptscriptstyle kin} = \dfrac12 mv^2 \quad \) \(E_{\rm \scriptscriptstyle pot} = mgh \quad \) \(F = m\dfrac{v^2}{r} \quad \)

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Exercise:
Ein Wagen werde auf eine Höhe von pqm gebracht bevor er eine glqq Todesspiralegrqq d.h. einen vollen Looping zu durchfahren hat. Im höchsten Punkt der Spirale drücken die Räder des Wagens pqkg mit einer Kraft von pqN auf die Schienen. Berechne den Radius dieser Todesspirale.

Solution:
Es gilt der Energieerhaltungssatz: E_texttiny vor E_texttiny nach mgh frac mfracv^r + mg r Nun verwet man dass der Wagen im höchsten Punkt zwar von der Erde mit FGmgpqN angezogen wird aber trotzdem mit pqN auf die Schienen drückt. Das heisst die Zentripetalkraft welche nötig ist um den Wagen auf der Kreisbahn zu halten beträgt FZ FG + pqN pqN. Benutzt man dass wegen FZ mfracv^r quad Rightarrow mv^FZ r ist so folgt: mgh frac FZ r + mg r r fracmghfracFZ + mg pq.m

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Attributes & Decorations

Branches	Laws of Thermodynamics, Work, Energy, Power
Tags	achterbahn, energie, energieerhaltung, energieerhaltungssatz, freizeitpark, gewichtskraft, kinetische energie, looping, mechanik, physik, potentielle energie, todesspirale, zentrifugalkraft, zentripetalkraft
Content image
Difficulty	(3, default)
Points	3 (default)
Language	(Deutsch)
Type	Calculative / Quantity
Creator	uz
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