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A houses major source of heat loss is through the windows. Consider a $\SI{3.2}{mm}$ thick glass window of $\SI{2.0}{m}\times\SI{1.5}{m}$ of area, if the temperatures at the inner and outer surfaces are \SI{15}{\degreeCelsius} and \SI{14}{\degreeCelsius} respectively. Calculate the rate of heat flow through this window, under the assumption that its with thermal conductivity is \SI{0.84}{\watt\per\kelvin\per\meter}.
$\SI{790}{W}$
The rate of heat flow is: \begin{align} \Phi &= \frac{\Delta Q}{\Delta t}\\ &= \lambda \cdot \frac{\Delta T}{\Delta x} \cdot A\\ &= \SI{0.84}{\watt\per\kelvin\per\meter} \cdot \frac{\SI{1}{K}}{\SI{3.2e3}{m}} \cdot \SI{3}{\meter\squared}\\ &= \SI{787.5}{W} \end{align}
12:44, 12. June 2017  text  Urs Zellweger (urs)  Current Version 
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