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Calculate the velocity of a $\SI{5.00}{kg}$ rifle that shoots a $\SI{20.0}{g}$ bullet at a speed of $\SI{620}{\meter\per\second}$.
The conservation of momentum gives (since the momentum at the beginning is zero): \begin{align} 0 &\mustbe p_b + p_r\\ &= m_b\cdot v_b + m_r\cdot v_r\\ v_r &= \frac{m_b\cdot v_b}{m_r}\\ &= \frac{\SI{0.02}{kg} \cdot \SI{620}{\meter\per\second}}{\SI{5}{kg}}\\ &= \SI{2.48}{\meter\per\second} \end{align} The minus sign means, that the rifle recoils in the opposite direction of the bullet.
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