Exercise
https://texercises.com/exercise/addition-of-linear-subspaces/
Question
Solution
Short
Video
\(\LaTeX\)
No explanation / solution video to this exercise has yet been created.

Visit our YouTube-Channel to see solutions to other exercises.
Don't forget to subscribe to our channel, like the videos and leave comments!
Exercise:
Let mathcalUWsubset V be two finite dimensional linear subspaces of a vector space V. The following are equivalent: abcliste abc dimmathcalU+W dim mathcalU+dim mathcalW abc dimmathcalUcapmathcalW abc mathcalUcapmathcalW abc Every vin mathcalU+mathcalW can be written in a unique way as vu+w with uin mathcalU winmathcalW. abc If u+w where uinmathcalUwinmathcalW then uw. abcliste

Solution:
Proof of aiff b follows from a previous Proposition Proof of biff c because there is only one linear subspace of dim the space . Proof of cLongrightarrow d By definition every vinmathcalU+W can be written as vu+w. To see the uniqueness suppose that vu+wu'+w' where uu'in mathcalU ww'in mathcalW Longrightarrow u-u'w-w'in mathcalUcapmathcalW Longrightarrow uu' and w'w. Proof of dLongrightarrow e + so if u+w and d holds then uw. Proof of eLongrightarrow c Let vin mathcalUcapmathcalW. We have v+-v. If e holds we have v.
Report An Error
You are on texercises.com.
reCaptcha will only work on our main-domain \(\TeX\)ercises.com!
Meta Information
\(\LaTeX\)-Code
Exercise:
Let mathcalUWsubset V be two finite dimensional linear subspaces of a vector space V. The following are equivalent: abcliste abc dimmathcalU+W dim mathcalU+dim mathcalW abc dimmathcalUcapmathcalW abc mathcalUcapmathcalW abc Every vin mathcalU+mathcalW can be written in a unique way as vu+w with uin mathcalU winmathcalW. abc If u+w where uinmathcalUwinmathcalW then uw. abcliste

Solution:
Proof of aiff b follows from a previous Proposition Proof of biff c because there is only one linear subspace of dim the space . Proof of cLongrightarrow d By definition every vinmathcalU+W can be written as vu+w. To see the uniqueness suppose that vu+wu'+w' where uu'in mathcalU ww'in mathcalW Longrightarrow u-u'w-w'in mathcalUcapmathcalW Longrightarrow uu' and w'w. Proof of dLongrightarrow e + so if u+w and d holds then uw. Proof of eLongrightarrow c Let vin mathcalUcapmathcalW. We have v+-v. If e holds we have v.
Contained in these collections

Similar exercises (47)
Title Creator Matched on
Linear subspaces and complements rk tags
Bases and identity rk tags
Linear subspaces rk tags
Constructing new vector spaces out of old ones rk tags
Examples of linear subspaces rk tags
more (42 more)
Attributes & Decorations
Tags
eth, hs22, linear subspace, lineare algebra, proof, vector space
Difficulty
(3, default)
Points
0 (default)
Language
ENG (English)
Type
Proof
Decoration
Content image