Auftreffwinkel von horizontal abgeschossenem Körper
About points...
We associate a certain number of points with each exercise.
When you click an exercise into a collection, this number will be taken as points for the exercise, kind of "by default".
But once the exercise is on the collection, you can edit the number of points for the exercise in the collection independently, without any effect on "points by default" as represented by the number here.
That being said... How many "default points" should you associate with an exercise upon creation?
As with difficulty, there is no straight forward and generally accepted way.
But as a guideline, we tend to give as many points by default as there are mathematical steps to do in the exercise.
Again, very vague... But the number should kind of represent the "work" required.
When you click an exercise into a collection, this number will be taken as points for the exercise, kind of "by default".
But once the exercise is on the collection, you can edit the number of points for the exercise in the collection independently, without any effect on "points by default" as represented by the number here.
That being said... How many "default points" should you associate with an exercise upon creation?
As with difficulty, there is no straight forward and generally accepted way.
But as a guideline, we tend to give as many points by default as there are mathematical steps to do in the exercise.
Again, very vague... But the number should kind of represent the "work" required.
About difficulty...
We associate a certain difficulty with each exercise.
When you click an exercise into a collection, this number will be taken as difficulty for the exercise, kind of "by default".
But once the exercise is on the collection, you can edit its difficulty in the collection independently, without any effect on the "difficulty by default" here.
Why we use chess pieces? Well... we like chess, we like playing around with \(\LaTeX\)-fonts, we wanted symbols that need less space than six stars in a table-column... But in your layouts, you are of course free to indicate the difficulty of the exercise the way you want.
That being said... How "difficult" is an exercise? It depends on many factors, like what was being taught etc.
In physics exercises, we try to follow this pattern:
Level 1 - One formula (one you would find in a reference book) is enough to solve the exercise. Example exercise
Level 2 - Two formulas are needed, it's possible to compute an "in-between" solution, i.e. no algebraic equation needed. Example exercise
Level 3 - "Chain-computations" like on level 2, but 3+ calculations. Still, no equations, i.e. you are not forced to solve it in an algebraic manner. Example exercise
Level 4 - Exercise needs to be solved by algebraic equations, not possible to calculate numerical "in-between" results. Example exercise
Level 5 -
Level 6 -
When you click an exercise into a collection, this number will be taken as difficulty for the exercise, kind of "by default".
But once the exercise is on the collection, you can edit its difficulty in the collection independently, without any effect on the "difficulty by default" here.
Why we use chess pieces? Well... we like chess, we like playing around with \(\LaTeX\)-fonts, we wanted symbols that need less space than six stars in a table-column... But in your layouts, you are of course free to indicate the difficulty of the exercise the way you want.
That being said... How "difficult" is an exercise? It depends on many factors, like what was being taught etc.
In physics exercises, we try to follow this pattern:
Level 1 - One formula (one you would find in a reference book) is enough to solve the exercise. Example exercise
Level 2 - Two formulas are needed, it's possible to compute an "in-between" solution, i.e. no algebraic equation needed. Example exercise
Level 3 - "Chain-computations" like on level 2, but 3+ calculations. Still, no equations, i.e. you are not forced to solve it in an algebraic manner. Example exercise
Level 4 - Exercise needs to be solved by algebraic equations, not possible to calculate numerical "in-between" results. Example exercise
Level 5 -
Level 6 -
Question
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Exercise:
Ein Körper werde horizontal von einer Anhöhe abgeschossen und treffe nach sxO horizontaler Distanz etwas weiter unten mit vyO vertikaler Geschwindigkeit auf einen ebenen Boden. Unter welchem Winkel zur Horizontalen schlägt der Körper dort auf?
Solution:
Geg s_x sxO sx v_y vyO vy GesAuftreff-Winkelbetasirad Der Körper ist insgesamt t fracv_yg fracvyg t unterwegs womit er v_x fracs_xt fracs_xfracv_yg fracgs_xv_y fracsxt vx horizontale Geschwindigkeit haben muss. Der Winkel des Auftreffens beträgt also beta arctanfracv_yv_x arctanfracv_yfracgs_xv_y arctanfracv_y^gs_x arctanfracvyvx alpr approx alprS alpd approx alpdP gegenüber der Horizontalen. beta arctanfracv_y^gs_x alprS alpdP
Ein Körper werde horizontal von einer Anhöhe abgeschossen und treffe nach sxO horizontaler Distanz etwas weiter unten mit vyO vertikaler Geschwindigkeit auf einen ebenen Boden. Unter welchem Winkel zur Horizontalen schlägt der Körper dort auf?
Solution:
Geg s_x sxO sx v_y vyO vy GesAuftreff-Winkelbetasirad Der Körper ist insgesamt t fracv_yg fracvyg t unterwegs womit er v_x fracs_xt fracs_xfracv_yg fracgs_xv_y fracsxt vx horizontale Geschwindigkeit haben muss. Der Winkel des Auftreffens beträgt also beta arctanfracv_yv_x arctanfracv_yfracgs_xv_y arctanfracv_y^gs_x arctanfracvyvx alpr approx alprS alpd approx alpdP gegenüber der Horizontalen. beta arctanfracv_y^gs_x alprS alpdP
Meta Information
Exercise:
Ein Körper werde horizontal von einer Anhöhe abgeschossen und treffe nach sxO horizontaler Distanz etwas weiter unten mit vyO vertikaler Geschwindigkeit auf einen ebenen Boden. Unter welchem Winkel zur Horizontalen schlägt der Körper dort auf?
Solution:
Geg s_x sxO sx v_y vyO vy GesAuftreff-Winkelbetasirad Der Körper ist insgesamt t fracv_yg fracvyg t unterwegs womit er v_x fracs_xt fracs_xfracv_yg fracgs_xv_y fracsxt vx horizontale Geschwindigkeit haben muss. Der Winkel des Auftreffens beträgt also beta arctanfracv_yv_x arctanfracv_yfracgs_xv_y arctanfracv_y^gs_x arctanfracvyvx alpr approx alprS alpd approx alpdP gegenüber der Horizontalen. beta arctanfracv_y^gs_x alprS alpdP
Ein Körper werde horizontal von einer Anhöhe abgeschossen und treffe nach sxO horizontaler Distanz etwas weiter unten mit vyO vertikaler Geschwindigkeit auf einen ebenen Boden. Unter welchem Winkel zur Horizontalen schlägt der Körper dort auf?
Solution:
Geg s_x sxO sx v_y vyO vy GesAuftreff-Winkelbetasirad Der Körper ist insgesamt t fracv_yg fracvyg t unterwegs womit er v_x fracs_xt fracs_xfracv_yg fracgs_xv_y fracsxt vx horizontale Geschwindigkeit haben muss. Der Winkel des Auftreffens beträgt also beta arctanfracv_yv_x arctanfracv_yfracgs_xv_y arctanfracv_y^gs_x arctanfracvyvx alpr approx alprS alpd approx alpdP gegenüber der Horizontalen. beta arctanfracv_y^gs_x alprS alpdP
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Horizontaler Wurf [sx vy beta] by TeXercises
Asked Quantity:
Winkel \(\theta\)
in
Radian \(\rm rad\)
Physical Quantity
Unit