Exercise
https://texercises.com/exercise/betonrohre/
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The following quantities appear in the problem: Masse mm / Volumen VV / Höhe hh / Radius rr / Dichte ϱ\varrho /
The following formulas must be used to solve the exercise: ϱ=mV\varrho = \dfrac{m}{V} \quad V=πh(R2r2)V = \pi h (R^2-r^2) \quad
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Exercise:
Eine zylindrische Betonröhre hat mittlere Dichte .eeesikg/m^. Welchen Volumenanteil hat der Hohlraum in der Röhre?

Solution:
% . August Lie. * &barrho fracm_BV fracrho_BV-V_HV rho_B-rho_B fracV_HV Rightarrow qquad textLuftmasse im Hohlraum ist vernachlässigbar &fracV_HV fracrho_B-barrhorho_B - fracbarrhorho_B - frac.eeesikg/m^.eeesikg/m^ uuline. *
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Exercise:
Eine zylindrische Betonröhre hat mittlere Dichte .eeesikg/m^. Welchen Volumenanteil hat der Hohlraum in der Röhre?

Solution:
% . August Lie. * &barrho fracm_BV fracrho_BV-V_HV rho_B-rho_B fracV_HV Rightarrow qquad textLuftmasse im Hohlraum ist vernachlässigbar &fracV_HV fracrho_B-barrhorho_B - fracbarrhorho_B - frac.eeesikg/m^.eeesikg/m^ uuline. *
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RohrDichtHohlV
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Language
GER (Deutsch)
Type
Calculative / Quantity
Creator Lie
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