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Exercise:
Estimate the rate at which heat can be conducted from the erior of the body to the surface. Ase that the thickness of human tissue .wattperkelvinpermeter is .cm that the skin is at degreeCelsius and the erior at degreeCelsius and that the surface area is .metersquared. Compare this to the measured value of about W that must be dissipated by a person working lightly.

Solution:
The cooling rate by conductivity is: Phi fracDelta QDelta t -lambda fracT_-T_d A -.W Compared to W this clearly shows the necessity of convective cooling by the blood.
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Exercise:
Estimate the rate at which heat can be conducted from the erior of the body to the surface. Ase that the thickness of human tissue .wattperkelvinpermeter is .cm that the skin is at degreeCelsius and the erior at degreeCelsius and that the surface area is .metersquared. Compare this to the measured value of about W that must be dissipated by a person working lightly.

Solution:
The cooling rate by conductivity is: Phi fracDelta QDelta t -lambda fracT_-T_d A -.W Compared to W this clearly shows the necessity of convective cooling by the blood.
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Attributes & Decorations
Branches
Temperatur & Heat, Work, Energy, Power
Tags
biology, body, conduction, convection, cooling, heat, human, loss, physics, power, thermodynamics, tissue, transfer
Content image
Difficulty
(1, default)
Points
3 (default)
Language
ENG (English)
Type
Calculative / Quantity
Creator uz
Decoration
File
Link