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Exercise:
In a cathode ray tube the electrons are accelerated from the cathode C to a first anode A_ and then to a second anode A_. The potentials at the cathode and the second anode are VAO and VCO respectively. What is the potential at the first anode if the electrons arrive there with half their final speed?

Solution:
The potential differences between the cathode and the two anodes are proportional to square of the respective speed: Delta V_CA_ &varpropto v_^ Delta V_CA_ &varpropto v_^ The ratio of the potentential differences is fracDelta V_CA_Delta V_CA_ fracv_^v_^ frac For the potential difference between the cathode and the first anode we thus find Delta V_CA_ fracDelta V_CA_ DVF fracVC-VA DVP Since Delta V_CA_ V_C-V_A_ the potential at the first anode is V_A_ VBF VC - DV resultVBP
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Exercise:
In a cathode ray tube the electrons are accelerated from the cathode C to a first anode A_ and then to a second anode A_. The potentials at the cathode and the second anode are VAO and VCO respectively. What is the potential at the first anode if the electrons arrive there with half their final speed?

Solution:
The potential differences between the cathode and the two anodes are proportional to square of the respective speed: Delta V_CA_ &varpropto v_^ Delta V_CA_ &varpropto v_^ The ratio of the potentential differences is fracDelta V_CA_Delta V_CA_ fracv_^v_^ frac For the potential difference between the cathode and the first anode we thus find Delta V_CA_ fracDelta V_CA_ DVF fracVC-VA DVP Since Delta V_CA_ V_C-V_A_ the potential at the first anode is V_A_ VBF VC - DV resultVBP
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Electrostatics
Tags
acceleration voltage, cathode ray tube, crt, electric potential
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(1, default)
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Language
ENG (English)
Type
Calculative / Quantity
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