Cathode Ray Tube
About points...
We associate a certain number of points with each exercise.
When you click an exercise into a collection, this number will be taken as points for the exercise, kind of "by default".
But once the exercise is on the collection, you can edit the number of points for the exercise in the collection independently, without any effect on "points by default" as represented by the number here.
That being said... How many "default points" should you associate with an exercise upon creation?
As with difficulty, there is no straight forward and generally accepted way.
But as a guideline, we tend to give as many points by default as there are mathematical steps to do in the exercise.
Again, very vague... But the number should kind of represent the "work" required.
When you click an exercise into a collection, this number will be taken as points for the exercise, kind of "by default".
But once the exercise is on the collection, you can edit the number of points for the exercise in the collection independently, without any effect on "points by default" as represented by the number here.
That being said... How many "default points" should you associate with an exercise upon creation?
As with difficulty, there is no straight forward and generally accepted way.
But as a guideline, we tend to give as many points by default as there are mathematical steps to do in the exercise.
Again, very vague... But the number should kind of represent the "work" required.
About difficulty...
We associate a certain difficulty with each exercise.
When you click an exercise into a collection, this number will be taken as difficulty for the exercise, kind of "by default".
But once the exercise is on the collection, you can edit its difficulty in the collection independently, without any effect on the "difficulty by default" here.
Why we use chess pieces? Well... we like chess, we like playing around with \(\LaTeX\)-fonts, we wanted symbols that need less space than six stars in a table-column... But in your layouts, you are of course free to indicate the difficulty of the exercise the way you want.
That being said... How "difficult" is an exercise? It depends on many factors, like what was being taught etc.
In physics exercises, we try to follow this pattern:
Level 1 - One formula (one you would find in a reference book) is enough to solve the exercise. Example exercise
Level 2 - Two formulas are needed, it's possible to compute an "in-between" solution, i.e. no algebraic equation needed. Example exercise
Level 3 - "Chain-computations" like on level 2, but 3+ calculations. Still, no equations, i.e. you are not forced to solve it in an algebraic manner. Example exercise
Level 4 - Exercise needs to be solved by algebraic equations, not possible to calculate numerical "in-between" results. Example exercise
Level 5 -
Level 6 -
When you click an exercise into a collection, this number will be taken as difficulty for the exercise, kind of "by default".
But once the exercise is on the collection, you can edit its difficulty in the collection independently, without any effect on the "difficulty by default" here.
Why we use chess pieces? Well... we like chess, we like playing around with \(\LaTeX\)-fonts, we wanted symbols that need less space than six stars in a table-column... But in your layouts, you are of course free to indicate the difficulty of the exercise the way you want.
That being said... How "difficult" is an exercise? It depends on many factors, like what was being taught etc.
In physics exercises, we try to follow this pattern:
Level 1 - One formula (one you would find in a reference book) is enough to solve the exercise. Example exercise
Level 2 - Two formulas are needed, it's possible to compute an "in-between" solution, i.e. no algebraic equation needed. Example exercise
Level 3 - "Chain-computations" like on level 2, but 3+ calculations. Still, no equations, i.e. you are not forced to solve it in an algebraic manner. Example exercise
Level 4 - Exercise needs to be solved by algebraic equations, not possible to calculate numerical "in-between" results. Example exercise
Level 5 -
Level 6 -
Question
Solution
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Exercise:
In a cathode ray tube the electrons are accelerated from the cathode C to a first anode A_ and then to a second anode A_. The potentials at the cathode and the second anode are VAO and VCO respectively. What is the potential at the first anode if the electrons arrive there with half their final speed?
Solution:
The potential differences between the cathode and the two anodes are proportional to square of the respective speed: Delta V_CA_ &varpropto v_^ Delta V_CA_ &varpropto v_^ The ratio of the potentential differences is fracDelta V_CA_Delta V_CA_ fracv_^v_^ frac For the potential difference between the cathode and the first anode we thus find Delta V_CA_ fracDelta V_CA_ DVF fracVC-VA DVP Since Delta V_CA_ V_C-V_A_ the potential at the first anode is V_A_ VBF VC - DV resultVBP
In a cathode ray tube the electrons are accelerated from the cathode C to a first anode A_ and then to a second anode A_. The potentials at the cathode and the second anode are VAO and VCO respectively. What is the potential at the first anode if the electrons arrive there with half their final speed?
Solution:
The potential differences between the cathode and the two anodes are proportional to square of the respective speed: Delta V_CA_ &varpropto v_^ Delta V_CA_ &varpropto v_^ The ratio of the potentential differences is fracDelta V_CA_Delta V_CA_ fracv_^v_^ frac For the potential difference between the cathode and the first anode we thus find Delta V_CA_ fracDelta V_CA_ DVF fracVC-VA DVP Since Delta V_CA_ V_C-V_A_ the potential at the first anode is V_A_ VBF VC - DV resultVBP
Meta Information
Exercise:
In a cathode ray tube the electrons are accelerated from the cathode C to a first anode A_ and then to a second anode A_. The potentials at the cathode and the second anode are VAO and VCO respectively. What is the potential at the first anode if the electrons arrive there with half their final speed?
Solution:
The potential differences between the cathode and the two anodes are proportional to square of the respective speed: Delta V_CA_ &varpropto v_^ Delta V_CA_ &varpropto v_^ The ratio of the potentential differences is fracDelta V_CA_Delta V_CA_ fracv_^v_^ frac For the potential difference between the cathode and the first anode we thus find Delta V_CA_ fracDelta V_CA_ DVF fracVC-VA DVP Since Delta V_CA_ V_C-V_A_ the potential at the first anode is V_A_ VBF VC - DV resultVBP
In a cathode ray tube the electrons are accelerated from the cathode C to a first anode A_ and then to a second anode A_. The potentials at the cathode and the second anode are VAO and VCO respectively. What is the potential at the first anode if the electrons arrive there with half their final speed?
Solution:
The potential differences between the cathode and the two anodes are proportional to square of the respective speed: Delta V_CA_ &varpropto v_^ Delta V_CA_ &varpropto v_^ The ratio of the potentential differences is fracDelta V_CA_Delta V_CA_ fracv_^v_^ frac For the potential difference between the cathode and the first anode we thus find Delta V_CA_ fracDelta V_CA_ DVF fracVC-VA DVP Since Delta V_CA_ V_C-V_A_ the potential at the first anode is V_A_ VBF VC - DV resultVBP
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Acceleration Voltage by by