Chemical Reactions
About points...
We associate a certain number of points with each exercise.
When you click an exercise into a collection, this number will be taken as points for the exercise, kind of "by default".
But once the exercise is on the collection, you can edit the number of points for the exercise in the collection independently, without any effect on "points by default" as represented by the number here.
That being said... How many "default points" should you associate with an exercise upon creation?
As with difficulty, there is no straight forward and generally accepted way.
But as a guideline, we tend to give as many points by default as there are mathematical steps to do in the exercise.
Again, very vague... But the number should kind of represent the "work" required.
When you click an exercise into a collection, this number will be taken as points for the exercise, kind of "by default".
But once the exercise is on the collection, you can edit the number of points for the exercise in the collection independently, without any effect on "points by default" as represented by the number here.
That being said... How many "default points" should you associate with an exercise upon creation?
As with difficulty, there is no straight forward and generally accepted way.
But as a guideline, we tend to give as many points by default as there are mathematical steps to do in the exercise.
Again, very vague... But the number should kind of represent the "work" required.
About difficulty...
We associate a certain difficulty with each exercise.
When you click an exercise into a collection, this number will be taken as difficulty for the exercise, kind of "by default".
But once the exercise is on the collection, you can edit its difficulty in the collection independently, without any effect on the "difficulty by default" here.
Why we use chess pieces? Well... we like chess, we like playing around with \(\LaTeX\)-fonts, we wanted symbols that need less space than six stars in a table-column... But in your layouts, you are of course free to indicate the difficulty of the exercise the way you want.
That being said... How "difficult" is an exercise? It depends on many factors, like what was being taught etc.
In physics exercises, we try to follow this pattern:
Level 1 - One formula (one you would find in a reference book) is enough to solve the exercise. Example exercise
Level 2 - Two formulas are needed, it's possible to compute an "in-between" solution, i.e. no algebraic equation needed. Example exercise
Level 3 - "Chain-computations" like on level 2, but 3+ calculations. Still, no equations, i.e. you are not forced to solve it in an algebraic manner. Example exercise
Level 4 - Exercise needs to be solved by algebraic equations, not possible to calculate numerical "in-between" results. Example exercise
Level 5 -
Level 6 -
When you click an exercise into a collection, this number will be taken as difficulty for the exercise, kind of "by default".
But once the exercise is on the collection, you can edit its difficulty in the collection independently, without any effect on the "difficulty by default" here.
Why we use chess pieces? Well... we like chess, we like playing around with \(\LaTeX\)-fonts, we wanted symbols that need less space than six stars in a table-column... But in your layouts, you are of course free to indicate the difficulty of the exercise the way you want.
That being said... How "difficult" is an exercise? It depends on many factors, like what was being taught etc.
In physics exercises, we try to follow this pattern:
Level 1 - One formula (one you would find in a reference book) is enough to solve the exercise. Example exercise
Level 2 - Two formulas are needed, it's possible to compute an "in-between" solution, i.e. no algebraic equation needed. Example exercise
Level 3 - "Chain-computations" like on level 2, but 3+ calculations. Still, no equations, i.e. you are not forced to solve it in an algebraic manner. Example exercise
Level 4 - Exercise needs to be solved by algebraic equations, not possible to calculate numerical "in-between" results. Example exercise
Level 5 -
Level 6 -
Question
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Exercise:
In a simple chemical reaction a chemical A turns o chemical B: A xlongrightarrowk B The rates of change of the concentrations of A and B are given by the reaction rate k: fracdAdt -kA fracdBdt +kA A more complicated reaction A xrightleftharpoonsk_k_ B xrightarrowk_ C with chemicals A B and C which also takes o account the reverse reaction between A and B can be described by fracdAdt -k_A + k_ B fracdBdt k_A - k_B - k_B fracdCdt k_B abcliste abc Derive the matrix describing the system of differential s. abc Calculate the eigenvalues and eigenvectors for k_ k_ k_ abc Find the solution for the initial conditions A A_ B C abcliste
Solution:
abcliste abc The matrix is M leftmatrix-k_ & k_ & k_ & -k_+k_ & & k_ & matrixright abc The eigenvalues of the matrix M are lambda_ lambda_ --sqrt lambda_ -+sqrt and the corresponding eigenvectors bf v_ leftmatrix matrixright bf v_ leftmatrix+sqrt --sqrt matrixright bf v_ leftmatrix-sqrt -+sqrt matrixright For the initial conditions we have to find coefficients a_ a_ and a_ such that leftmatrix matrixright a_bf v_+a_bf v_+a_bf v_ The three s are a_ +sqrt + a_ -sqrt a_ --sqrt + a_ -+sqrt a_ + a_ + a_ We find that a_ a_ frac-+sqrt a_ frac--sqrt so the concentrations are A frac-+sqrt+sqrt e^--sqrt t+frac--sqrt-sqrt e^-+sqrtt resultfrac e^--sqrt t+frace^-+sqrtt B frac-+sqrt--sqrt e^--sqrt t+frac--sqrt-+sqrt e^-+sqrtt result-fracsqrte^--sqrt t+fracsqrte^-+sqrtt C e^ t+frac-+sqrt e^--sqrt t+frac--sqrt e^-+sqrtt result+frac-+sqrt e^--sqrt t+frac--sqrt e^-+sqrtt The solution has the expected behaviour see figure below. Asymptotically the concentrations of A and B t towards while the concentration of C reaches %. center includegraphicswidthtextwidth#image_path:chemical-reactions# center abcliste
In a simple chemical reaction a chemical A turns o chemical B: A xlongrightarrowk B The rates of change of the concentrations of A and B are given by the reaction rate k: fracdAdt -kA fracdBdt +kA A more complicated reaction A xrightleftharpoonsk_k_ B xrightarrowk_ C with chemicals A B and C which also takes o account the reverse reaction between A and B can be described by fracdAdt -k_A + k_ B fracdBdt k_A - k_B - k_B fracdCdt k_B abcliste abc Derive the matrix describing the system of differential s. abc Calculate the eigenvalues and eigenvectors for k_ k_ k_ abc Find the solution for the initial conditions A A_ B C abcliste
Solution:
abcliste abc The matrix is M leftmatrix-k_ & k_ & k_ & -k_+k_ & & k_ & matrixright abc The eigenvalues of the matrix M are lambda_ lambda_ --sqrt lambda_ -+sqrt and the corresponding eigenvectors bf v_ leftmatrix matrixright bf v_ leftmatrix+sqrt --sqrt matrixright bf v_ leftmatrix-sqrt -+sqrt matrixright For the initial conditions we have to find coefficients a_ a_ and a_ such that leftmatrix matrixright a_bf v_+a_bf v_+a_bf v_ The three s are a_ +sqrt + a_ -sqrt a_ --sqrt + a_ -+sqrt a_ + a_ + a_ We find that a_ a_ frac-+sqrt a_ frac--sqrt so the concentrations are A frac-+sqrt+sqrt e^--sqrt t+frac--sqrt-sqrt e^-+sqrtt resultfrac e^--sqrt t+frace^-+sqrtt B frac-+sqrt--sqrt e^--sqrt t+frac--sqrt-+sqrt e^-+sqrtt result-fracsqrte^--sqrt t+fracsqrte^-+sqrtt C e^ t+frac-+sqrt e^--sqrt t+frac--sqrt e^-+sqrtt result+frac-+sqrt e^--sqrt t+frac--sqrt e^-+sqrtt The solution has the expected behaviour see figure below. Asymptotically the concentrations of A and B t towards while the concentration of C reaches %. center includegraphicswidthtextwidth#image_path:chemical-reactions# center abcliste
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Exercise:
In a simple chemical reaction a chemical A turns o chemical B: A xlongrightarrowk B The rates of change of the concentrations of A and B are given by the reaction rate k: fracdAdt -kA fracdBdt +kA A more complicated reaction A xrightleftharpoonsk_k_ B xrightarrowk_ C with chemicals A B and C which also takes o account the reverse reaction between A and B can be described by fracdAdt -k_A + k_ B fracdBdt k_A - k_B - k_B fracdCdt k_B abcliste abc Derive the matrix describing the system of differential s. abc Calculate the eigenvalues and eigenvectors for k_ k_ k_ abc Find the solution for the initial conditions A A_ B C abcliste
Solution:
abcliste abc The matrix is M leftmatrix-k_ & k_ & k_ & -k_+k_ & & k_ & matrixright abc The eigenvalues of the matrix M are lambda_ lambda_ --sqrt lambda_ -+sqrt and the corresponding eigenvectors bf v_ leftmatrix matrixright bf v_ leftmatrix+sqrt --sqrt matrixright bf v_ leftmatrix-sqrt -+sqrt matrixright For the initial conditions we have to find coefficients a_ a_ and a_ such that leftmatrix matrixright a_bf v_+a_bf v_+a_bf v_ The three s are a_ +sqrt + a_ -sqrt a_ --sqrt + a_ -+sqrt a_ + a_ + a_ We find that a_ a_ frac-+sqrt a_ frac--sqrt so the concentrations are A frac-+sqrt+sqrt e^--sqrt t+frac--sqrt-sqrt e^-+sqrtt resultfrac e^--sqrt t+frace^-+sqrtt B frac-+sqrt--sqrt e^--sqrt t+frac--sqrt-+sqrt e^-+sqrtt result-fracsqrte^--sqrt t+fracsqrte^-+sqrtt C e^ t+frac-+sqrt e^--sqrt t+frac--sqrt e^-+sqrtt result+frac-+sqrt e^--sqrt t+frac--sqrt e^-+sqrtt The solution has the expected behaviour see figure below. Asymptotically the concentrations of A and B t towards while the concentration of C reaches %. center includegraphicswidthtextwidth#image_path:chemical-reactions# center abcliste
In a simple chemical reaction a chemical A turns o chemical B: A xlongrightarrowk B The rates of change of the concentrations of A and B are given by the reaction rate k: fracdAdt -kA fracdBdt +kA A more complicated reaction A xrightleftharpoonsk_k_ B xrightarrowk_ C with chemicals A B and C which also takes o account the reverse reaction between A and B can be described by fracdAdt -k_A + k_ B fracdBdt k_A - k_B - k_B fracdCdt k_B abcliste abc Derive the matrix describing the system of differential s. abc Calculate the eigenvalues and eigenvectors for k_ k_ k_ abc Find the solution for the initial conditions A A_ B C abcliste
Solution:
abcliste abc The matrix is M leftmatrix-k_ & k_ & k_ & -k_+k_ & & k_ & matrixright abc The eigenvalues of the matrix M are lambda_ lambda_ --sqrt lambda_ -+sqrt and the corresponding eigenvectors bf v_ leftmatrix matrixright bf v_ leftmatrix+sqrt --sqrt matrixright bf v_ leftmatrix-sqrt -+sqrt matrixright For the initial conditions we have to find coefficients a_ a_ and a_ such that leftmatrix matrixright a_bf v_+a_bf v_+a_bf v_ The three s are a_ +sqrt + a_ -sqrt a_ --sqrt + a_ -+sqrt a_ + a_ + a_ We find that a_ a_ frac-+sqrt a_ frac--sqrt so the concentrations are A frac-+sqrt+sqrt e^--sqrt t+frac--sqrt-sqrt e^-+sqrtt resultfrac e^--sqrt t+frace^-+sqrtt B frac-+sqrt--sqrt e^--sqrt t+frac--sqrt-+sqrt e^-+sqrtt result-fracsqrte^--sqrt t+fracsqrte^-+sqrtt C e^ t+frac-+sqrt e^--sqrt t+frac--sqrt e^-+sqrtt result+frac-+sqrt e^--sqrt t+frac--sqrt e^-+sqrtt The solution has the expected behaviour see figure below. Asymptotically the concentrations of A and B t towards while the concentration of C reaches %. center includegraphicswidthtextwidth#image_path:chemical-reactions# center abcliste
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