Differential Equation for Damped Oscillation
About points...
We associate a certain number of points with each exercise.
When you click an exercise into a collection, this number will be taken as points for the exercise, kind of "by default".
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That being said... How many "default points" should you associate with an exercise upon creation?
As with difficulty, there is no straight forward and generally accepted way.
But as a guideline, we tend to give as many points by default as there are mathematical steps to do in the exercise.
Again, very vague... But the number should kind of represent the "work" required.
When you click an exercise into a collection, this number will be taken as points for the exercise, kind of "by default".
But once the exercise is on the collection, you can edit the number of points for the exercise in the collection independently, without any effect on "points by default" as represented by the number here.
That being said... How many "default points" should you associate with an exercise upon creation?
As with difficulty, there is no straight forward and generally accepted way.
But as a guideline, we tend to give as many points by default as there are mathematical steps to do in the exercise.
Again, very vague... But the number should kind of represent the "work" required.
About difficulty...
We associate a certain difficulty with each exercise.
When you click an exercise into a collection, this number will be taken as difficulty for the exercise, kind of "by default".
But once the exercise is on the collection, you can edit its difficulty in the collection independently, without any effect on the "difficulty by default" here.
Why we use chess pieces? Well... we like chess, we like playing around with \(\LaTeX\)-fonts, we wanted symbols that need less space than six stars in a table-column... But in your layouts, you are of course free to indicate the difficulty of the exercise the way you want.
That being said... How "difficult" is an exercise? It depends on many factors, like what was being taught etc.
In physics exercises, we try to follow this pattern:
Level 1 - One formula (one you would find in a reference book) is enough to solve the exercise. Example exercise
Level 2 - Two formulas are needed, it's possible to compute an "in-between" solution, i.e. no algebraic equation needed. Example exercise
Level 3 - "Chain-computations" like on level 2, but 3+ calculations. Still, no equations, i.e. you are not forced to solve it in an algebraic manner. Example exercise
Level 4 - Exercise needs to be solved by algebraic equations, not possible to calculate numerical "in-between" results. Example exercise
Level 5 -
Level 6 -
When you click an exercise into a collection, this number will be taken as difficulty for the exercise, kind of "by default".
But once the exercise is on the collection, you can edit its difficulty in the collection independently, without any effect on the "difficulty by default" here.
Why we use chess pieces? Well... we like chess, we like playing around with \(\LaTeX\)-fonts, we wanted symbols that need less space than six stars in a table-column... But in your layouts, you are of course free to indicate the difficulty of the exercise the way you want.
That being said... How "difficult" is an exercise? It depends on many factors, like what was being taught etc.
In physics exercises, we try to follow this pattern:
Level 1 - One formula (one you would find in a reference book) is enough to solve the exercise. Example exercise
Level 2 - Two formulas are needed, it's possible to compute an "in-between" solution, i.e. no algebraic equation needed. Example exercise
Level 3 - "Chain-computations" like on level 2, but 3+ calculations. Still, no equations, i.e. you are not forced to solve it in an algebraic manner. Example exercise
Level 4 - Exercise needs to be solved by algebraic equations, not possible to calculate numerical "in-between" results. Example exercise
Level 5 -
Level 6 -
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Exercise:
Show that the damped oscillation yt A e^-delta t cosomega t with omega^omega_^-delta^ is the solution to the differential ddot yt -omega_^ yt-deltadot yt with the initial conditions yA and dot y-Adelta.
Solution:
The first and second derivatives are as follows: dot yt Alefte^-delta t-delta cosomega t-e^-delta tsinomega tomegaright A e^-delta tleft-deltacosomega t-omegasinomega tright ddot yt Ae^-delta t-deltaleft-deltacosomega t-omegasinomega tright nonumber & quad +A e^-delta tleft+deltasinomega tomega-omegacosomega tomegaright A e^-delta tleftdelta^-omega^cosomega t+deltaomegasinomega tright For the right-hand side of the differential we find -omega_^ yt-delta dot yt -A e^-delta tleftomega^+delta^cosomega t -deltaleftdeltacosomega t+omegasinomega trightright A e^-delta tleftdelta^-omega^cosomega t+deltaomegasinomega tright This is equal to the left-hand side of the differential so the given function is a solution to the differential . The initial conditions can easily be verified.
Show that the damped oscillation yt A e^-delta t cosomega t with omega^omega_^-delta^ is the solution to the differential ddot yt -omega_^ yt-deltadot yt with the initial conditions yA and dot y-Adelta.
Solution:
The first and second derivatives are as follows: dot yt Alefte^-delta t-delta cosomega t-e^-delta tsinomega tomegaright A e^-delta tleft-deltacosomega t-omegasinomega tright ddot yt Ae^-delta t-deltaleft-deltacosomega t-omegasinomega tright nonumber & quad +A e^-delta tleft+deltasinomega tomega-omegacosomega tomegaright A e^-delta tleftdelta^-omega^cosomega t+deltaomegasinomega tright For the right-hand side of the differential we find -omega_^ yt-delta dot yt -A e^-delta tleftomega^+delta^cosomega t -deltaleftdeltacosomega t+omegasinomega trightright A e^-delta tleftdelta^-omega^cosomega t+deltaomegasinomega tright This is equal to the left-hand side of the differential so the given function is a solution to the differential . The initial conditions can easily be verified.
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Exercise:
Show that the damped oscillation yt A e^-delta t cosomega t with omega^omega_^-delta^ is the solution to the differential ddot yt -omega_^ yt-deltadot yt with the initial conditions yA and dot y-Adelta.
Solution:
The first and second derivatives are as follows: dot yt Alefte^-delta t-delta cosomega t-e^-delta tsinomega tomegaright A e^-delta tleft-deltacosomega t-omegasinomega tright ddot yt Ae^-delta t-deltaleft-deltacosomega t-omegasinomega tright nonumber & quad +A e^-delta tleft+deltasinomega tomega-omegacosomega tomegaright A e^-delta tleftdelta^-omega^cosomega t+deltaomegasinomega tright For the right-hand side of the differential we find -omega_^ yt-delta dot yt -A e^-delta tleftomega^+delta^cosomega t -deltaleftdeltacosomega t+omegasinomega trightright A e^-delta tleftdelta^-omega^cosomega t+deltaomegasinomega tright This is equal to the left-hand side of the differential so the given function is a solution to the differential . The initial conditions can easily be verified.
Show that the damped oscillation yt A e^-delta t cosomega t with omega^omega_^-delta^ is the solution to the differential ddot yt -omega_^ yt-deltadot yt with the initial conditions yA and dot y-Adelta.
Solution:
The first and second derivatives are as follows: dot yt Alefte^-delta t-delta cosomega t-e^-delta tsinomega tomegaright A e^-delta tleft-deltacosomega t-omegasinomega tright ddot yt Ae^-delta t-deltaleft-deltacosomega t-omegasinomega tright nonumber & quad +A e^-delta tleft+deltasinomega tomega-omegacosomega tomegaright A e^-delta tleftdelta^-omega^cosomega t+deltaomegasinomega tright For the right-hand side of the differential we find -omega_^ yt-delta dot yt -A e^-delta tleftomega^+delta^cosomega t -deltaleftdeltacosomega t+omegasinomega trightright A e^-delta tleftdelta^-omega^cosomega t+deltaomegasinomega tright This is equal to the left-hand side of the differential so the given function is a solution to the differential . The initial conditions can easily be verified.
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