Dipole in Field of Point Charge
About points...
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That being said... How many "default points" should you associate with an exercise upon creation?
As with difficulty, there is no straight forward and generally accepted way.
But as a guideline, we tend to give as many points by default as there are mathematical steps to do in the exercise.
Again, very vague... But the number should kind of represent the "work" required.
When you click an exercise into a collection, this number will be taken as points for the exercise, kind of "by default".
But once the exercise is on the collection, you can edit the number of points for the exercise in the collection independently, without any effect on "points by default" as represented by the number here.
That being said... How many "default points" should you associate with an exercise upon creation?
As with difficulty, there is no straight forward and generally accepted way.
But as a guideline, we tend to give as many points by default as there are mathematical steps to do in the exercise.
Again, very vague... But the number should kind of represent the "work" required.
About difficulty...
We associate a certain difficulty with each exercise.
When you click an exercise into a collection, this number will be taken as difficulty for the exercise, kind of "by default".
But once the exercise is on the collection, you can edit its difficulty in the collection independently, without any effect on the "difficulty by default" here.
Why we use chess pieces? Well... we like chess, we like playing around with \(\LaTeX\)-fonts, we wanted symbols that need less space than six stars in a table-column... But in your layouts, you are of course free to indicate the difficulty of the exercise the way you want.
That being said... How "difficult" is an exercise? It depends on many factors, like what was being taught etc.
In physics exercises, we try to follow this pattern:
Level 1 - One formula (one you would find in a reference book) is enough to solve the exercise. Example exercise
Level 2 - Two formulas are needed, it's possible to compute an "in-between" solution, i.e. no algebraic equation needed. Example exercise
Level 3 - "Chain-computations" like on level 2, but 3+ calculations. Still, no equations, i.e. you are not forced to solve it in an algebraic manner. Example exercise
Level 4 - Exercise needs to be solved by algebraic equations, not possible to calculate numerical "in-between" results. Example exercise
Level 5 -
Level 6 -
When you click an exercise into a collection, this number will be taken as difficulty for the exercise, kind of "by default".
But once the exercise is on the collection, you can edit its difficulty in the collection independently, without any effect on the "difficulty by default" here.
Why we use chess pieces? Well... we like chess, we like playing around with \(\LaTeX\)-fonts, we wanted symbols that need less space than six stars in a table-column... But in your layouts, you are of course free to indicate the difficulty of the exercise the way you want.
That being said... How "difficult" is an exercise? It depends on many factors, like what was being taught etc.
In physics exercises, we try to follow this pattern:
Level 1 - One formula (one you would find in a reference book) is enough to solve the exercise. Example exercise
Level 2 - Two formulas are needed, it's possible to compute an "in-between" solution, i.e. no algebraic equation needed. Example exercise
Level 3 - "Chain-computations" like on level 2, but 3+ calculations. Still, no equations, i.e. you are not forced to solve it in an algebraic manner. Example exercise
Level 4 - Exercise needs to be solved by algebraic equations, not possible to calculate numerical "in-between" results. Example exercise
Level 5 -
Level 6 -
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Exercise:
A dipole is placed in the field of a po charge with its dipole moment vec p q vec d ed in the direction of the field lines. abcliste abc Show that for a distance r from the po charge Q with r gg d the force acting on the dipole can be written as F - k_C fracQ pr^ abc Calculate the force on an HCl hydrochloric acid molecule at a distance rO from a H^+ ion. The dipole moment of an HCl molecule is pO. Compare the result to the force acting on an electron at the same distance. abcliste
Solution:
abcliste abc The forces on the positive and negative charge of a dipole at distance r from a po charge Q are F_+ q E_Qr+d/ q k_C fracQr+d/^ F_- -q E_Qr-d/ -q k_C fracQr-d/^ where we ase a simple dipole with its negative charge facing the po charge see figure. The net force is thus F q k_C Q leftfracr+d/^ - fracr-d/^ right k_C q Q fracr-d/^ - r+d/^r+d/^ r-d/^ k_C q Q fracr^+d^/-rd - r^+d^/+rdr^-d^/^ &approx k_C q Q frac-rdr^ - k_C Q q d fracr^ - k_C fracQ pr^ In this situation the force pos towards the po charge negative sign. abc The force acting on the molecule is F FF timeskCtimesfracncetimespr^ resultFS The force on an electron at the same distance would be F' FeF kC times fracnce^r^ resultFeS The force on the dipole is much weaker than that on the electron. abcliste
A dipole is placed in the field of a po charge with its dipole moment vec p q vec d ed in the direction of the field lines. abcliste abc Show that for a distance r from the po charge Q with r gg d the force acting on the dipole can be written as F - k_C fracQ pr^ abc Calculate the force on an HCl hydrochloric acid molecule at a distance rO from a H^+ ion. The dipole moment of an HCl molecule is pO. Compare the result to the force acting on an electron at the same distance. abcliste
Solution:
abcliste abc The forces on the positive and negative charge of a dipole at distance r from a po charge Q are F_+ q E_Qr+d/ q k_C fracQr+d/^ F_- -q E_Qr-d/ -q k_C fracQr-d/^ where we ase a simple dipole with its negative charge facing the po charge see figure. The net force is thus F q k_C Q leftfracr+d/^ - fracr-d/^ right k_C q Q fracr-d/^ - r+d/^r+d/^ r-d/^ k_C q Q fracr^+d^/-rd - r^+d^/+rdr^-d^/^ &approx k_C q Q frac-rdr^ - k_C Q q d fracr^ - k_C fracQ pr^ In this situation the force pos towards the po charge negative sign. abc The force acting on the molecule is F FF timeskCtimesfracncetimespr^ resultFS The force on an electron at the same distance would be F' FeF kC times fracnce^r^ resultFeS The force on the dipole is much weaker than that on the electron. abcliste
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Exercise:
A dipole is placed in the field of a po charge with its dipole moment vec p q vec d ed in the direction of the field lines. abcliste abc Show that for a distance r from the po charge Q with r gg d the force acting on the dipole can be written as F - k_C fracQ pr^ abc Calculate the force on an HCl hydrochloric acid molecule at a distance rO from a H^+ ion. The dipole moment of an HCl molecule is pO. Compare the result to the force acting on an electron at the same distance. abcliste
Solution:
abcliste abc The forces on the positive and negative charge of a dipole at distance r from a po charge Q are F_+ q E_Qr+d/ q k_C fracQr+d/^ F_- -q E_Qr-d/ -q k_C fracQr-d/^ where we ase a simple dipole with its negative charge facing the po charge see figure. The net force is thus F q k_C Q leftfracr+d/^ - fracr-d/^ right k_C q Q fracr-d/^ - r+d/^r+d/^ r-d/^ k_C q Q fracr^+d^/-rd - r^+d^/+rdr^-d^/^ &approx k_C q Q frac-rdr^ - k_C Q q d fracr^ - k_C fracQ pr^ In this situation the force pos towards the po charge negative sign. abc The force acting on the molecule is F FF timeskCtimesfracncetimespr^ resultFS The force on an electron at the same distance would be F' FeF kC times fracnce^r^ resultFeS The force on the dipole is much weaker than that on the electron. abcliste
A dipole is placed in the field of a po charge with its dipole moment vec p q vec d ed in the direction of the field lines. abcliste abc Show that for a distance r from the po charge Q with r gg d the force acting on the dipole can be written as F - k_C fracQ pr^ abc Calculate the force on an HCl hydrochloric acid molecule at a distance rO from a H^+ ion. The dipole moment of an HCl molecule is pO. Compare the result to the force acting on an electron at the same distance. abcliste
Solution:
abcliste abc The forces on the positive and negative charge of a dipole at distance r from a po charge Q are F_+ q E_Qr+d/ q k_C fracQr+d/^ F_- -q E_Qr-d/ -q k_C fracQr-d/^ where we ase a simple dipole with its negative charge facing the po charge see figure. The net force is thus F q k_C Q leftfracr+d/^ - fracr-d/^ right k_C q Q fracr-d/^ - r+d/^r+d/^ r-d/^ k_C q Q fracr^+d^/-rd - r^+d^/+rdr^-d^/^ &approx k_C q Q frac-rdr^ - k_C Q q d fracr^ - k_C fracQ pr^ In this situation the force pos towards the po charge negative sign. abc The force acting on the molecule is F FF timeskCtimesfracncetimespr^ resultFS The force on an electron at the same distance would be F' FeF kC times fracnce^r^ resultFeS The force on the dipole is much weaker than that on the electron. abcliste
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