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Driftgeschwindigkeit von Elektronen

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In physics exercises, we try to follow this pattern:

Level 1 - One formula (one you would find in a reference book) is enough to solve the exercise. Example exercise

Level 2 - Two formulas are needed, it's possible to compute an "in-between" solution, i.e. no algebraic equation needed. Example exercise

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Level 5 -
Level 6 -

Exercise

https://texercises.com/exercise/driftgeschwindigkeit-von-elektronen/

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Solution

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The following quantities appear in the problem: Masse \(m\) / elektrische Stromstärke \(I\) / elektrische Ladung \(q, Q\) / Volumen \(V\) / Geschwindigkeit \(v\) / Fläche \(A\) / molare Masse \(M\) / Stoffmenge \(n\) / Dichte \(\varrho\) /

The following formulas must be used to solve the exercise: \(\varrho = \dfrac{m}{V} \quad \) \(v = \frac{I}{neA} \quad \) \(m = nM \quad \)

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Exercise:
Wie gross ist die Driftgeschwindigkeit der Elektronen in einem Kupferdraht mit .mm Radius in dem ein Strom von einem Ampere fliesst? Es soll davon ausgeangen werden dass im Kupferdraht ein Leitungselektron pro Atom vorliegt.

Solution:
Es wird davon ausgeangen dass im Kupferdraht ein Leitungselektron pro Atom vorliegt was für Kupfer charakteristisch ist. Die Anzahl der Atome pro Volumenelement erhält man dann aus der Dichte der Avogadro-Konstanten sowie der molaren Masse n fracrho NAM fracpq.g/cm^ pq.emol^-pq.g/mol pq.ecm^- pq.em^-. Damit erhält man eine ungefähre Driftgeschwindigkeit von v fracIAne fracpqC/spi pq.m^ pq.em^- pq.C &approx pq..

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Tags	draht, driftgeschwindigkeit, elektrizitätslehre, elektron, gleichstromlehre, kupfer, physik, stromstärke
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Difficulty	(2, default)
Points	2 (default)
Language	(Deutsch)
Type	Calculative / Quantity
Creator	uz
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