Eistee
About points...
We associate a certain number of points with each exercise.
When you click an exercise into a collection, this number will be taken as points for the exercise, kind of "by default".
But once the exercise is on the collection, you can edit the number of points for the exercise in the collection independently, without any effect on "points by default" as represented by the number here.
That being said... How many "default points" should you associate with an exercise upon creation?
As with difficulty, there is no straight forward and generally accepted way.
But as a guideline, we tend to give as many points by default as there are mathematical steps to do in the exercise.
Again, very vague... But the number should kind of represent the "work" required.
When you click an exercise into a collection, this number will be taken as points for the exercise, kind of "by default".
But once the exercise is on the collection, you can edit the number of points for the exercise in the collection independently, without any effect on "points by default" as represented by the number here.
That being said... How many "default points" should you associate with an exercise upon creation?
As with difficulty, there is no straight forward and generally accepted way.
But as a guideline, we tend to give as many points by default as there are mathematical steps to do in the exercise.
Again, very vague... But the number should kind of represent the "work" required.
About difficulty...
We associate a certain difficulty with each exercise.
When you click an exercise into a collection, this number will be taken as difficulty for the exercise, kind of "by default".
But once the exercise is on the collection, you can edit its difficulty in the collection independently, without any effect on the "difficulty by default" here.
Why we use chess pieces? Well... we like chess, we like playing around with \(\LaTeX\)-fonts, we wanted symbols that need less space than six stars in a table-column... But in your layouts, you are of course free to indicate the difficulty of the exercise the way you want.
That being said... How "difficult" is an exercise? It depends on many factors, like what was being taught etc.
In physics exercises, we try to follow this pattern:
Level 1 - One formula (one you would find in a reference book) is enough to solve the exercise. Example exercise
Level 2 - Two formulas are needed, it's possible to compute an "in-between" solution, i.e. no algebraic equation needed. Example exercise
Level 3 - "Chain-computations" like on level 2, but 3+ calculations. Still, no equations, i.e. you are not forced to solve it in an algebraic manner. Example exercise
Level 4 - Exercise needs to be solved by algebraic equations, not possible to calculate numerical "in-between" results. Example exercise
Level 5 -
Level 6 -
When you click an exercise into a collection, this number will be taken as difficulty for the exercise, kind of "by default".
But once the exercise is on the collection, you can edit its difficulty in the collection independently, without any effect on the "difficulty by default" here.
Why we use chess pieces? Well... we like chess, we like playing around with \(\LaTeX\)-fonts, we wanted symbols that need less space than six stars in a table-column... But in your layouts, you are of course free to indicate the difficulty of the exercise the way you want.
That being said... How "difficult" is an exercise? It depends on many factors, like what was being taught etc.
In physics exercises, we try to follow this pattern:
Level 1 - One formula (one you would find in a reference book) is enough to solve the exercise. Example exercise
Level 2 - Two formulas are needed, it's possible to compute an "in-between" solution, i.e. no algebraic equation needed. Example exercise
Level 3 - "Chain-computations" like on level 2, but 3+ calculations. Still, no equations, i.e. you are not forced to solve it in an algebraic manner. Example exercise
Level 4 - Exercise needs to be solved by algebraic equations, not possible to calculate numerical "in-between" results. Example exercise
Level 5 -
Level 6 -
Question
Solution
Short
Video
\(\LaTeX\)
Need help? Yes, please!
The following quantities appear in the problem:
Masse \(m\) / Temperatur \(T\) / Wärme \(Q\) / spezifische latente Wärme \(L\) / Wärmekapazität \(c\) /
The following formulas must be used to solve the exercise:
\(Q = c \cdot m \cdot \Delta\vartheta \quad \) \(Q = m \cdot L_{\scriptscriptstyle\rm f} \quad \) \(\sum Q^\nearrow \stackrel{!}{=} \sum Q^\swarrow \quad \)
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Visit our YouTube-Channel to see solutions to other exercises.
Don't forget to subscribe to our channel, like the videos and leave comments!
Exercise:
Zu pqdl Eistee als Wasser zu betrachten! von TCelsius gibt man pqg Eis von TCelsius-. Auf welche Endtemperatur könnte der Saft im günstigsten Falle abgekühlt werden?
Solution:
Der Eistee mit Masse m_T rho V pqkgpmk pqm^ pq.kg gibt beim Abkühlen Wärme ab Qab c_w m_T pqCelsius-theta. Diese Wärme heizt das Eis bis zur Schmelztemperatur auf Qzu_ c_E m_E Dtheta pqJpkgK pq.kg pqK pqJ schmelzt es wofür die Energie Qzu_ L_f m_E pq.eJpkg pq.kg pqJ nötig ist und wärmt das so entstandene Wasser weiter bis zur Mischtemperatur auf Qzu_ c_W m_E theta-pqCelsius c_W m_E theta. Somit gilt Qabmustbe Qzu_+Qzu_+Qzu_; also Qab &mustbe Qzu c_W m_T pqCelsius-theta c_E m_E Dtheta + L_f m_E + c_W m_E theta c_W m_T pqCelsius-theta pqJ + pqJ + c_W m_E theta theta fracc_wm_T pqK - pqJc_Wm_E+m_T pq.Celsius.
Zu pqdl Eistee als Wasser zu betrachten! von TCelsius gibt man pqg Eis von TCelsius-. Auf welche Endtemperatur könnte der Saft im günstigsten Falle abgekühlt werden?
Solution:
Der Eistee mit Masse m_T rho V pqkgpmk pqm^ pq.kg gibt beim Abkühlen Wärme ab Qab c_w m_T pqCelsius-theta. Diese Wärme heizt das Eis bis zur Schmelztemperatur auf Qzu_ c_E m_E Dtheta pqJpkgK pq.kg pqK pqJ schmelzt es wofür die Energie Qzu_ L_f m_E pq.eJpkg pq.kg pqJ nötig ist und wärmt das so entstandene Wasser weiter bis zur Mischtemperatur auf Qzu_ c_W m_E theta-pqCelsius c_W m_E theta. Somit gilt Qabmustbe Qzu_+Qzu_+Qzu_; also Qab &mustbe Qzu c_W m_T pqCelsius-theta c_E m_E Dtheta + L_f m_E + c_W m_E theta c_W m_T pqCelsius-theta pqJ + pqJ + c_W m_E theta theta fracc_wm_T pqK - pqJc_Wm_E+m_T pq.Celsius.
Meta Information
Exercise:
Zu pqdl Eistee als Wasser zu betrachten! von TCelsius gibt man pqg Eis von TCelsius-. Auf welche Endtemperatur könnte der Saft im günstigsten Falle abgekühlt werden?
Solution:
Der Eistee mit Masse m_T rho V pqkgpmk pqm^ pq.kg gibt beim Abkühlen Wärme ab Qab c_w m_T pqCelsius-theta. Diese Wärme heizt das Eis bis zur Schmelztemperatur auf Qzu_ c_E m_E Dtheta pqJpkgK pq.kg pqK pqJ schmelzt es wofür die Energie Qzu_ L_f m_E pq.eJpkg pq.kg pqJ nötig ist und wärmt das so entstandene Wasser weiter bis zur Mischtemperatur auf Qzu_ c_W m_E theta-pqCelsius c_W m_E theta. Somit gilt Qabmustbe Qzu_+Qzu_+Qzu_; also Qab &mustbe Qzu c_W m_T pqCelsius-theta c_E m_E Dtheta + L_f m_E + c_W m_E theta c_W m_T pqCelsius-theta pqJ + pqJ + c_W m_E theta theta fracc_wm_T pqK - pqJc_Wm_E+m_T pq.Celsius.
Zu pqdl Eistee als Wasser zu betrachten! von TCelsius gibt man pqg Eis von TCelsius-. Auf welche Endtemperatur könnte der Saft im günstigsten Falle abgekühlt werden?
Solution:
Der Eistee mit Masse m_T rho V pqkgpmk pqm^ pq.kg gibt beim Abkühlen Wärme ab Qab c_w m_T pqCelsius-theta. Diese Wärme heizt das Eis bis zur Schmelztemperatur auf Qzu_ c_E m_E Dtheta pqJpkgK pq.kg pqK pqJ schmelzt es wofür die Energie Qzu_ L_f m_E pq.eJpkg pq.kg pqJ nötig ist und wärmt das so entstandene Wasser weiter bis zur Mischtemperatur auf Qzu_ c_W m_E theta-pqCelsius c_W m_E theta. Somit gilt Qabmustbe Qzu_+Qzu_+Qzu_; also Qab &mustbe Qzu c_W m_T pqCelsius-theta c_E m_E Dtheta + L_f m_E + c_W m_E theta c_W m_T pqCelsius-theta pqJ + pqJ + c_W m_E theta theta fracc_wm_T pqK - pqJc_Wm_E+m_T pq.Celsius.
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Asked Quantity:
Temperatur \(T\)
in
Kelvin \(\rm K\)
Physical Quantity
Unit