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Exercise:
Electrons enter a uniform magnetic field with strength BO at vcO of the speed of light. The angle between the electron beam and the magnetic field lines is alO. Determine the direction and magnitude of an additional electric field which compensates the effect of the magnetic force.

Solution:
Asing the electron's velocity and the magnetic field are in the drawing plane as in the figure the magnetic force pos o the drawing plane left-hand rule. To compensate this force the electrostatic force has to po out of the plane. Since the electron is a negatively charged particle this means that the electric field pos o the plane. includegraphicswidth.textwidth#image_path:electron-in-crossed-fields# The force equlibrium ist given by F_E F_B q E q v B sinalpha It follows for the strength of the electric field E EF vtimes Btimes sinal E approx resultEP
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Exercise:
Electrons enter a uniform magnetic field with strength BO at vcO of the speed of light. The angle between the electron beam and the magnetic field lines is alO. Determine the direction and magnitude of an additional electric field which compensates the effect of the magnetic force.

Solution:
Asing the electron's velocity and the magnetic field are in the drawing plane as in the figure the magnetic force pos o the drawing plane left-hand rule. To compensate this force the electrostatic force has to po out of the plane. Since the electron is a negatively charged particle this means that the electric field pos o the plane. includegraphicswidth.textwidth#image_path:electron-in-crossed-fields# The force equlibrium ist given by F_E F_B q E q v B sinalpha It follows for the strength of the electric field E EF vtimes Btimes sinal E approx resultEP
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Attributes & Decorations
Branches
Magnetism
Tags
electric field, electron, magnetic field, magnetic force
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Difficulty
(2, default)
Points
0 (default)
Language
ENG (English)
Type
Calculative / Quantity
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Decoration