Exercise
https://texercises.com/exercise/ersatzwiderstand-19/
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The following quantities appear in the problem: elektrischer Widerstand \(R\) / Federkonstante \(D\) /
The following formulas must be used to solve the exercise: \(\frac{1}{R} = \frac{1}{R_1} + \frac{1}{R_2} \quad \) \(\frac{1}{D} = \frac{1}{D_1} + \frac{1}{D_2} \quad \) \(R = R_1 + R_2 \quad \)
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Exercise:
Berechnen Sie für folge Schaltung den Ersatzwiderstand: center tikzpicture draw . to european resistor l^ohm .; draw . to european resistor l^.ohm .; draw -. to european resistor l^.ohm -.; draw -. to european resistor l^ohm -.; draw .---.; draw .---.; draw ---.; draw --.; %draw .--.-. to battery -.-.---.; tikzpicture center

Solution:
Der Ersatzwiderstand beträgt al R_ Rof qtyfracRe+Rz + fracRd+Rv^- RoTTTT.
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Exercise:
Berechnen Sie für folge Schaltung den Ersatzwiderstand: center tikzpicture draw . to european resistor l^ohm .; draw . to european resistor l^.ohm .; draw -. to european resistor l^.ohm -.; draw -. to european resistor l^ohm -.; draw .---.; draw .---.; draw ---.; draw --.; %draw .--.-. to battery -.-.---.; tikzpicture center

Solution:
Der Ersatzwiderstand beträgt al R_ Rof qtyfracRe+Rz + fracRd+Rv^- RoTTTT.
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Direct Current
Tags
ersatzwiderstand, gleichstrom, schaltungstechnik, sudoku, widerstand
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Difficulty
(3, default)
Points
3 (default)
Language
GER (Deutsch)
Type
Calculative / Quantity
Creator aej
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Link