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Exercise:
An electron flies at constant speed parallel to the earth’s surface. Determine the magnitude and direction of the electric field at the position of the electron and discuss the result.

Solution:
Since the electron flies at constant height it is in a force equilibrium i.e. there is an upward electrostatic force F_E compensating the downward gravitational force F_G: sscFE sscFG longrightarrow e E m_e g It follows for the electric field E: E EF fracncmetimesncgnce E approx EP- Since the electron has a negative charge and the electrostatic force has to po upwards the electric field pos downwards. The magnitude of the electric field required to keep the electron on a horizontal trajectory is much weaker than typical fields in the air. It is therefore very unlikely that this will happen.
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Exercise:
An electron flies at constant speed parallel to the earth’s surface. Determine the magnitude and direction of the electric field at the position of the electron and discuss the result.

Solution:
Since the electron flies at constant height it is in a force equilibrium i.e. there is an upward electrostatic force F_E compensating the downward gravitational force F_G: sscFE sscFG longrightarrow e E m_e g It follows for the electric field E: E EF fracncmetimesncgnce E approx EP- Since the electron has a negative charge and the electrostatic force has to po upwards the electric field pos downwards. The magnitude of the electric field required to keep the electron on a horizontal trajectory is much weaker than typical fields in the air. It is therefore very unlikely that this will happen.
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Branches
Electrostatics
Tags
electric field, electrostatics, elementary charge, gravitation
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Difficulty
(1, default)
Points
0 (default)
Language
ENG (English)
Type
Calculative / Quantity
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