Gestossener Klotz
About points...
We associate a certain number of points with each exercise.
When you click an exercise into a collection, this number will be taken as points for the exercise, kind of "by default".
But once the exercise is on the collection, you can edit the number of points for the exercise in the collection independently, without any effect on "points by default" as represented by the number here.
That being said... How many "default points" should you associate with an exercise upon creation?
As with difficulty, there is no straight forward and generally accepted way.
But as a guideline, we tend to give as many points by default as there are mathematical steps to do in the exercise.
Again, very vague... But the number should kind of represent the "work" required.
When you click an exercise into a collection, this number will be taken as points for the exercise, kind of "by default".
But once the exercise is on the collection, you can edit the number of points for the exercise in the collection independently, without any effect on "points by default" as represented by the number here.
That being said... How many "default points" should you associate with an exercise upon creation?
As with difficulty, there is no straight forward and generally accepted way.
But as a guideline, we tend to give as many points by default as there are mathematical steps to do in the exercise.
Again, very vague... But the number should kind of represent the "work" required.
About difficulty...
We associate a certain difficulty with each exercise.
When you click an exercise into a collection, this number will be taken as difficulty for the exercise, kind of "by default".
But once the exercise is on the collection, you can edit its difficulty in the collection independently, without any effect on the "difficulty by default" here.
Why we use chess pieces? Well... we like chess, we like playing around with \(\LaTeX\)-fonts, we wanted symbols that need less space than six stars in a table-column... But in your layouts, you are of course free to indicate the difficulty of the exercise the way you want.
That being said... How "difficult" is an exercise? It depends on many factors, like what was being taught etc.
In physics exercises, we try to follow this pattern:
Level 1 - One formula (one you would find in a reference book) is enough to solve the exercise. Example exercise
Level 2 - Two formulas are needed, it's possible to compute an "in-between" solution, i.e. no algebraic equation needed. Example exercise
Level 3 - "Chain-computations" like on level 2, but 3+ calculations. Still, no equations, i.e. you are not forced to solve it in an algebraic manner. Example exercise
Level 4 - Exercise needs to be solved by algebraic equations, not possible to calculate numerical "in-between" results. Example exercise
Level 5 -
Level 6 -
When you click an exercise into a collection, this number will be taken as difficulty for the exercise, kind of "by default".
But once the exercise is on the collection, you can edit its difficulty in the collection independently, without any effect on the "difficulty by default" here.
Why we use chess pieces? Well... we like chess, we like playing around with \(\LaTeX\)-fonts, we wanted symbols that need less space than six stars in a table-column... But in your layouts, you are of course free to indicate the difficulty of the exercise the way you want.
That being said... How "difficult" is an exercise? It depends on many factors, like what was being taught etc.
In physics exercises, we try to follow this pattern:
Level 1 - One formula (one you would find in a reference book) is enough to solve the exercise. Example exercise
Level 2 - Two formulas are needed, it's possible to compute an "in-between" solution, i.e. no algebraic equation needed. Example exercise
Level 3 - "Chain-computations" like on level 2, but 3+ calculations. Still, no equations, i.e. you are not forced to solve it in an algebraic manner. Example exercise
Level 4 - Exercise needs to be solved by algebraic equations, not possible to calculate numerical "in-between" results. Example exercise
Level 5 -
Level 6 -
Question
Solution
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Exercise:
Eine konstante Stosskraft von siN greift unter einem Winkel von degr zur Waagrechten an einem ruhen Block an. Der Block liegt auf einer horizontalen Oberfläche und hat eine Masse von sikg. Mit der Stosskraft erreicht der Block nach sis eine Geschwindigkeit von .sim/s. Wie gross ist der Reibungskoeffizient mu_tinysubG?
Solution:
Geg.: FsiN alphadegr tsis v_mathrme.sim/s msikg Ges.: mu_tinysubG Kräfteskizze: figureH centering tikzpicturelatex %draw step.colorgray! -- grid ; %fill circle .; draw --; fill patternnorth east lines rectangle -.; draw fillgray! rectangle .;%nodemidwayyshift.cmxshift.cm m scopexshift.cm draw - -.---..noderight x; draw - -.---.nodeabove y; scope draw -thickRed .-- -noderight vfg ; draw -thickBlue .-- ..noderight vecF_mathrmN; draw -thickGreen --nodeabovevecF_mathrmR; draw -thick -.--nodebelowvecF_x .; draw -thick -.--nodeleftvecF_y -; draw -thick ---nodeabovevecF.; draw thick .arc:.:; node at .. alpha; tikzpicture figure Für die beiden Koordinatenrichtungen gilt: fresxm a_xF_x-F_mathrmR fresyF_mathrmN-sscFG-F_y Die Bewegung erfolgt in x-Richtung. Wir können Gleichung so schreiben: m a_xFcosalpha-mu_tinysubG F_mathrmN Für a_x erhalten wir: a_xfracv_mathrmet.sis Für F_mathrmN erhalten wir aus Gleichung : F_mathrmNm g+Fsinalpha.siN Damit erhalten wir: mu_tinysubGfrac-m a_x+FcosalphaF_mathrmNres. Allgemeine Lösung: mu_tinysubGfrac-m fracv_mathrmet+Fcosalpham g+Fsinalpha
Eine konstante Stosskraft von siN greift unter einem Winkel von degr zur Waagrechten an einem ruhen Block an. Der Block liegt auf einer horizontalen Oberfläche und hat eine Masse von sikg. Mit der Stosskraft erreicht der Block nach sis eine Geschwindigkeit von .sim/s. Wie gross ist der Reibungskoeffizient mu_tinysubG?
Solution:
Geg.: FsiN alphadegr tsis v_mathrme.sim/s msikg Ges.: mu_tinysubG Kräfteskizze: figureH centering tikzpicturelatex %draw step.colorgray! -- grid ; %fill circle .; draw --; fill patternnorth east lines rectangle -.; draw fillgray! rectangle .;%nodemidwayyshift.cmxshift.cm m scopexshift.cm draw - -.---..noderight x; draw - -.---.nodeabove y; scope draw -thickRed .-- -noderight vfg ; draw -thickBlue .-- ..noderight vecF_mathrmN; draw -thickGreen --nodeabovevecF_mathrmR; draw -thick -.--nodebelowvecF_x .; draw -thick -.--nodeleftvecF_y -; draw -thick ---nodeabovevecF.; draw thick .arc:.:; node at .. alpha; tikzpicture figure Für die beiden Koordinatenrichtungen gilt: fresxm a_xF_x-F_mathrmR fresyF_mathrmN-sscFG-F_y Die Bewegung erfolgt in x-Richtung. Wir können Gleichung so schreiben: m a_xFcosalpha-mu_tinysubG F_mathrmN Für a_x erhalten wir: a_xfracv_mathrmet.sis Für F_mathrmN erhalten wir aus Gleichung : F_mathrmNm g+Fsinalpha.siN Damit erhalten wir: mu_tinysubGfrac-m a_x+FcosalphaF_mathrmNres. Allgemeine Lösung: mu_tinysubGfrac-m fracv_mathrmet+Fcosalpham g+Fsinalpha
Meta Information
Exercise:
Eine konstante Stosskraft von siN greift unter einem Winkel von degr zur Waagrechten an einem ruhen Block an. Der Block liegt auf einer horizontalen Oberfläche und hat eine Masse von sikg. Mit der Stosskraft erreicht der Block nach sis eine Geschwindigkeit von .sim/s. Wie gross ist der Reibungskoeffizient mu_tinysubG?
Solution:
Geg.: FsiN alphadegr tsis v_mathrme.sim/s msikg Ges.: mu_tinysubG Kräfteskizze: figureH centering tikzpicturelatex %draw step.colorgray! -- grid ; %fill circle .; draw --; fill patternnorth east lines rectangle -.; draw fillgray! rectangle .;%nodemidwayyshift.cmxshift.cm m scopexshift.cm draw - -.---..noderight x; draw - -.---.nodeabove y; scope draw -thickRed .-- -noderight vfg ; draw -thickBlue .-- ..noderight vecF_mathrmN; draw -thickGreen --nodeabovevecF_mathrmR; draw -thick -.--nodebelowvecF_x .; draw -thick -.--nodeleftvecF_y -; draw -thick ---nodeabovevecF.; draw thick .arc:.:; node at .. alpha; tikzpicture figure Für die beiden Koordinatenrichtungen gilt: fresxm a_xF_x-F_mathrmR fresyF_mathrmN-sscFG-F_y Die Bewegung erfolgt in x-Richtung. Wir können Gleichung so schreiben: m a_xFcosalpha-mu_tinysubG F_mathrmN Für a_x erhalten wir: a_xfracv_mathrmet.sis Für F_mathrmN erhalten wir aus Gleichung : F_mathrmNm g+Fsinalpha.siN Damit erhalten wir: mu_tinysubGfrac-m a_x+FcosalphaF_mathrmNres. Allgemeine Lösung: mu_tinysubGfrac-m fracv_mathrmet+Fcosalpham g+Fsinalpha
Eine konstante Stosskraft von siN greift unter einem Winkel von degr zur Waagrechten an einem ruhen Block an. Der Block liegt auf einer horizontalen Oberfläche und hat eine Masse von sikg. Mit der Stosskraft erreicht der Block nach sis eine Geschwindigkeit von .sim/s. Wie gross ist der Reibungskoeffizient mu_tinysubG?
Solution:
Geg.: FsiN alphadegr tsis v_mathrme.sim/s msikg Ges.: mu_tinysubG Kräfteskizze: figureH centering tikzpicturelatex %draw step.colorgray! -- grid ; %fill circle .; draw --; fill patternnorth east lines rectangle -.; draw fillgray! rectangle .;%nodemidwayyshift.cmxshift.cm m scopexshift.cm draw - -.---..noderight x; draw - -.---.nodeabove y; scope draw -thickRed .-- -noderight vfg ; draw -thickBlue .-- ..noderight vecF_mathrmN; draw -thickGreen --nodeabovevecF_mathrmR; draw -thick -.--nodebelowvecF_x .; draw -thick -.--nodeleftvecF_y -; draw -thick ---nodeabovevecF.; draw thick .arc:.:; node at .. alpha; tikzpicture figure Für die beiden Koordinatenrichtungen gilt: fresxm a_xF_x-F_mathrmR fresyF_mathrmN-sscFG-F_y Die Bewegung erfolgt in x-Richtung. Wir können Gleichung so schreiben: m a_xFcosalpha-mu_tinysubG F_mathrmN Für a_x erhalten wir: a_xfracv_mathrmet.sis Für F_mathrmN erhalten wir aus Gleichung : F_mathrmNm g+Fsinalpha.siN Damit erhalten wir: mu_tinysubGfrac-m a_x+FcosalphaF_mathrmNres. Allgemeine Lösung: mu_tinysubGfrac-m fracv_mathrmet+Fcosalpham g+Fsinalpha
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