Gewicht von Kupferdraht
About points...
We associate a certain number of points with each exercise.
When you click an exercise into a collection, this number will be taken as points for the exercise, kind of "by default".
But once the exercise is on the collection, you can edit the number of points for the exercise in the collection independently, without any effect on "points by default" as represented by the number here.
That being said... How many "default points" should you associate with an exercise upon creation?
As with difficulty, there is no straight forward and generally accepted way.
But as a guideline, we tend to give as many points by default as there are mathematical steps to do in the exercise.
Again, very vague... But the number should kind of represent the "work" required.
When you click an exercise into a collection, this number will be taken as points for the exercise, kind of "by default".
But once the exercise is on the collection, you can edit the number of points for the exercise in the collection independently, without any effect on "points by default" as represented by the number here.
That being said... How many "default points" should you associate with an exercise upon creation?
As with difficulty, there is no straight forward and generally accepted way.
But as a guideline, we tend to give as many points by default as there are mathematical steps to do in the exercise.
Again, very vague... But the number should kind of represent the "work" required.
About difficulty...
We associate a certain difficulty with each exercise.
When you click an exercise into a collection, this number will be taken as difficulty for the exercise, kind of "by default".
But once the exercise is on the collection, you can edit its difficulty in the collection independently, without any effect on the "difficulty by default" here.
Why we use chess pieces? Well... we like chess, we like playing around with \(\LaTeX\)-fonts, we wanted symbols that need less space than six stars in a table-column... But in your layouts, you are of course free to indicate the difficulty of the exercise the way you want.
That being said... How "difficult" is an exercise? It depends on many factors, like what was being taught etc.
In physics exercises, we try to follow this pattern:
Level 1 - One formula (one you would find in a reference book) is enough to solve the exercise. Example exercise
Level 2 - Two formulas are needed, it's possible to compute an "in-between" solution, i.e. no algebraic equation needed. Example exercise
Level 3 - "Chain-computations" like on level 2, but 3+ calculations. Still, no equations, i.e. you are not forced to solve it in an algebraic manner. Example exercise
Level 4 - Exercise needs to be solved by algebraic equations, not possible to calculate numerical "in-between" results. Example exercise
Level 5 -
Level 6 -
When you click an exercise into a collection, this number will be taken as difficulty for the exercise, kind of "by default".
But once the exercise is on the collection, you can edit its difficulty in the collection independently, without any effect on the "difficulty by default" here.
Why we use chess pieces? Well... we like chess, we like playing around with \(\LaTeX\)-fonts, we wanted symbols that need less space than six stars in a table-column... But in your layouts, you are of course free to indicate the difficulty of the exercise the way you want.
That being said... How "difficult" is an exercise? It depends on many factors, like what was being taught etc.
In physics exercises, we try to follow this pattern:
Level 1 - One formula (one you would find in a reference book) is enough to solve the exercise. Example exercise
Level 2 - Two formulas are needed, it's possible to compute an "in-between" solution, i.e. no algebraic equation needed. Example exercise
Level 3 - "Chain-computations" like on level 2, but 3+ calculations. Still, no equations, i.e. you are not forced to solve it in an algebraic manner. Example exercise
Level 4 - Exercise needs to be solved by algebraic equations, not possible to calculate numerical "in-between" results. Example exercise
Level 5 -
Level 6 -
Question
Solution
Short
Video
Applet
\(\LaTeX\)
Need help? Yes, please!
The following quantities appear in the problem:
Länge \(\ell\) / Masse \(m\) / Kraft \(F\) / elektrischer Widerstand \(R\) / Volumen \(V\) / Fläche \(A\) / Ortsfaktor \(g\) / Höhe \(h\) / Radius \(r\) / Dichte \(\varrho\) / spezifischer elektrischer Widerstand \(\rho\) /
The following formulas must be used to solve the exercise:
\(\varrho = \dfrac{m}{V} \quad \) \(F = mg \quad \) \(A = \pi r^2 \quad \) \(R = \varrho \dfrac{\ell}{A} \quad \) \(V = \pi r^2 \cdot h \quad \)
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Visit our YouTube-Channel to see solutions to other exercises.
Don't forget to subscribe to our channel, like the videos and leave comments!
Widerstand eines Drahtes
Open in its own page
Exercise:
Welche Länge hat ein Kupferdraht kilogrampercubicmeter .ohmmeter von .mm Durchmesser und .ohm Widerstand und wie gross ist sein Gewicht?
Solution:
NewQtyrckilogrampercubicmeter NewQtyre.ohmmeter NewQtyd.m NewQtyR.ohm % Geg rho rc rhoel re d .mm d R R % GesGewichtskraftFG siN Der Querschnitt des Drahtes ist beim angegebenen Durchmesser SolQtyAfracd^pidX***pi/squaremeter al A AF fracqtyd^ pi A. % Er ist SolQtyelfracRd^pirhoelRX*AX/reXm al ell fracRArhoel elF fracR qtyd^ pi re el lang. Sein Volumen ist folglich SolQtyVfracRd^pi^rhoelelX*AXcubicmeter al V ell A VF fracR qtyd^ pi^ re V. % Bei der angegebenen Dichte ist die Masse dann SolQtymfracrho Rd^pi^rhoelrcX*VXkg al m rho V mF fracrc R qtyd^ pi^ re m. % Auf der Erde ist sein Gewicht SolQtyFfracrho g Rd^pi^rhoelmX*gMnN al FG mg FF fracrc gM R qtyd^ pi^ re F. % FG FF FS
Welche Länge hat ein Kupferdraht kilogrampercubicmeter .ohmmeter von .mm Durchmesser und .ohm Widerstand und wie gross ist sein Gewicht?
Solution:
NewQtyrckilogrampercubicmeter NewQtyre.ohmmeter NewQtyd.m NewQtyR.ohm % Geg rho rc rhoel re d .mm d R R % GesGewichtskraftFG siN Der Querschnitt des Drahtes ist beim angegebenen Durchmesser SolQtyAfracd^pidX***pi/squaremeter al A AF fracqtyd^ pi A. % Er ist SolQtyelfracRd^pirhoelRX*AX/reXm al ell fracRArhoel elF fracR qtyd^ pi re el lang. Sein Volumen ist folglich SolQtyVfracRd^pi^rhoelelX*AXcubicmeter al V ell A VF fracR qtyd^ pi^ re V. % Bei der angegebenen Dichte ist die Masse dann SolQtymfracrho Rd^pi^rhoelrcX*VXkg al m rho V mF fracrc R qtyd^ pi^ re m. % Auf der Erde ist sein Gewicht SolQtyFfracrho g Rd^pi^rhoelmX*gMnN al FG mg FF fracrc gM R qtyd^ pi^ re F. % FG FF FS
Meta Information
Exercise:
Welche Länge hat ein Kupferdraht kilogrampercubicmeter .ohmmeter von .mm Durchmesser und .ohm Widerstand und wie gross ist sein Gewicht?
Solution:
NewQtyrckilogrampercubicmeter NewQtyre.ohmmeter NewQtyd.m NewQtyR.ohm % Geg rho rc rhoel re d .mm d R R % GesGewichtskraftFG siN Der Querschnitt des Drahtes ist beim angegebenen Durchmesser SolQtyAfracd^pidX***pi/squaremeter al A AF fracqtyd^ pi A. % Er ist SolQtyelfracRd^pirhoelRX*AX/reXm al ell fracRArhoel elF fracR qtyd^ pi re el lang. Sein Volumen ist folglich SolQtyVfracRd^pi^rhoelelX*AXcubicmeter al V ell A VF fracR qtyd^ pi^ re V. % Bei der angegebenen Dichte ist die Masse dann SolQtymfracrho Rd^pi^rhoelrcX*VXkg al m rho V mF fracrc R qtyd^ pi^ re m. % Auf der Erde ist sein Gewicht SolQtyFfracrho g Rd^pi^rhoelmX*gMnN al FG mg FF fracrc gM R qtyd^ pi^ re F. % FG FF FS
Welche Länge hat ein Kupferdraht kilogrampercubicmeter .ohmmeter von .mm Durchmesser und .ohm Widerstand und wie gross ist sein Gewicht?
Solution:
NewQtyrckilogrampercubicmeter NewQtyre.ohmmeter NewQtyd.m NewQtyR.ohm % Geg rho rc rhoel re d .mm d R R % GesGewichtskraftFG siN Der Querschnitt des Drahtes ist beim angegebenen Durchmesser SolQtyAfracd^pidX***pi/squaremeter al A AF fracqtyd^ pi A. % Er ist SolQtyelfracRd^pirhoelRX*AX/reXm al ell fracRArhoel elF fracR qtyd^ pi re el lang. Sein Volumen ist folglich SolQtyVfracRd^pi^rhoelelX*AXcubicmeter al V ell A VF fracR qtyd^ pi^ re V. % Bei der angegebenen Dichte ist die Masse dann SolQtymfracrho Rd^pi^rhoelrcX*VXkg al m rho V mF fracrc R qtyd^ pi^ re m. % Auf der Erde ist sein Gewicht SolQtyFfracrho g Rd^pi^rhoelmX*gMnN al FG mg FF fracrc gM R qtyd^ pi^ re F. % FG FF FS
Contained in these collections
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Masse von elektrischem Leiter by TeXercises
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Widerstand by pw
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Widerstand eines Leiters by pw
| Title | Matched on |
|---|---|
| Baustelle | formula |
| Kupferdraht | formula |
| Kupfer vs. Aluminium | tags |
| Durchmesser von Aluminiumdraht | tags |
| Kufper- und Eisenkabel | tags |
Similar exercises (7)
| Title | Matched on |
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| Baustelle | formula |
| Kupferdraht | formula |
| Kupfer vs. Aluminium | tags |
| Durchmesser von Aluminiumdraht | tags |
| Kufper- und Eisenkabel | tags |
| Querschnitt von Telefonleitung | tags |
| Massenverhältnis zweier Leiter | tags |