Gleichstromlehre: Leistung und Widerstand 12
About points...
We associate a certain number of points with each exercise.
When you click an exercise into a collection, this number will be taken as points for the exercise, kind of "by default".
But once the exercise is on the collection, you can edit the number of points for the exercise in the collection independently, without any effect on "points by default" as represented by the number here.
That being said... How many "default points" should you associate with an exercise upon creation?
As with difficulty, there is no straight forward and generally accepted way.
But as a guideline, we tend to give as many points by default as there are mathematical steps to do in the exercise.
Again, very vague... But the number should kind of represent the "work" required.
When you click an exercise into a collection, this number will be taken as points for the exercise, kind of "by default".
But once the exercise is on the collection, you can edit the number of points for the exercise in the collection independently, without any effect on "points by default" as represented by the number here.
That being said... How many "default points" should you associate with an exercise upon creation?
As with difficulty, there is no straight forward and generally accepted way.
But as a guideline, we tend to give as many points by default as there are mathematical steps to do in the exercise.
Again, very vague... But the number should kind of represent the "work" required.
About difficulty...
We associate a certain difficulty with each exercise.
When you click an exercise into a collection, this number will be taken as difficulty for the exercise, kind of "by default".
But once the exercise is on the collection, you can edit its difficulty in the collection independently, without any effect on the "difficulty by default" here.
Why we use chess pieces? Well... we like chess, we like playing around with \(\LaTeX\)-fonts, we wanted symbols that need less space than six stars in a table-column... But in your layouts, you are of course free to indicate the difficulty of the exercise the way you want.
That being said... How "difficult" is an exercise? It depends on many factors, like what was being taught etc.
In physics exercises, we try to follow this pattern:
Level 1 - One formula (one you would find in a reference book) is enough to solve the exercise. Example exercise
Level 2 - Two formulas are needed, it's possible to compute an "in-between" solution, i.e. no algebraic equation needed. Example exercise
Level 3 - "Chain-computations" like on level 2, but 3+ calculations. Still, no equations, i.e. you are not forced to solve it in an algebraic manner. Example exercise
Level 4 - Exercise needs to be solved by algebraic equations, not possible to calculate numerical "in-between" results. Example exercise
Level 5 -
Level 6 -
When you click an exercise into a collection, this number will be taken as difficulty for the exercise, kind of "by default".
But once the exercise is on the collection, you can edit its difficulty in the collection independently, without any effect on the "difficulty by default" here.
Why we use chess pieces? Well... we like chess, we like playing around with \(\LaTeX\)-fonts, we wanted symbols that need less space than six stars in a table-column... But in your layouts, you are of course free to indicate the difficulty of the exercise the way you want.
That being said... How "difficult" is an exercise? It depends on many factors, like what was being taught etc.
In physics exercises, we try to follow this pattern:
Level 1 - One formula (one you would find in a reference book) is enough to solve the exercise. Example exercise
Level 2 - Two formulas are needed, it's possible to compute an "in-between" solution, i.e. no algebraic equation needed. Example exercise
Level 3 - "Chain-computations" like on level 2, but 3+ calculations. Still, no equations, i.e. you are not forced to solve it in an algebraic manner. Example exercise
Level 4 - Exercise needs to be solved by algebraic equations, not possible to calculate numerical "in-between" results. Example exercise
Level 5 -
Level 6 -
Question
Solution
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Video
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Don't forget to subscribe to our channel, like the videos and leave comments!
Exercise:
Gegeben sei der Temperaturkoeffizient alpha_ und der Widerstand R_ bei der Referenztemperatur vartheta_. Berechnen Sie den Temperaturkoeffizienten alpha_ und den Widerstand R_ bei der Referenztemperatur vartheta_. Nennen Sie die Annahme die Sie haben treffen müssen.
Solution:
% . Sept. Lie. Annahme: Der Widerstandswert sei eine lineare Funktion Polynom . Grades der Temperatur vartheta. * & R_+R_alpha_ vartheta-vartheta_ R_ +R_alpha_ vartheta-vartheta_ & R_+R_alpha_vartheta- R_alpha_vartheta_ R_ +R_alpha_vartheta -R_alpha_vartheta_ textquad Polynom . Grades: Koeffizientenvergleich &Rightarrow R_alpha_ R_alpha_ &Rightarrow R_- R_alpha_vartheta_ R_ -R_alpha_vartheta_ R_ -R_alpha_vartheta_ Rightarrow R_ R_ + R_alpha_ vartheta_-vartheta_ textquad klar! &Rightarrow alpha_ alpha_fracR_R_ fracalpha_+alpha_ vartheta_-vartheta_ * newpage
Gegeben sei der Temperaturkoeffizient alpha_ und der Widerstand R_ bei der Referenztemperatur vartheta_. Berechnen Sie den Temperaturkoeffizienten alpha_ und den Widerstand R_ bei der Referenztemperatur vartheta_. Nennen Sie die Annahme die Sie haben treffen müssen.
Solution:
% . Sept. Lie. Annahme: Der Widerstandswert sei eine lineare Funktion Polynom . Grades der Temperatur vartheta. * & R_+R_alpha_ vartheta-vartheta_ R_ +R_alpha_ vartheta-vartheta_ & R_+R_alpha_vartheta- R_alpha_vartheta_ R_ +R_alpha_vartheta -R_alpha_vartheta_ textquad Polynom . Grades: Koeffizientenvergleich &Rightarrow R_alpha_ R_alpha_ &Rightarrow R_- R_alpha_vartheta_ R_ -R_alpha_vartheta_ R_ -R_alpha_vartheta_ Rightarrow R_ R_ + R_alpha_ vartheta_-vartheta_ textquad klar! &Rightarrow alpha_ alpha_fracR_R_ fracalpha_+alpha_ vartheta_-vartheta_ * newpage
Meta Information
Exercise:
Gegeben sei der Temperaturkoeffizient alpha_ und der Widerstand R_ bei der Referenztemperatur vartheta_. Berechnen Sie den Temperaturkoeffizienten alpha_ und den Widerstand R_ bei der Referenztemperatur vartheta_. Nennen Sie die Annahme die Sie haben treffen müssen.
Solution:
% . Sept. Lie. Annahme: Der Widerstandswert sei eine lineare Funktion Polynom . Grades der Temperatur vartheta. * & R_+R_alpha_ vartheta-vartheta_ R_ +R_alpha_ vartheta-vartheta_ & R_+R_alpha_vartheta- R_alpha_vartheta_ R_ +R_alpha_vartheta -R_alpha_vartheta_ textquad Polynom . Grades: Koeffizientenvergleich &Rightarrow R_alpha_ R_alpha_ &Rightarrow R_- R_alpha_vartheta_ R_ -R_alpha_vartheta_ R_ -R_alpha_vartheta_ Rightarrow R_ R_ + R_alpha_ vartheta_-vartheta_ textquad klar! &Rightarrow alpha_ alpha_fracR_R_ fracalpha_+alpha_ vartheta_-vartheta_ * newpage
Gegeben sei der Temperaturkoeffizient alpha_ und der Widerstand R_ bei der Referenztemperatur vartheta_. Berechnen Sie den Temperaturkoeffizienten alpha_ und den Widerstand R_ bei der Referenztemperatur vartheta_. Nennen Sie die Annahme die Sie haben treffen müssen.
Solution:
% . Sept. Lie. Annahme: Der Widerstandswert sei eine lineare Funktion Polynom . Grades der Temperatur vartheta. * & R_+R_alpha_ vartheta-vartheta_ R_ +R_alpha_ vartheta-vartheta_ & R_+R_alpha_vartheta- R_alpha_vartheta_ R_ +R_alpha_vartheta -R_alpha_vartheta_ textquad Polynom . Grades: Koeffizientenvergleich &Rightarrow R_alpha_ R_alpha_ &Rightarrow R_- R_alpha_vartheta_ R_ -R_alpha_vartheta_ R_ -R_alpha_vartheta_ Rightarrow R_ R_ + R_alpha_ vartheta_-vartheta_ textquad klar! &Rightarrow alpha_ alpha_fracR_R_ fracalpha_+alpha_ vartheta_-vartheta_ * newpage
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