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The following quantities appear in the problem: Zeit \(t\) / elektrische Stromstärke \(I\) / elektrische Spannung \(U\) / Arbeit \(W\) / Energie \(E\) / Leistung \(P, \Phi\) / elektrischer Widerstand \(R\) /
The following formulas must be used to solve the exercise: \(P = UI \quad \) \(P = \dfrac{E}{t} = \dfrac{W}{t} = \dfrac{Q}{t} \quad \) \(U=RI \quad \)
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Exercise:
A heating coil generates a heat quantity of EO at a mains voltage of UO in tO. What is its resistance?

Solution:
NewQtyUbV NewQtytbs NewQtyQ.eJ % Geg U Ub t .min  tb Q .kJ Q % GesWiderstandR siohm % Die Leistung der Heizspirale beträgt SolQtyPfracQtQX/tbXW al P PF fracQtb P. % Der Widerstand ist folglich SolQtyRfracU^tQUbX**/PXohm al R fracU^P RF fracqtyUb^P R. % R RF RP
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Exercise:
A heating coil generates a heat quantity of EO at a mains voltage of UO in tO. What is its resistance?

Solution:
NewQtyUbV NewQtytbs NewQtyQ.eJ % Geg U Ub t .min  tb Q .kJ Q % GesWiderstandR siohm % Die Leistung der Heizspirale beträgt SolQtyPfracQtQX/tbXW al P PF fracQtb P. % Der Widerstand ist folglich SolQtyRfracU^tQUbX**/PXohm al R fracU^P RF fracqtyUb^P R. % R RF RP
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Topic
Tags
energy, physics, power, resistance
Difficulty
(2, default)
Points
2 (default)
Language
ENG (English)
Type
Calculative / Quantity
Decoration
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