Integral: Partialbruchzerlegung
About points...
We associate a certain number of points with each exercise.
When you click an exercise into a collection, this number will be taken as points for the exercise, kind of "by default".
But once the exercise is on the collection, you can edit the number of points for the exercise in the collection independently, without any effect on "points by default" as represented by the number here.
That being said... How many "default points" should you associate with an exercise upon creation?
As with difficulty, there is no straight forward and generally accepted way.
But as a guideline, we tend to give as many points by default as there are mathematical steps to do in the exercise.
Again, very vague... But the number should kind of represent the "work" required.
When you click an exercise into a collection, this number will be taken as points for the exercise, kind of "by default".
But once the exercise is on the collection, you can edit the number of points for the exercise in the collection independently, without any effect on "points by default" as represented by the number here.
That being said... How many "default points" should you associate with an exercise upon creation?
As with difficulty, there is no straight forward and generally accepted way.
But as a guideline, we tend to give as many points by default as there are mathematical steps to do in the exercise.
Again, very vague... But the number should kind of represent the "work" required.
About difficulty...
We associate a certain difficulty with each exercise.
When you click an exercise into a collection, this number will be taken as difficulty for the exercise, kind of "by default".
But once the exercise is on the collection, you can edit its difficulty in the collection independently, without any effect on the "difficulty by default" here.
Why we use chess pieces? Well... we like chess, we like playing around with \(\LaTeX\)-fonts, we wanted symbols that need less space than six stars in a table-column... But in your layouts, you are of course free to indicate the difficulty of the exercise the way you want.
That being said... How "difficult" is an exercise? It depends on many factors, like what was being taught etc.
In physics exercises, we try to follow this pattern:
Level 1 - One formula (one you would find in a reference book) is enough to solve the exercise. Example exercise
Level 2 - Two formulas are needed, it's possible to compute an "in-between" solution, i.e. no algebraic equation needed. Example exercise
Level 3 - "Chain-computations" like on level 2, but 3+ calculations. Still, no equations, i.e. you are not forced to solve it in an algebraic manner. Example exercise
Level 4 - Exercise needs to be solved by algebraic equations, not possible to calculate numerical "in-between" results. Example exercise
Level 5 -
Level 6 -
When you click an exercise into a collection, this number will be taken as difficulty for the exercise, kind of "by default".
But once the exercise is on the collection, you can edit its difficulty in the collection independently, without any effect on the "difficulty by default" here.
Why we use chess pieces? Well... we like chess, we like playing around with \(\LaTeX\)-fonts, we wanted symbols that need less space than six stars in a table-column... But in your layouts, you are of course free to indicate the difficulty of the exercise the way you want.
That being said... How "difficult" is an exercise? It depends on many factors, like what was being taught etc.
In physics exercises, we try to follow this pattern:
Level 1 - One formula (one you would find in a reference book) is enough to solve the exercise. Example exercise
Level 2 - Two formulas are needed, it's possible to compute an "in-between" solution, i.e. no algebraic equation needed. Example exercise
Level 3 - "Chain-computations" like on level 2, but 3+ calculations. Still, no equations, i.e. you are not forced to solve it in an algebraic manner. Example exercise
Level 4 - Exercise needs to be solved by algebraic equations, not possible to calculate numerical "in-between" results. Example exercise
Level 5 -
Level 6 -
Question
Solution
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\(\LaTeX\)
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Exercise:
displaystyle fxfracx^-x-. Berechne die Stammfunktion.
Solution:
bf Variante : Der Nenner kann wie folgt quadratisch ergänzt werden: fracx^-x- ddx fracsqrtx-fracsqrt^-frac ddx fracy^-frac fracsqrt ddy fracz^- fracsqrt fracsqrt ddz -frac operatornameatanhleftzright + c -frac operatornameatanhleft frac x-frac right + c bf Variante : Der Nenner dieser gebrochen rationalen Funktion hat die folgen Nullstellen: x_frac quad x_- Die Partialbruchzerlegung der Funktion ist damit sehr einfach: fracx^-x- fraca_x-frac + fraca_x+ fraca_x++a_leftx-fracrightleftx-fracright x+ fraca_x+a_ + a_x -fraca_leftx-fracright x+ Ein Koeffizientenvergleich führt auf folges Gleichungssystem: partialkv * arraylrcrcr x^:qquad&qquad & a_ &+& a_ x^:qquad&qquad & a_ &-& frac a_ array * tcblower Die Lösung ist a_frac sowie a_-frac. Das Integral kann somit wie folgt gelöst werden: Fx fracx^-x- ddx leftfracfracx-frac - fracfracx+ right ddx frac leftlnx--lnx+right+c frac fraclnx-lnx+ + c
displaystyle fxfracx^-x-. Berechne die Stammfunktion.
Solution:
bf Variante : Der Nenner kann wie folgt quadratisch ergänzt werden: fracx^-x- ddx fracsqrtx-fracsqrt^-frac ddx fracy^-frac fracsqrt ddy fracz^- fracsqrt fracsqrt ddz -frac operatornameatanhleftzright + c -frac operatornameatanhleft frac x-frac right + c bf Variante : Der Nenner dieser gebrochen rationalen Funktion hat die folgen Nullstellen: x_frac quad x_- Die Partialbruchzerlegung der Funktion ist damit sehr einfach: fracx^-x- fraca_x-frac + fraca_x+ fraca_x++a_leftx-fracrightleftx-fracright x+ fraca_x+a_ + a_x -fraca_leftx-fracright x+ Ein Koeffizientenvergleich führt auf folges Gleichungssystem: partialkv * arraylrcrcr x^:qquad&qquad & a_ &+& a_ x^:qquad&qquad & a_ &-& frac a_ array * tcblower Die Lösung ist a_frac sowie a_-frac. Das Integral kann somit wie folgt gelöst werden: Fx fracx^-x- ddx leftfracfracx-frac - fracfracx+ right ddx frac leftlnx--lnx+right+c frac fraclnx-lnx+ + c
Meta Information
Exercise:
displaystyle fxfracx^-x-. Berechne die Stammfunktion.
Solution:
bf Variante : Der Nenner kann wie folgt quadratisch ergänzt werden: fracx^-x- ddx fracsqrtx-fracsqrt^-frac ddx fracy^-frac fracsqrt ddy fracz^- fracsqrt fracsqrt ddz -frac operatornameatanhleftzright + c -frac operatornameatanhleft frac x-frac right + c bf Variante : Der Nenner dieser gebrochen rationalen Funktion hat die folgen Nullstellen: x_frac quad x_- Die Partialbruchzerlegung der Funktion ist damit sehr einfach: fracx^-x- fraca_x-frac + fraca_x+ fraca_x++a_leftx-fracrightleftx-fracright x+ fraca_x+a_ + a_x -fraca_leftx-fracright x+ Ein Koeffizientenvergleich führt auf folges Gleichungssystem: partialkv * arraylrcrcr x^:qquad&qquad & a_ &+& a_ x^:qquad&qquad & a_ &-& frac a_ array * tcblower Die Lösung ist a_frac sowie a_-frac. Das Integral kann somit wie folgt gelöst werden: Fx fracx^-x- ddx leftfracfracx-frac - fracfracx+ right ddx frac leftlnx--lnx+right+c frac fraclnx-lnx+ + c
displaystyle fxfracx^-x-. Berechne die Stammfunktion.
Solution:
bf Variante : Der Nenner kann wie folgt quadratisch ergänzt werden: fracx^-x- ddx fracsqrtx-fracsqrt^-frac ddx fracy^-frac fracsqrt ddy fracz^- fracsqrt fracsqrt ddz -frac operatornameatanhleftzright + c -frac operatornameatanhleft frac x-frac right + c bf Variante : Der Nenner dieser gebrochen rationalen Funktion hat die folgen Nullstellen: x_frac quad x_- Die Partialbruchzerlegung der Funktion ist damit sehr einfach: fracx^-x- fraca_x-frac + fraca_x+ fraca_x++a_leftx-fracrightleftx-fracright x+ fraca_x+a_ + a_x -fraca_leftx-fracright x+ Ein Koeffizientenvergleich führt auf folges Gleichungssystem: partialkv * arraylrcrcr x^:qquad&qquad & a_ &+& a_ x^:qquad&qquad & a_ &-& frac a_ array * tcblower Die Lösung ist a_frac sowie a_-frac. Das Integral kann somit wie folgt gelöst werden: Fx fracx^-x- ddx leftfracfracx-frac - fracfracx+ right ddx frac leftlnx--lnx+right+c frac fraclnx-lnx+ + c
Contained in these collections:
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Integralrechnung 7: Partialbruchzerlegung by TeXercises

