Isochor vs. isobar
About points...
We associate a certain number of points with each exercise.
When you click an exercise into a collection, this number will be taken as points for the exercise, kind of "by default".
But once the exercise is on the collection, you can edit the number of points for the exercise in the collection independently, without any effect on "points by default" as represented by the number here.
That being said... How many "default points" should you associate with an exercise upon creation?
As with difficulty, there is no straight forward and generally accepted way.
But as a guideline, we tend to give as many points by default as there are mathematical steps to do in the exercise.
Again, very vague... But the number should kind of represent the "work" required.
When you click an exercise into a collection, this number will be taken as points for the exercise, kind of "by default".
But once the exercise is on the collection, you can edit the number of points for the exercise in the collection independently, without any effect on "points by default" as represented by the number here.
That being said... How many "default points" should you associate with an exercise upon creation?
As with difficulty, there is no straight forward and generally accepted way.
But as a guideline, we tend to give as many points by default as there are mathematical steps to do in the exercise.
Again, very vague... But the number should kind of represent the "work" required.
About difficulty...
We associate a certain difficulty with each exercise.
When you click an exercise into a collection, this number will be taken as difficulty for the exercise, kind of "by default".
But once the exercise is on the collection, you can edit its difficulty in the collection independently, without any effect on the "difficulty by default" here.
Why we use chess pieces? Well... we like chess, we like playing around with \(\LaTeX\)-fonts, we wanted symbols that need less space than six stars in a table-column... But in your layouts, you are of course free to indicate the difficulty of the exercise the way you want.
That being said... How "difficult" is an exercise? It depends on many factors, like what was being taught etc.
In physics exercises, we try to follow this pattern:
Level 1 - One formula (one you would find in a reference book) is enough to solve the exercise. Example exercise
Level 2 - Two formulas are needed, it's possible to compute an "in-between" solution, i.e. no algebraic equation needed. Example exercise
Level 3 - "Chain-computations" like on level 2, but 3+ calculations. Still, no equations, i.e. you are not forced to solve it in an algebraic manner. Example exercise
Level 4 - Exercise needs to be solved by algebraic equations, not possible to calculate numerical "in-between" results. Example exercise
Level 5 -
Level 6 -
When you click an exercise into a collection, this number will be taken as difficulty for the exercise, kind of "by default".
But once the exercise is on the collection, you can edit its difficulty in the collection independently, without any effect on the "difficulty by default" here.
Why we use chess pieces? Well... we like chess, we like playing around with \(\LaTeX\)-fonts, we wanted symbols that need less space than six stars in a table-column... But in your layouts, you are of course free to indicate the difficulty of the exercise the way you want.
That being said... How "difficult" is an exercise? It depends on many factors, like what was being taught etc.
In physics exercises, we try to follow this pattern:
Level 1 - One formula (one you would find in a reference book) is enough to solve the exercise. Example exercise
Level 2 - Two formulas are needed, it's possible to compute an "in-between" solution, i.e. no algebraic equation needed. Example exercise
Level 3 - "Chain-computations" like on level 2, but 3+ calculations. Still, no equations, i.e. you are not forced to solve it in an algebraic manner. Example exercise
Level 4 - Exercise needs to be solved by algebraic equations, not possible to calculate numerical "in-between" results. Example exercise
Level 5 -
Level 6 -
Question
Solution
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\(\LaTeX\)
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Don't forget to subscribe to our channel, like the videos and leave comments!
Exercise:
Leiten Sie durch den Vergleich von einem isochoren und isobaren Prozess folge Beziehung her: C_p C_V + R wobei C_p die molare Wärmekapazität bei konstantem Druck und C_V bei konstantem Volumen sind sowie R die universelle Gaskonstante ist.
Solution:
Wir nen bei einem isobaren Prozess für den gilt mit dem . HS: Delta U Q - pDelta V quad Leftrightarrow quad Delta U + pDelta V Q. Da Delta U der Wärmemenge ohne Verrichtung der Arbeit entspricht ist die Delta U C_VnDelta T. Die rechte Seite entspricht der Wärmemenge mit Verrichtung der Arbeit welches wir als Q_p C_pnDelta T definieren. Damit erhalten wir: C_VnDelta T + pDelta V C_pnDelta T. Mit der Zustandsgleichung des idealen Gases pV nRT erhalten wir: C_VnDelta T + nRDelta T C_pnDelta T myRarrow C_V + R C_p.
Leiten Sie durch den Vergleich von einem isochoren und isobaren Prozess folge Beziehung her: C_p C_V + R wobei C_p die molare Wärmekapazität bei konstantem Druck und C_V bei konstantem Volumen sind sowie R die universelle Gaskonstante ist.
Solution:
Wir nen bei einem isobaren Prozess für den gilt mit dem . HS: Delta U Q - pDelta V quad Leftrightarrow quad Delta U + pDelta V Q. Da Delta U der Wärmemenge ohne Verrichtung der Arbeit entspricht ist die Delta U C_VnDelta T. Die rechte Seite entspricht der Wärmemenge mit Verrichtung der Arbeit welches wir als Q_p C_pnDelta T definieren. Damit erhalten wir: C_VnDelta T + pDelta V C_pnDelta T. Mit der Zustandsgleichung des idealen Gases pV nRT erhalten wir: C_VnDelta T + nRDelta T C_pnDelta T myRarrow C_V + R C_p.
Meta Information
Exercise:
Leiten Sie durch den Vergleich von einem isochoren und isobaren Prozess folge Beziehung her: C_p C_V + R wobei C_p die molare Wärmekapazität bei konstantem Druck und C_V bei konstantem Volumen sind sowie R die universelle Gaskonstante ist.
Solution:
Wir nen bei einem isobaren Prozess für den gilt mit dem . HS: Delta U Q - pDelta V quad Leftrightarrow quad Delta U + pDelta V Q. Da Delta U der Wärmemenge ohne Verrichtung der Arbeit entspricht ist die Delta U C_VnDelta T. Die rechte Seite entspricht der Wärmemenge mit Verrichtung der Arbeit welches wir als Q_p C_pnDelta T definieren. Damit erhalten wir: C_VnDelta T + pDelta V C_pnDelta T. Mit der Zustandsgleichung des idealen Gases pV nRT erhalten wir: C_VnDelta T + nRDelta T C_pnDelta T myRarrow C_V + R C_p.
Leiten Sie durch den Vergleich von einem isochoren und isobaren Prozess folge Beziehung her: C_p C_V + R wobei C_p die molare Wärmekapazität bei konstantem Druck und C_V bei konstantem Volumen sind sowie R die universelle Gaskonstante ist.
Solution:
Wir nen bei einem isobaren Prozess für den gilt mit dem . HS: Delta U Q - pDelta V quad Leftrightarrow quad Delta U + pDelta V Q. Da Delta U der Wärmemenge ohne Verrichtung der Arbeit entspricht ist die Delta U C_VnDelta T. Die rechte Seite entspricht der Wärmemenge mit Verrichtung der Arbeit welches wir als Q_p C_pnDelta T definieren. Damit erhalten wir: C_VnDelta T + pDelta V C_pnDelta T. Mit der Zustandsgleichung des idealen Gases pV nRT erhalten wir: C_VnDelta T + nRDelta T C_pnDelta T myRarrow C_V + R C_p.
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