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Kartonröhre -- Spannung

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We associate a certain number of points with each exercise.
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That being said... How many "default points" should you associate with an exercise upon creation?
As with difficulty, there is no straight forward and generally accepted way.
But as a guideline, we tend to give as many points by default as there are mathematical steps to do in the exercise.
Again, very vague... But the number should kind of represent the "work" required.

About difficulty...

We associate a certain difficulty with each exercise.
When you click an exercise into a collection, this number will be taken as difficulty for the exercise, kind of "by default".
But once the exercise is on the collection, you can edit its difficulty in the collection independently, without any effect on the "difficulty by default" here.
Why we use chess pieces? Well... we like chess, we like playing around with \(\LaTeX\)-fonts, we wanted symbols that need less space than six stars in a table-column... But in your layouts, you are of course free to indicate the difficulty of the exercise the way you want.

That being said... How "difficult" is an exercise? It depends on many factors, like what was being taught etc.
In physics exercises, we try to follow this pattern:

Level 1 - One formula (one you would find in a reference book) is enough to solve the exercise. Example exercise

Level 2 - Two formulas are needed, it's possible to compute an "in-between" solution, i.e. no algebraic equation needed. Example exercise

Level 3 - "Chain-computations" like on level 2, but 3+ calculations. Still, no equations, i.e. you are not forced to solve it in an algebraic manner. Example exercise

Level 4 - Exercise needs to be solved by algebraic equations, not possible to calculate numerical "in-between" results. Example exercise

Level 5 -
Level 6 -

Exercise

https://texercises.com/exercise/kartonrohre-spannung/

Question

Solution

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The following quantities appear in the problem: Länge \(\ell\) / elektrische Stromstärke \(I\) / Magnetische Flussdichte \(B\) / elektrische Spannung \(U\) / elektrischer Widerstand \(R\) / Fläche \(A\) / Anzahl \(N\) / spezifischer elektrischer Widerstand \(\rho\) /

The following formulas must be used to solve the exercise: \(B = \mu_0 \cdot \frac{N}{\ell} \cdot I \quad \) \(U=RI \quad \) \(R = R_1 + R_2 \quad \) \(R = \varrho \dfrac{\ell}{A} \quad \)

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Exercise:
Jemand wickelt L Konstantandraht FormelbuchRel von do Durchmesser auf eine lange dünne Kartonröhre so dass sich benachbarte Windungen berühren. Anschliess verbindet er die beiden Enden des Drahtes mit einer Batterie deren Innenwiderstand zu Ri angenommen werden soll Länge der Zuleitungen ist zu Vernachlässigen. Dadurch entsteht im Innern der Kartonröhre ein Magnetfeld der Stärke Bo. Berechne die Klemmenspannung der angeschlossenen Batterie.

Solution:
Geg ell L textKonstantan to sscrhoel Rel d do d sscRi Ri B Bo B % GesSpannungU siV % Die Windungsdichte der Spule beträgt al n fracNell fracNN d nf fracd n. Damit im Innern dieser Spule das angegebene Magnetfeld entsteht muss folger Strom fliessen: al I fracBmu_ n fracBmu_ nf If fracBmuo n I Der aufgewickelte Draht hat folgen Widerstand: al R sscrhoel fracellA sscrhoel fracellpi leftfracdright^ Rf RelfracRelLpiqtyd^ R In Serie geschaltet mit dem Innenwiderstand ergibt sich die folge Spannung: al U R + sscRi I Uf qtyR + Ri I U approx UII % U Uf &approx UII

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Tags	batterie, elektromagnetismus, innenwiderstand, kartonröhre, magnetfeld, physik, spule, uri
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Difficulty	(3, default)
Points	6 (default)
Language	(Deutsch)
Type	Calculative / Quantity
Creator	uz
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