Kiste hochziehen
About points...
We associate a certain number of points with each exercise.
When you click an exercise into a collection, this number will be taken as points for the exercise, kind of "by default".
But once the exercise is on the collection, you can edit the number of points for the exercise in the collection independently, without any effect on "points by default" as represented by the number here.
That being said... How many "default points" should you associate with an exercise upon creation?
As with difficulty, there is no straight forward and generally accepted way.
But as a guideline, we tend to give as many points by default as there are mathematical steps to do in the exercise.
Again, very vague... But the number should kind of represent the "work" required.
When you click an exercise into a collection, this number will be taken as points for the exercise, kind of "by default".
But once the exercise is on the collection, you can edit the number of points for the exercise in the collection independently, without any effect on "points by default" as represented by the number here.
That being said... How many "default points" should you associate with an exercise upon creation?
As with difficulty, there is no straight forward and generally accepted way.
But as a guideline, we tend to give as many points by default as there are mathematical steps to do in the exercise.
Again, very vague... But the number should kind of represent the "work" required.
About difficulty...
We associate a certain difficulty with each exercise.
When you click an exercise into a collection, this number will be taken as difficulty for the exercise, kind of "by default".
But once the exercise is on the collection, you can edit its difficulty in the collection independently, without any effect on the "difficulty by default" here.
Why we use chess pieces? Well... we like chess, we like playing around with \(\LaTeX\)-fonts, we wanted symbols that need less space than six stars in a table-column... But in your layouts, you are of course free to indicate the difficulty of the exercise the way you want.
That being said... How "difficult" is an exercise? It depends on many factors, like what was being taught etc.
In physics exercises, we try to follow this pattern:
Level 1 - One formula (one you would find in a reference book) is enough to solve the exercise. Example exercise
Level 2 - Two formulas are needed, it's possible to compute an "in-between" solution, i.e. no algebraic equation needed. Example exercise
Level 3 - "Chain-computations" like on level 2, but 3+ calculations. Still, no equations, i.e. you are not forced to solve it in an algebraic manner. Example exercise
Level 4 - Exercise needs to be solved by algebraic equations, not possible to calculate numerical "in-between" results. Example exercise
Level 5 -
Level 6 -
When you click an exercise into a collection, this number will be taken as difficulty for the exercise, kind of "by default".
But once the exercise is on the collection, you can edit its difficulty in the collection independently, without any effect on the "difficulty by default" here.
Why we use chess pieces? Well... we like chess, we like playing around with \(\LaTeX\)-fonts, we wanted symbols that need less space than six stars in a table-column... But in your layouts, you are of course free to indicate the difficulty of the exercise the way you want.
That being said... How "difficult" is an exercise? It depends on many factors, like what was being taught etc.
In physics exercises, we try to follow this pattern:
Level 1 - One formula (one you would find in a reference book) is enough to solve the exercise. Example exercise
Level 2 - Two formulas are needed, it's possible to compute an "in-between" solution, i.e. no algebraic equation needed. Example exercise
Level 3 - "Chain-computations" like on level 2, but 3+ calculations. Still, no equations, i.e. you are not forced to solve it in an algebraic manner. Example exercise
Level 4 - Exercise needs to be solved by algebraic equations, not possible to calculate numerical "in-between" results. Example exercise
Level 5 -
Level 6 -
Question
Solution
Short
Video
\(\LaTeX\)
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Exercise:
Bestimmen Sie für das folge System die Beschleunigung der Masse m g sofern an der Schnur mit einer konstanten Kraft von F .N gezogen wird. Der Winkel varphi grad und der Gleitreibungskoeffizient mu_G . sind gegeben. Vernachlässigen Sie die Masse sowie die Reibung der Rolle. center tikzpicturescale. pgfmathsetmacroh/*sqrt % Winkel draw thick arc ::; node at .. varphi; % Schnur draw line width.pt brown rotate around: . -- .; draw line width.pt brown .h+. -- .h-; % Kraft F draw blue very thick- .h- -- node right vec F .h- ; % Massen draw thick fillgray!rotate around: rectangle noderotate around: m .; % Rolle draw thick h -- +.h+.; draw thickfillwhite +.h+. circle mm; draw fillblack +.h+. circle .mm; % Dreieck draw very thick -- -- h -- ; tikzpicture center
Solution:
Da die Rolle die Kraft F nur umlenkt kann die Seilkraft auf die Masse m mit der Kraft F gleichgesetzt werden. Daher erhalten wir für die Kräfte auf die Masse m: F_resx ma myRarrow F_S - F_g_x - F_R ma und in y-Richtung: F_resy myRarrow F_N - F_g_y Daraus erhalten wir für die Normalkraft: F_N mgcosvarphi. Eingestetzt in die erste Gleichung erhalten wir mit F F_S: F - mgsinvarphi - mu_G mgcosvarphi ma myRarrow a fracFm - gsinvarphi + mu_Gcosvarphi apx .^.
Bestimmen Sie für das folge System die Beschleunigung der Masse m g sofern an der Schnur mit einer konstanten Kraft von F .N gezogen wird. Der Winkel varphi grad und der Gleitreibungskoeffizient mu_G . sind gegeben. Vernachlässigen Sie die Masse sowie die Reibung der Rolle. center tikzpicturescale. pgfmathsetmacroh/*sqrt % Winkel draw thick arc ::; node at .. varphi; % Schnur draw line width.pt brown rotate around: . -- .; draw line width.pt brown .h+. -- .h-; % Kraft F draw blue very thick- .h- -- node right vec F .h- ; % Massen draw thick fillgray!rotate around: rectangle noderotate around: m .; % Rolle draw thick h -- +.h+.; draw thickfillwhite +.h+. circle mm; draw fillblack +.h+. circle .mm; % Dreieck draw very thick -- -- h -- ; tikzpicture center
Solution:
Da die Rolle die Kraft F nur umlenkt kann die Seilkraft auf die Masse m mit der Kraft F gleichgesetzt werden. Daher erhalten wir für die Kräfte auf die Masse m: F_resx ma myRarrow F_S - F_g_x - F_R ma und in y-Richtung: F_resy myRarrow F_N - F_g_y Daraus erhalten wir für die Normalkraft: F_N mgcosvarphi. Eingestetzt in die erste Gleichung erhalten wir mit F F_S: F - mgsinvarphi - mu_G mgcosvarphi ma myRarrow a fracFm - gsinvarphi + mu_Gcosvarphi apx .^.
Meta Information
Exercise:
Bestimmen Sie für das folge System die Beschleunigung der Masse m g sofern an der Schnur mit einer konstanten Kraft von F .N gezogen wird. Der Winkel varphi grad und der Gleitreibungskoeffizient mu_G . sind gegeben. Vernachlässigen Sie die Masse sowie die Reibung der Rolle. center tikzpicturescale. pgfmathsetmacroh/*sqrt % Winkel draw thick arc ::; node at .. varphi; % Schnur draw line width.pt brown rotate around: . -- .; draw line width.pt brown .h+. -- .h-; % Kraft F draw blue very thick- .h- -- node right vec F .h- ; % Massen draw thick fillgray!rotate around: rectangle noderotate around: m .; % Rolle draw thick h -- +.h+.; draw thickfillwhite +.h+. circle mm; draw fillblack +.h+. circle .mm; % Dreieck draw very thick -- -- h -- ; tikzpicture center
Solution:
Da die Rolle die Kraft F nur umlenkt kann die Seilkraft auf die Masse m mit der Kraft F gleichgesetzt werden. Daher erhalten wir für die Kräfte auf die Masse m: F_resx ma myRarrow F_S - F_g_x - F_R ma und in y-Richtung: F_resy myRarrow F_N - F_g_y Daraus erhalten wir für die Normalkraft: F_N mgcosvarphi. Eingestetzt in die erste Gleichung erhalten wir mit F F_S: F - mgsinvarphi - mu_G mgcosvarphi ma myRarrow a fracFm - gsinvarphi + mu_Gcosvarphi apx .^.
Bestimmen Sie für das folge System die Beschleunigung der Masse m g sofern an der Schnur mit einer konstanten Kraft von F .N gezogen wird. Der Winkel varphi grad und der Gleitreibungskoeffizient mu_G . sind gegeben. Vernachlässigen Sie die Masse sowie die Reibung der Rolle. center tikzpicturescale. pgfmathsetmacroh/*sqrt % Winkel draw thick arc ::; node at .. varphi; % Schnur draw line width.pt brown rotate around: . -- .; draw line width.pt brown .h+. -- .h-; % Kraft F draw blue very thick- .h- -- node right vec F .h- ; % Massen draw thick fillgray!rotate around: rectangle noderotate around: m .; % Rolle draw thick h -- +.h+.; draw thickfillwhite +.h+. circle mm; draw fillblack +.h+. circle .mm; % Dreieck draw very thick -- -- h -- ; tikzpicture center
Solution:
Da die Rolle die Kraft F nur umlenkt kann die Seilkraft auf die Masse m mit der Kraft F gleichgesetzt werden. Daher erhalten wir für die Kräfte auf die Masse m: F_resx ma myRarrow F_S - F_g_x - F_R ma und in y-Richtung: F_resy myRarrow F_N - F_g_y Daraus erhalten wir für die Normalkraft: F_N mgcosvarphi. Eingestetzt in die erste Gleichung erhalten wir mit F F_S: F - mgsinvarphi - mu_G mgcosvarphi ma myRarrow a fracFm - gsinvarphi + mu_Gcosvarphi apx .^.
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