Lichtflecke auf Schirm
About points...
We associate a certain number of points with each exercise.
When you click an exercise into a collection, this number will be taken as points for the exercise, kind of "by default".
But once the exercise is on the collection, you can edit the number of points for the exercise in the collection independently, without any effect on "points by default" as represented by the number here.
That being said... How many "default points" should you associate with an exercise upon creation?
As with difficulty, there is no straight forward and generally accepted way.
But as a guideline, we tend to give as many points by default as there are mathematical steps to do in the exercise.
Again, very vague... But the number should kind of represent the "work" required.
When you click an exercise into a collection, this number will be taken as points for the exercise, kind of "by default".
But once the exercise is on the collection, you can edit the number of points for the exercise in the collection independently, without any effect on "points by default" as represented by the number here.
That being said... How many "default points" should you associate with an exercise upon creation?
As with difficulty, there is no straight forward and generally accepted way.
But as a guideline, we tend to give as many points by default as there are mathematical steps to do in the exercise.
Again, very vague... But the number should kind of represent the "work" required.
About difficulty...
We associate a certain difficulty with each exercise.
When you click an exercise into a collection, this number will be taken as difficulty for the exercise, kind of "by default".
But once the exercise is on the collection, you can edit its difficulty in the collection independently, without any effect on the "difficulty by default" here.
Why we use chess pieces? Well... we like chess, we like playing around with \(\LaTeX\)-fonts, we wanted symbols that need less space than six stars in a table-column... But in your layouts, you are of course free to indicate the difficulty of the exercise the way you want.
That being said... How "difficult" is an exercise? It depends on many factors, like what was being taught etc.
In physics exercises, we try to follow this pattern:
Level 1 - One formula (one you would find in a reference book) is enough to solve the exercise. Example exercise
Level 2 - Two formulas are needed, it's possible to compute an "in-between" solution, i.e. no algebraic equation needed. Example exercise
Level 3 - "Chain-computations" like on level 2, but 3+ calculations. Still, no equations, i.e. you are not forced to solve it in an algebraic manner. Example exercise
Level 4 - Exercise needs to be solved by algebraic equations, not possible to calculate numerical "in-between" results. Example exercise
Level 5 -
Level 6 -
When you click an exercise into a collection, this number will be taken as difficulty for the exercise, kind of "by default".
But once the exercise is on the collection, you can edit its difficulty in the collection independently, without any effect on the "difficulty by default" here.
Why we use chess pieces? Well... we like chess, we like playing around with \(\LaTeX\)-fonts, we wanted symbols that need less space than six stars in a table-column... But in your layouts, you are of course free to indicate the difficulty of the exercise the way you want.
That being said... How "difficult" is an exercise? It depends on many factors, like what was being taught etc.
In physics exercises, we try to follow this pattern:
Level 1 - One formula (one you would find in a reference book) is enough to solve the exercise. Example exercise
Level 2 - Two formulas are needed, it's possible to compute an "in-between" solution, i.e. no algebraic equation needed. Example exercise
Level 3 - "Chain-computations" like on level 2, but 3+ calculations. Still, no equations, i.e. you are not forced to solve it in an algebraic manner. Example exercise
Level 4 - Exercise needs to be solved by algebraic equations, not possible to calculate numerical "in-between" results. Example exercise
Level 5 -
Level 6 -
Question
Solution
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Video
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Exercise:
Die beiden punktförmigen Lichtquellen L_ und L_ beleuchten eine Lochble mit einem kreisrunden Loch. Auf dem Schirm erscheinen die Lichtflecke der beiden Lichtquellen. Welche der Figuren A bis E ersche auf dem Schirm? Begründe deine Antwort! center tikzpicture %draw ystep.xstep.colorgray! -. grid .; %fill circle .; % Lichtquellen L und L und Strahelngang vor Ble node fontsffamily at x; node fontsffamily at . x; node at . L_; node at .. L_; % Lochble und Strahlengang draw shorten -mmdensely dash dot --..; draw shorten -mmdensely dash dot --..; draw shorten -mm .--..; draw shorten -mm .--..; draw fillblack! --.------.--cycle; drawfillwhite .. ellipse . and .; node at .. Lochble; draw densely dash dot--..; draw densely dash dot--..; draw .--..; draw .--..; % Schirm scopescale.xshift.cmyshift-.cm draw thick --.------.--cycle; node at . . Schirm; scope tikzpicturevspacept tikzpicture % Bild A draw fillblack rectangle ; drawfillgray! . circle .; drawfillgray! . circle .; node at -. A; % Bild B scopexshift.cm draw fillblack rectangle ; drawfillgray! . circle .; drawfillgray! . circle .; scope clip . circle .; draw fillblack! . circle .; draw . circle .; scope node at -. B; scope % Bild C scopexshiftcm draw fillblack rectangle ; drawfillgray! . circle .; drawfillwhite . circle .; node at -. C; scope % Bild D scopexshift.cm draw fillblack rectangle ; drawfillwhite . circle .; drawfillwhite . circle .; scope clip . circle .; fill gray! . circle .; draw . circle .; draw . circle .; scope node at -. D; scope % Bild E scopexshiftcm draw fillblack rectangle ; drawfillgray! . circle .; drawfillgray! . circle .; scope clip . circle .; fill white . circle .; draw . circle .; draw . circle .; scope node at -. E; scope tikzpicture center
Solution:
Es muss bf Figur E sein! Die Lampe L_ ist weiter weg und bildet deshalb den kleineren Kreis als Lampe L_. Der kleinere Kreis muss also oben sein. Der Überschneidungsbereich der beiden Lampen ist am hellsten weil dort Licht von beiden Lampen den Schirm beleuchtet. Das ist nur bei Figur E der Fall. Hinweis: Der zweite Teil der Begründung ist zwing weil sonst auch B oder D in Frage kämen!
Die beiden punktförmigen Lichtquellen L_ und L_ beleuchten eine Lochble mit einem kreisrunden Loch. Auf dem Schirm erscheinen die Lichtflecke der beiden Lichtquellen. Welche der Figuren A bis E ersche auf dem Schirm? Begründe deine Antwort! center tikzpicture %draw ystep.xstep.colorgray! -. grid .; %fill circle .; % Lichtquellen L und L und Strahelngang vor Ble node fontsffamily at x; node fontsffamily at . x; node at . L_; node at .. L_; % Lochble und Strahlengang draw shorten -mmdensely dash dot --..; draw shorten -mmdensely dash dot --..; draw shorten -mm .--..; draw shorten -mm .--..; draw fillblack! --.------.--cycle; drawfillwhite .. ellipse . and .; node at .. Lochble; draw densely dash dot--..; draw densely dash dot--..; draw .--..; draw .--..; % Schirm scopescale.xshift.cmyshift-.cm draw thick --.------.--cycle; node at . . Schirm; scope tikzpicturevspacept tikzpicture % Bild A draw fillblack rectangle ; drawfillgray! . circle .; drawfillgray! . circle .; node at -. A; % Bild B scopexshift.cm draw fillblack rectangle ; drawfillgray! . circle .; drawfillgray! . circle .; scope clip . circle .; draw fillblack! . circle .; draw . circle .; scope node at -. B; scope % Bild C scopexshiftcm draw fillblack rectangle ; drawfillgray! . circle .; drawfillwhite . circle .; node at -. C; scope % Bild D scopexshift.cm draw fillblack rectangle ; drawfillwhite . circle .; drawfillwhite . circle .; scope clip . circle .; fill gray! . circle .; draw . circle .; draw . circle .; scope node at -. D; scope % Bild E scopexshiftcm draw fillblack rectangle ; drawfillgray! . circle .; drawfillgray! . circle .; scope clip . circle .; fill white . circle .; draw . circle .; draw . circle .; scope node at -. E; scope tikzpicture center
Solution:
Es muss bf Figur E sein! Die Lampe L_ ist weiter weg und bildet deshalb den kleineren Kreis als Lampe L_. Der kleinere Kreis muss also oben sein. Der Überschneidungsbereich der beiden Lampen ist am hellsten weil dort Licht von beiden Lampen den Schirm beleuchtet. Das ist nur bei Figur E der Fall. Hinweis: Der zweite Teil der Begründung ist zwing weil sonst auch B oder D in Frage kämen!
Meta Information
Exercise:
Die beiden punktförmigen Lichtquellen L_ und L_ beleuchten eine Lochble mit einem kreisrunden Loch. Auf dem Schirm erscheinen die Lichtflecke der beiden Lichtquellen. Welche der Figuren A bis E ersche auf dem Schirm? Begründe deine Antwort! center tikzpicture %draw ystep.xstep.colorgray! -. grid .; %fill circle .; % Lichtquellen L und L und Strahelngang vor Ble node fontsffamily at x; node fontsffamily at . x; node at . L_; node at .. L_; % Lochble und Strahlengang draw shorten -mmdensely dash dot --..; draw shorten -mmdensely dash dot --..; draw shorten -mm .--..; draw shorten -mm .--..; draw fillblack! --.------.--cycle; drawfillwhite .. ellipse . and .; node at .. Lochble; draw densely dash dot--..; draw densely dash dot--..; draw .--..; draw .--..; % Schirm scopescale.xshift.cmyshift-.cm draw thick --.------.--cycle; node at . . Schirm; scope tikzpicturevspacept tikzpicture % Bild A draw fillblack rectangle ; drawfillgray! . circle .; drawfillgray! . circle .; node at -. A; % Bild B scopexshift.cm draw fillblack rectangle ; drawfillgray! . circle .; drawfillgray! . circle .; scope clip . circle .; draw fillblack! . circle .; draw . circle .; scope node at -. B; scope % Bild C scopexshiftcm draw fillblack rectangle ; drawfillgray! . circle .; drawfillwhite . circle .; node at -. C; scope % Bild D scopexshift.cm draw fillblack rectangle ; drawfillwhite . circle .; drawfillwhite . circle .; scope clip . circle .; fill gray! . circle .; draw . circle .; draw . circle .; scope node at -. D; scope % Bild E scopexshiftcm draw fillblack rectangle ; drawfillgray! . circle .; drawfillgray! . circle .; scope clip . circle .; fill white . circle .; draw . circle .; draw . circle .; scope node at -. E; scope tikzpicture center
Solution:
Es muss bf Figur E sein! Die Lampe L_ ist weiter weg und bildet deshalb den kleineren Kreis als Lampe L_. Der kleinere Kreis muss also oben sein. Der Überschneidungsbereich der beiden Lampen ist am hellsten weil dort Licht von beiden Lampen den Schirm beleuchtet. Das ist nur bei Figur E der Fall. Hinweis: Der zweite Teil der Begründung ist zwing weil sonst auch B oder D in Frage kämen!
Die beiden punktförmigen Lichtquellen L_ und L_ beleuchten eine Lochble mit einem kreisrunden Loch. Auf dem Schirm erscheinen die Lichtflecke der beiden Lichtquellen. Welche der Figuren A bis E ersche auf dem Schirm? Begründe deine Antwort! center tikzpicture %draw ystep.xstep.colorgray! -. grid .; %fill circle .; % Lichtquellen L und L und Strahelngang vor Ble node fontsffamily at x; node fontsffamily at . x; node at . L_; node at .. L_; % Lochble und Strahlengang draw shorten -mmdensely dash dot --..; draw shorten -mmdensely dash dot --..; draw shorten -mm .--..; draw shorten -mm .--..; draw fillblack! --.------.--cycle; drawfillwhite .. ellipse . and .; node at .. Lochble; draw densely dash dot--..; draw densely dash dot--..; draw .--..; draw .--..; % Schirm scopescale.xshift.cmyshift-.cm draw thick --.------.--cycle; node at . . Schirm; scope tikzpicturevspacept tikzpicture % Bild A draw fillblack rectangle ; drawfillgray! . circle .; drawfillgray! . circle .; node at -. A; % Bild B scopexshift.cm draw fillblack rectangle ; drawfillgray! . circle .; drawfillgray! . circle .; scope clip . circle .; draw fillblack! . circle .; draw . circle .; scope node at -. B; scope % Bild C scopexshiftcm draw fillblack rectangle ; drawfillgray! . circle .; drawfillwhite . circle .; node at -. C; scope % Bild D scopexshift.cm draw fillblack rectangle ; drawfillwhite . circle .; drawfillwhite . circle .; scope clip . circle .; fill gray! . circle .; draw . circle .; draw . circle .; scope node at -. D; scope % Bild E scopexshiftcm draw fillblack rectangle ; drawfillgray! . circle .; drawfillgray! . circle .; scope clip . circle .; fill white . circle .; draw . circle .; draw . circle .; scope node at -. E; scope tikzpicture center
Solution:
Es muss bf Figur E sein! Die Lampe L_ ist weiter weg und bildet deshalb den kleineren Kreis als Lampe L_. Der kleinere Kreis muss also oben sein. Der Überschneidungsbereich der beiden Lampen ist am hellsten weil dort Licht von beiden Lampen den Schirm beleuchtet. Das ist nur bei Figur E der Fall. Hinweis: Der zweite Teil der Begründung ist zwing weil sonst auch B oder D in Frage kämen!
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