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https://texercises.com/exercise/magnetic-field-in-zurich/
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Exercise:
For the magnetic field in Zurich look up the horizontal component the inclination and declination angle. Calculate the vertical component and the magnitude of the magnetic field vector.

Solution:
The inclination angle can be linked to the horizontal and vertical components of the terrestrial magnetic field: tan I fracB_vB_h Solving for the vertical component yields B_v BvF Bh times tanInc resultBvP Using the same right triangle as before we find that fracB_hB cos I where B is the magnitude of the total magnetic field vector. Solving for B yields B BF fracBhcosInc resultBP Alternatively we can use the pythagorean theorem to calculate the magnitude of the field vector: B BbF sqrtBh^+BvP^ resultBbP
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Exercise:
For the magnetic field in Zurich look up the horizontal component the inclination and declination angle. Calculate the vertical component and the magnitude of the magnetic field vector.

Solution:
The inclination angle can be linked to the horizontal and vertical components of the terrestrial magnetic field: tan I fracB_vB_h Solving for the vertical component yields B_v BvF Bh times tanInc resultBvP Using the same right triangle as before we find that fracB_hB cos I where B is the magnitude of the total magnetic field vector. Solving for B yields B BF fracBhcosInc resultBP Alternatively we can use the pythagorean theorem to calculate the magnitude of the field vector: B BbF sqrtBh^+BvP^ resultBbP
Contained in these collections:

Attributes & Decorations
Branches
Magnetism
Tags
declination, earth, inclination, magnetic field
Content image
Difficulty
(1, default)
Points
0 (default)
Language
ENG (English)
Type
Calculative / Quantity
Decoration