Magnetic Force on Charged Particles
About points...
We associate a certain number of points with each exercise.
When you click an exercise into a collection, this number will be taken as points for the exercise, kind of "by default".
But once the exercise is on the collection, you can edit the number of points for the exercise in the collection independently, without any effect on "points by default" as represented by the number here.
That being said... How many "default points" should you associate with an exercise upon creation?
As with difficulty, there is no straight forward and generally accepted way.
But as a guideline, we tend to give as many points by default as there are mathematical steps to do in the exercise.
Again, very vague... But the number should kind of represent the "work" required.
When you click an exercise into a collection, this number will be taken as points for the exercise, kind of "by default".
But once the exercise is on the collection, you can edit the number of points for the exercise in the collection independently, without any effect on "points by default" as represented by the number here.
That being said... How many "default points" should you associate with an exercise upon creation?
As with difficulty, there is no straight forward and generally accepted way.
But as a guideline, we tend to give as many points by default as there are mathematical steps to do in the exercise.
Again, very vague... But the number should kind of represent the "work" required.
About difficulty...
We associate a certain difficulty with each exercise.
When you click an exercise into a collection, this number will be taken as difficulty for the exercise, kind of "by default".
But once the exercise is on the collection, you can edit its difficulty in the collection independently, without any effect on the "difficulty by default" here.
Why we use chess pieces? Well... we like chess, we like playing around with \(\LaTeX\)-fonts, we wanted symbols that need less space than six stars in a table-column... But in your layouts, you are of course free to indicate the difficulty of the exercise the way you want.
That being said... How "difficult" is an exercise? It depends on many factors, like what was being taught etc.
In physics exercises, we try to follow this pattern:
Level 1 - One formula (one you would find in a reference book) is enough to solve the exercise. Example exercise
Level 2 - Two formulas are needed, it's possible to compute an "in-between" solution, i.e. no algebraic equation needed. Example exercise
Level 3 - "Chain-computations" like on level 2, but 3+ calculations. Still, no equations, i.e. you are not forced to solve it in an algebraic manner. Example exercise
Level 4 - Exercise needs to be solved by algebraic equations, not possible to calculate numerical "in-between" results. Example exercise
Level 5 -
Level 6 -
When you click an exercise into a collection, this number will be taken as difficulty for the exercise, kind of "by default".
But once the exercise is on the collection, you can edit its difficulty in the collection independently, without any effect on the "difficulty by default" here.
Why we use chess pieces? Well... we like chess, we like playing around with \(\LaTeX\)-fonts, we wanted symbols that need less space than six stars in a table-column... But in your layouts, you are of course free to indicate the difficulty of the exercise the way you want.
That being said... How "difficult" is an exercise? It depends on many factors, like what was being taught etc.
In physics exercises, we try to follow this pattern:
Level 1 - One formula (one you would find in a reference book) is enough to solve the exercise. Example exercise
Level 2 - Two formulas are needed, it's possible to compute an "in-between" solution, i.e. no algebraic equation needed. Example exercise
Level 3 - "Chain-computations" like on level 2, but 3+ calculations. Still, no equations, i.e. you are not forced to solve it in an algebraic manner. Example exercise
Level 4 - Exercise needs to be solved by algebraic equations, not possible to calculate numerical "in-between" results. Example exercise
Level 5 -
Level 6 -
Question
Solution
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Exercise:
abcliste abc An electron with a speed of vaO moves perpicularly to the field lines of a magnetic field with strength BaO. Calculate the force acting on the electron. abc A proton moves at vbcO of the speed of light perpicularly to the field lines of a magnetic field. It experiences a force of FbO. Calculate the strength of the magnetic field. abc An alpha particle moves at an angle thcdegO with respect to the field lines of a magnetic field with strength BcO. It experiences a force FcO. Calculate the speed of the alpha particle and express the result as a fraction of the speed of light. abc A small styrofoam ball carrying a charge of qdO moves with a velocity of vdO through a magnetic field with strength BdO. It experiences as force FdO. Calculate the angle between the velocity vector and the magnetic field lines. abcliste
Solution:
abcliste abc The force is given by sscFB FaF ncetimes vatimes Ba Fa approx resultFaS abc The magnetic force is given by sscFB q v B Solving for the magnetic field leads to B BbF fracFbncetimes vbctimesncc Bb approx resultBbP- abc The force on a charged particle in a magnetic field is given by sscFB q v Bsheta Solving for the speed leads to v vcF fracFcqcetimesnce timesBctimes shcdeg vc vcc approx resultvccP abc The force on a charged particle in a magnetic field is given by sscFB q v Bsheta Solving for the angle theta leads to theta thradF arcsinleftfracFdqdtimes vdtimes Bdright thrad approx resultthdegP abcliste
abcliste abc An electron with a speed of vaO moves perpicularly to the field lines of a magnetic field with strength BaO. Calculate the force acting on the electron. abc A proton moves at vbcO of the speed of light perpicularly to the field lines of a magnetic field. It experiences a force of FbO. Calculate the strength of the magnetic field. abc An alpha particle moves at an angle thcdegO with respect to the field lines of a magnetic field with strength BcO. It experiences a force FcO. Calculate the speed of the alpha particle and express the result as a fraction of the speed of light. abc A small styrofoam ball carrying a charge of qdO moves with a velocity of vdO through a magnetic field with strength BdO. It experiences as force FdO. Calculate the angle between the velocity vector and the magnetic field lines. abcliste
Solution:
abcliste abc The force is given by sscFB FaF ncetimes vatimes Ba Fa approx resultFaS abc The magnetic force is given by sscFB q v B Solving for the magnetic field leads to B BbF fracFbncetimes vbctimesncc Bb approx resultBbP- abc The force on a charged particle in a magnetic field is given by sscFB q v Bsheta Solving for the speed leads to v vcF fracFcqcetimesnce timesBctimes shcdeg vc vcc approx resultvccP abc The force on a charged particle in a magnetic field is given by sscFB q v Bsheta Solving for the angle theta leads to theta thradF arcsinleftfracFdqdtimes vdtimes Bdright thrad approx resultthdegP abcliste
Meta Information
Exercise:
abcliste abc An electron with a speed of vaO moves perpicularly to the field lines of a magnetic field with strength BaO. Calculate the force acting on the electron. abc A proton moves at vbcO of the speed of light perpicularly to the field lines of a magnetic field. It experiences a force of FbO. Calculate the strength of the magnetic field. abc An alpha particle moves at an angle thcdegO with respect to the field lines of a magnetic field with strength BcO. It experiences a force FcO. Calculate the speed of the alpha particle and express the result as a fraction of the speed of light. abc A small styrofoam ball carrying a charge of qdO moves with a velocity of vdO through a magnetic field with strength BdO. It experiences as force FdO. Calculate the angle between the velocity vector and the magnetic field lines. abcliste
Solution:
abcliste abc The force is given by sscFB FaF ncetimes vatimes Ba Fa approx resultFaS abc The magnetic force is given by sscFB q v B Solving for the magnetic field leads to B BbF fracFbncetimes vbctimesncc Bb approx resultBbP- abc The force on a charged particle in a magnetic field is given by sscFB q v Bsheta Solving for the speed leads to v vcF fracFcqcetimesnce timesBctimes shcdeg vc vcc approx resultvccP abc The force on a charged particle in a magnetic field is given by sscFB q v Bsheta Solving for the angle theta leads to theta thradF arcsinleftfracFdqdtimes vdtimes Bdright thrad approx resultthdegP abcliste
abcliste abc An electron with a speed of vaO moves perpicularly to the field lines of a magnetic field with strength BaO. Calculate the force acting on the electron. abc A proton moves at vbcO of the speed of light perpicularly to the field lines of a magnetic field. It experiences a force of FbO. Calculate the strength of the magnetic field. abc An alpha particle moves at an angle thcdegO with respect to the field lines of a magnetic field with strength BcO. It experiences a force FcO. Calculate the speed of the alpha particle and express the result as a fraction of the speed of light. abc A small styrofoam ball carrying a charge of qdO moves with a velocity of vdO through a magnetic field with strength BdO. It experiences as force FdO. Calculate the angle between the velocity vector and the magnetic field lines. abcliste
Solution:
abcliste abc The force is given by sscFB FaF ncetimes vatimes Ba Fa approx resultFaS abc The magnetic force is given by sscFB q v B Solving for the magnetic field leads to B BbF fracFbncetimes vbctimesncc Bb approx resultBbP- abc The force on a charged particle in a magnetic field is given by sscFB q v Bsheta Solving for the speed leads to v vcF fracFcqcetimesnce timesBctimes shcdeg vc vcc approx resultvccP abc The force on a charged particle in a magnetic field is given by sscFB q v Bsheta Solving for the angle theta leads to theta thradF arcsinleftfracFdqdtimes vdtimes Bdright thrad approx resultthdegP abcliste
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