Mathematical Double Pendulum
About points...
We associate a certain number of points with each exercise.
When you click an exercise into a collection, this number will be taken as points for the exercise, kind of "by default".
But once the exercise is on the collection, you can edit the number of points for the exercise in the collection independently, without any effect on "points by default" as represented by the number here.
That being said... How many "default points" should you associate with an exercise upon creation?
As with difficulty, there is no straight forward and generally accepted way.
But as a guideline, we tend to give as many points by default as there are mathematical steps to do in the exercise.
Again, very vague... But the number should kind of represent the "work" required.
When you click an exercise into a collection, this number will be taken as points for the exercise, kind of "by default".
But once the exercise is on the collection, you can edit the number of points for the exercise in the collection independently, without any effect on "points by default" as represented by the number here.
That being said... How many "default points" should you associate with an exercise upon creation?
As with difficulty, there is no straight forward and generally accepted way.
But as a guideline, we tend to give as many points by default as there are mathematical steps to do in the exercise.
Again, very vague... But the number should kind of represent the "work" required.
About difficulty...
We associate a certain difficulty with each exercise.
When you click an exercise into a collection, this number will be taken as difficulty for the exercise, kind of "by default".
But once the exercise is on the collection, you can edit its difficulty in the collection independently, without any effect on the "difficulty by default" here.
Why we use chess pieces? Well... we like chess, we like playing around with \(\LaTeX\)-fonts, we wanted symbols that need less space than six stars in a table-column... But in your layouts, you are of course free to indicate the difficulty of the exercise the way you want.
That being said... How "difficult" is an exercise? It depends on many factors, like what was being taught etc.
In physics exercises, we try to follow this pattern:
Level 1 - One formula (one you would find in a reference book) is enough to solve the exercise. Example exercise
Level 2 - Two formulas are needed, it's possible to compute an "in-between" solution, i.e. no algebraic equation needed. Example exercise
Level 3 - "Chain-computations" like on level 2, but 3+ calculations. Still, no equations, i.e. you are not forced to solve it in an algebraic manner. Example exercise
Level 4 - Exercise needs to be solved by algebraic equations, not possible to calculate numerical "in-between" results. Example exercise
Level 5 -
Level 6 -
When you click an exercise into a collection, this number will be taken as difficulty for the exercise, kind of "by default".
But once the exercise is on the collection, you can edit its difficulty in the collection independently, without any effect on the "difficulty by default" here.
Why we use chess pieces? Well... we like chess, we like playing around with \(\LaTeX\)-fonts, we wanted symbols that need less space than six stars in a table-column... But in your layouts, you are of course free to indicate the difficulty of the exercise the way you want.
That being said... How "difficult" is an exercise? It depends on many factors, like what was being taught etc.
In physics exercises, we try to follow this pattern:
Level 1 - One formula (one you would find in a reference book) is enough to solve the exercise. Example exercise
Level 2 - Two formulas are needed, it's possible to compute an "in-between" solution, i.e. no algebraic equation needed. Example exercise
Level 3 - "Chain-computations" like on level 2, but 3+ calculations. Still, no equations, i.e. you are not forced to solve it in an algebraic manner. Example exercise
Level 4 - Exercise needs to be solved by algebraic equations, not possible to calculate numerical "in-between" results. Example exercise
Level 5 -
Level 6 -
Question
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Exercise:
A double pulum consists of two mathematical pula connected to each other see figure. center includegraphicswidth.mm#image_path:mathematical-doublpulum-# center For small angles uptheta_ and uptheta_ the differential s can be shown to be approximately ddot uptheta_ -+muomega_^uptheta_ + mulambdaomega_^uptheta_ ddot uptheta_ +mu/lambdaomega_^uptheta_ -+muomega_^uptheta_ with omega_^ fracgell_ omega_^ fracgell_ mu fracm_m_ lambda fracell_ell_ Derive the angular frequencies and eigenvectors for the following two cases: abcliste abc Equal masses and lengths: m_m_m and ell_ell_ell. abc Different masses and lengths: m_mub m_ mub m and ell_labell_labell. abcliste
Solution:
abcliste abc In this case we have omega^ omega_^omega_^fracgell mu lambda The simplified coefficient matrix is thus bf A pmatrix -omega^ & omega^ omega^ & -omega^ pmatrix -omega^ pmatrix & - - & pmatrix The trace and determinant are tau -tauaPomega^ Delta -detaPomega^ so the eigenvalues are lambda_sf -omega^fractauaP pm sqrttauaP^-timesdetaP -omega^solaPpmsqrtrootaP Longrightarrow omega_s sqrtfracgellsolaP-sqrtrootaP quad textrmslow mode omega_f sqrtfracgellsolaP+sqrtrootaP quad textrmfast mode The eigenvectors are hat x_s pmatrix sqrt pmatrix hat x_f pmatrix -sqrt pmatrix abc With mumubO lambdalabO omega_^omega^ and omega_^omega^/labO the coefficient matrix is bf A pmatrix -omega^ & omega^ omega^ & -omega^ pmatrix -omega^ pmatrix & - - & pmatrix The eigenvalues and angular frequencies of the normal modes are found to be lambda_sf -omega^solbPpmsqrtrootbP Longrightarrow omega_s sqrtfracgellsolbP-sqrtrootbP quad textrmslow mode omega_f sqrtfracgellsolbP+sqrtrootbP quad textrmfast mode The corresponding eigenvectors are hat x_s pmatrix sqrt- pmatrix hat x_f pmatrix sqrt+ - pmatrix abcliste
A double pulum consists of two mathematical pula connected to each other see figure. center includegraphicswidth.mm#image_path:mathematical-doublpulum-# center For small angles uptheta_ and uptheta_ the differential s can be shown to be approximately ddot uptheta_ -+muomega_^uptheta_ + mulambdaomega_^uptheta_ ddot uptheta_ +mu/lambdaomega_^uptheta_ -+muomega_^uptheta_ with omega_^ fracgell_ omega_^ fracgell_ mu fracm_m_ lambda fracell_ell_ Derive the angular frequencies and eigenvectors for the following two cases: abcliste abc Equal masses and lengths: m_m_m and ell_ell_ell. abc Different masses and lengths: m_mub m_ mub m and ell_labell_labell. abcliste
Solution:
abcliste abc In this case we have omega^ omega_^omega_^fracgell mu lambda The simplified coefficient matrix is thus bf A pmatrix -omega^ & omega^ omega^ & -omega^ pmatrix -omega^ pmatrix & - - & pmatrix The trace and determinant are tau -tauaPomega^ Delta -detaPomega^ so the eigenvalues are lambda_sf -omega^fractauaP pm sqrttauaP^-timesdetaP -omega^solaPpmsqrtrootaP Longrightarrow omega_s sqrtfracgellsolaP-sqrtrootaP quad textrmslow mode omega_f sqrtfracgellsolaP+sqrtrootaP quad textrmfast mode The eigenvectors are hat x_s pmatrix sqrt pmatrix hat x_f pmatrix -sqrt pmatrix abc With mumubO lambdalabO omega_^omega^ and omega_^omega^/labO the coefficient matrix is bf A pmatrix -omega^ & omega^ omega^ & -omega^ pmatrix -omega^ pmatrix & - - & pmatrix The eigenvalues and angular frequencies of the normal modes are found to be lambda_sf -omega^solbPpmsqrtrootbP Longrightarrow omega_s sqrtfracgellsolbP-sqrtrootbP quad textrmslow mode omega_f sqrtfracgellsolbP+sqrtrootbP quad textrmfast mode The corresponding eigenvectors are hat x_s pmatrix sqrt- pmatrix hat x_f pmatrix sqrt+ - pmatrix abcliste
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Exercise:
A double pulum consists of two mathematical pula connected to each other see figure. center includegraphicswidth.mm#image_path:mathematical-doublpulum-# center For small angles uptheta_ and uptheta_ the differential s can be shown to be approximately ddot uptheta_ -+muomega_^uptheta_ + mulambdaomega_^uptheta_ ddot uptheta_ +mu/lambdaomega_^uptheta_ -+muomega_^uptheta_ with omega_^ fracgell_ omega_^ fracgell_ mu fracm_m_ lambda fracell_ell_ Derive the angular frequencies and eigenvectors for the following two cases: abcliste abc Equal masses and lengths: m_m_m and ell_ell_ell. abc Different masses and lengths: m_mub m_ mub m and ell_labell_labell. abcliste
Solution:
abcliste abc In this case we have omega^ omega_^omega_^fracgell mu lambda The simplified coefficient matrix is thus bf A pmatrix -omega^ & omega^ omega^ & -omega^ pmatrix -omega^ pmatrix & - - & pmatrix The trace and determinant are tau -tauaPomega^ Delta -detaPomega^ so the eigenvalues are lambda_sf -omega^fractauaP pm sqrttauaP^-timesdetaP -omega^solaPpmsqrtrootaP Longrightarrow omega_s sqrtfracgellsolaP-sqrtrootaP quad textrmslow mode omega_f sqrtfracgellsolaP+sqrtrootaP quad textrmfast mode The eigenvectors are hat x_s pmatrix sqrt pmatrix hat x_f pmatrix -sqrt pmatrix abc With mumubO lambdalabO omega_^omega^ and omega_^omega^/labO the coefficient matrix is bf A pmatrix -omega^ & omega^ omega^ & -omega^ pmatrix -omega^ pmatrix & - - & pmatrix The eigenvalues and angular frequencies of the normal modes are found to be lambda_sf -omega^solbPpmsqrtrootbP Longrightarrow omega_s sqrtfracgellsolbP-sqrtrootbP quad textrmslow mode omega_f sqrtfracgellsolbP+sqrtrootbP quad textrmfast mode The corresponding eigenvectors are hat x_s pmatrix sqrt- pmatrix hat x_f pmatrix sqrt+ - pmatrix abcliste
A double pulum consists of two mathematical pula connected to each other see figure. center includegraphicswidth.mm#image_path:mathematical-doublpulum-# center For small angles uptheta_ and uptheta_ the differential s can be shown to be approximately ddot uptheta_ -+muomega_^uptheta_ + mulambdaomega_^uptheta_ ddot uptheta_ +mu/lambdaomega_^uptheta_ -+muomega_^uptheta_ with omega_^ fracgell_ omega_^ fracgell_ mu fracm_m_ lambda fracell_ell_ Derive the angular frequencies and eigenvectors for the following two cases: abcliste abc Equal masses and lengths: m_m_m and ell_ell_ell. abc Different masses and lengths: m_mub m_ mub m and ell_labell_labell. abcliste
Solution:
abcliste abc In this case we have omega^ omega_^omega_^fracgell mu lambda The simplified coefficient matrix is thus bf A pmatrix -omega^ & omega^ omega^ & -omega^ pmatrix -omega^ pmatrix & - - & pmatrix The trace and determinant are tau -tauaPomega^ Delta -detaPomega^ so the eigenvalues are lambda_sf -omega^fractauaP pm sqrttauaP^-timesdetaP -omega^solaPpmsqrtrootaP Longrightarrow omega_s sqrtfracgellsolaP-sqrtrootaP quad textrmslow mode omega_f sqrtfracgellsolaP+sqrtrootaP quad textrmfast mode The eigenvectors are hat x_s pmatrix sqrt pmatrix hat x_f pmatrix -sqrt pmatrix abc With mumubO lambdalabO omega_^omega^ and omega_^omega^/labO the coefficient matrix is bf A pmatrix -omega^ & omega^ omega^ & -omega^ pmatrix -omega^ pmatrix & - - & pmatrix The eigenvalues and angular frequencies of the normal modes are found to be lambda_sf -omega^solbPpmsqrtrootbP Longrightarrow omega_s sqrtfracgellsolbP-sqrtrootbP quad textrmslow mode omega_f sqrtfracgellsolbP+sqrtrootbP quad textrmfast mode The corresponding eigenvectors are hat x_s pmatrix sqrt- pmatrix hat x_f pmatrix sqrt+ - pmatrix abcliste
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