Milllikan Experiment
About points...
We associate a certain number of points with each exercise.
When you click an exercise into a collection, this number will be taken as points for the exercise, kind of "by default".
But once the exercise is on the collection, you can edit the number of points for the exercise in the collection independently, without any effect on "points by default" as represented by the number here.
That being said... How many "default points" should you associate with an exercise upon creation?
As with difficulty, there is no straight forward and generally accepted way.
But as a guideline, we tend to give as many points by default as there are mathematical steps to do in the exercise.
Again, very vague... But the number should kind of represent the "work" required.
When you click an exercise into a collection, this number will be taken as points for the exercise, kind of "by default".
But once the exercise is on the collection, you can edit the number of points for the exercise in the collection independently, without any effect on "points by default" as represented by the number here.
That being said... How many "default points" should you associate with an exercise upon creation?
As with difficulty, there is no straight forward and generally accepted way.
But as a guideline, we tend to give as many points by default as there are mathematical steps to do in the exercise.
Again, very vague... But the number should kind of represent the "work" required.
About difficulty...
We associate a certain difficulty with each exercise.
When you click an exercise into a collection, this number will be taken as difficulty for the exercise, kind of "by default".
But once the exercise is on the collection, you can edit its difficulty in the collection independently, without any effect on the "difficulty by default" here.
Why we use chess pieces? Well... we like chess, we like playing around with \(\LaTeX\)-fonts, we wanted symbols that need less space than six stars in a table-column... But in your layouts, you are of course free to indicate the difficulty of the exercise the way you want.
That being said... How "difficult" is an exercise? It depends on many factors, like what was being taught etc.
In physics exercises, we try to follow this pattern:
Level 1 - One formula (one you would find in a reference book) is enough to solve the exercise. Example exercise
Level 2 - Two formulas are needed, it's possible to compute an "in-between" solution, i.e. no algebraic equation needed. Example exercise
Level 3 - "Chain-computations" like on level 2, but 3+ calculations. Still, no equations, i.e. you are not forced to solve it in an algebraic manner. Example exercise
Level 4 - Exercise needs to be solved by algebraic equations, not possible to calculate numerical "in-between" results. Example exercise
Level 5 -
Level 6 -
When you click an exercise into a collection, this number will be taken as difficulty for the exercise, kind of "by default".
But once the exercise is on the collection, you can edit its difficulty in the collection independently, without any effect on the "difficulty by default" here.
Why we use chess pieces? Well... we like chess, we like playing around with \(\LaTeX\)-fonts, we wanted symbols that need less space than six stars in a table-column... But in your layouts, you are of course free to indicate the difficulty of the exercise the way you want.
That being said... How "difficult" is an exercise? It depends on many factors, like what was being taught etc.
In physics exercises, we try to follow this pattern:
Level 1 - One formula (one you would find in a reference book) is enough to solve the exercise. Example exercise
Level 2 - Two formulas are needed, it's possible to compute an "in-between" solution, i.e. no algebraic equation needed. Example exercise
Level 3 - "Chain-computations" like on level 2, but 3+ calculations. Still, no equations, i.e. you are not forced to solve it in an algebraic manner. Example exercise
Level 4 - Exercise needs to be solved by algebraic equations, not possible to calculate numerical "in-between" results. Example exercise
Level 5 -
Level 6 -
Question
Solution
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\(\LaTeX\)
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Exercise:
In order to determine the elementary charge Robert Millikan observed charged oil droplets in the electric field between two parallel plates. For each droplet he measured the terminal velocity v_ of the droplet descing in the absence of an electric field and the terminal velocity v_ while it was ascing in the ascing field. abcliste abc Show that the charge q of an oil droplet is given by the q E fracpi left frac eta right^/ left fracg rho_O-rho_A right^/ v_^/ left v_ + v_ where eta is the viscosity of air g the free fall acceleration and rho_O and rho_A are the densities of oil and air respectively. abc In his experiment Millikan used oil with a density rhOO. The density and viscosity of the air were rhAO and etAO respectively. The electric field was produced by applying a voltage dVO to plates with a distance dO. For a speciic droplet he measured velocities v_vaO and v_vbO. Calculate the charge of this oil drop and the ratio of its charge to the elementary charge. abcliste
Solution:
q qe
In order to determine the elementary charge Robert Millikan observed charged oil droplets in the electric field between two parallel plates. For each droplet he measured the terminal velocity v_ of the droplet descing in the absence of an electric field and the terminal velocity v_ while it was ascing in the ascing field. abcliste abc Show that the charge q of an oil droplet is given by the q E fracpi left frac eta right^/ left fracg rho_O-rho_A right^/ v_^/ left v_ + v_ where eta is the viscosity of air g the free fall acceleration and rho_O and rho_A are the densities of oil and air respectively. abc In his experiment Millikan used oil with a density rhOO. The density and viscosity of the air were rhAO and etAO respectively. The electric field was produced by applying a voltage dVO to plates with a distance dO. For a speciic droplet he measured velocities v_vaO and v_vbO. Calculate the charge of this oil drop and the ratio of its charge to the elementary charge. abcliste
Solution:
q qe
Meta Information
Exercise:
In order to determine the elementary charge Robert Millikan observed charged oil droplets in the electric field between two parallel plates. For each droplet he measured the terminal velocity v_ of the droplet descing in the absence of an electric field and the terminal velocity v_ while it was ascing in the ascing field. abcliste abc Show that the charge q of an oil droplet is given by the q E fracpi left frac eta right^/ left fracg rho_O-rho_A right^/ v_^/ left v_ + v_ where eta is the viscosity of air g the free fall acceleration and rho_O and rho_A are the densities of oil and air respectively. abc In his experiment Millikan used oil with a density rhOO. The density and viscosity of the air were rhAO and etAO respectively. The electric field was produced by applying a voltage dVO to plates with a distance dO. For a speciic droplet he measured velocities v_vaO and v_vbO. Calculate the charge of this oil drop and the ratio of its charge to the elementary charge. abcliste
Solution:
q qe
In order to determine the elementary charge Robert Millikan observed charged oil droplets in the electric field between two parallel plates. For each droplet he measured the terminal velocity v_ of the droplet descing in the absence of an electric field and the terminal velocity v_ while it was ascing in the ascing field. abcliste abc Show that the charge q of an oil droplet is given by the q E fracpi left frac eta right^/ left fracg rho_O-rho_A right^/ v_^/ left v_ + v_ where eta is the viscosity of air g the free fall acceleration and rho_O and rho_A are the densities of oil and air respectively. abc In his experiment Millikan used oil with a density rhOO. The density and viscosity of the air were rhAO and etAO respectively. The electric field was produced by applying a voltage dVO to plates with a distance dO. For a speciic droplet he measured velocities v_vaO and v_vbO. Calculate the charge of this oil drop and the ratio of its charge to the elementary charge. abcliste
Solution:
q qe
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