Mondgestein
About points...
We associate a certain number of points with each exercise.
When you click an exercise into a collection, this number will be taken as points for the exercise, kind of "by default".
But once the exercise is on the collection, you can edit the number of points for the exercise in the collection independently, without any effect on "points by default" as represented by the number here.
That being said... How many "default points" should you associate with an exercise upon creation?
As with difficulty, there is no straight forward and generally accepted way.
But as a guideline, we tend to give as many points by default as there are mathematical steps to do in the exercise.
Again, very vague... But the number should kind of represent the "work" required.
When you click an exercise into a collection, this number will be taken as points for the exercise, kind of "by default".
But once the exercise is on the collection, you can edit the number of points for the exercise in the collection independently, without any effect on "points by default" as represented by the number here.
That being said... How many "default points" should you associate with an exercise upon creation?
As with difficulty, there is no straight forward and generally accepted way.
But as a guideline, we tend to give as many points by default as there are mathematical steps to do in the exercise.
Again, very vague... But the number should kind of represent the "work" required.
About difficulty...
We associate a certain difficulty with each exercise.
When you click an exercise into a collection, this number will be taken as difficulty for the exercise, kind of "by default".
But once the exercise is on the collection, you can edit its difficulty in the collection independently, without any effect on the "difficulty by default" here.
Why we use chess pieces? Well... we like chess, we like playing around with \(\LaTeX\)-fonts, we wanted symbols that need less space than six stars in a table-column... But in your layouts, you are of course free to indicate the difficulty of the exercise the way you want.
That being said... How "difficult" is an exercise? It depends on many factors, like what was being taught etc.
In physics exercises, we try to follow this pattern:
Level 1 - One formula (one you would find in a reference book) is enough to solve the exercise. Example exercise
Level 2 - Two formulas are needed, it's possible to compute an "in-between" solution, i.e. no algebraic equation needed. Example exercise
Level 3 - "Chain-computations" like on level 2, but 3+ calculations. Still, no equations, i.e. you are not forced to solve it in an algebraic manner. Example exercise
Level 4 - Exercise needs to be solved by algebraic equations, not possible to calculate numerical "in-between" results. Example exercise
Level 5 -
Level 6 -
When you click an exercise into a collection, this number will be taken as difficulty for the exercise, kind of "by default".
But once the exercise is on the collection, you can edit its difficulty in the collection independently, without any effect on the "difficulty by default" here.
Why we use chess pieces? Well... we like chess, we like playing around with \(\LaTeX\)-fonts, we wanted symbols that need less space than six stars in a table-column... But in your layouts, you are of course free to indicate the difficulty of the exercise the way you want.
That being said... How "difficult" is an exercise? It depends on many factors, like what was being taught etc.
In physics exercises, we try to follow this pattern:
Level 1 - One formula (one you would find in a reference book) is enough to solve the exercise. Example exercise
Level 2 - Two formulas are needed, it's possible to compute an "in-between" solution, i.e. no algebraic equation needed. Example exercise
Level 3 - "Chain-computations" like on level 2, but 3+ calculations. Still, no equations, i.e. you are not forced to solve it in an algebraic manner. Example exercise
Level 4 - Exercise needs to be solved by algebraic equations, not possible to calculate numerical "in-between" results. Example exercise
Level 5 -
Level 6 -
Question
Solution
Short
Video
\(\LaTeX\)
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Visit our YouTube-Channel to see solutions to other exercises.
Don't forget to subscribe to our channel, like the videos and leave comments!
Exercise:
Ein Geologe wägt Mondgestein einmal normal und misst mO dann einmal komplett in Wasser eingetaucht und misst msO. Wie gross ist die Dichte des Gesteins?
Solution:
Geg m m textWasser Rightarrow rho R m' msO ms % GesDichterho' sikgpcm % Die Massifferenz zwischen den beiden Wägungen beträgt al Delta m DmF m - ms Dm. Das entspricht einer Verminderung der Gewichtskraft um al sscFA Delta m g FaF Dm ncg Fa was gerade der Auftriebskraft entsprechen muss. Das Volumen des Steins welches auch das verdrängte Volumen des Wasser ist ist folglich al V fracsscFArho g fracFaFrho g VF fracFaR ncg V. Daraus ergibt sich für die Dichte des Gesteins al rho' fracmV fracmVF RsF fracmV Rs approx RsS. % rho' RsF RsS
Ein Geologe wägt Mondgestein einmal normal und misst mO dann einmal komplett in Wasser eingetaucht und misst msO. Wie gross ist die Dichte des Gesteins?
Solution:
Geg m m textWasser Rightarrow rho R m' msO ms % GesDichterho' sikgpcm % Die Massifferenz zwischen den beiden Wägungen beträgt al Delta m DmF m - ms Dm. Das entspricht einer Verminderung der Gewichtskraft um al sscFA Delta m g FaF Dm ncg Fa was gerade der Auftriebskraft entsprechen muss. Das Volumen des Steins welches auch das verdrängte Volumen des Wasser ist ist folglich al V fracsscFArho g fracFaFrho g VF fracFaR ncg V. Daraus ergibt sich für die Dichte des Gesteins al rho' fracmV fracmVF RsF fracmV Rs approx RsS. % rho' RsF RsS
Meta Information
Exercise:
Ein Geologe wägt Mondgestein einmal normal und misst mO dann einmal komplett in Wasser eingetaucht und misst msO. Wie gross ist die Dichte des Gesteins?
Solution:
Geg m m textWasser Rightarrow rho R m' msO ms % GesDichterho' sikgpcm % Die Massifferenz zwischen den beiden Wägungen beträgt al Delta m DmF m - ms Dm. Das entspricht einer Verminderung der Gewichtskraft um al sscFA Delta m g FaF Dm ncg Fa was gerade der Auftriebskraft entsprechen muss. Das Volumen des Steins welches auch das verdrängte Volumen des Wasser ist ist folglich al V fracsscFArho g fracFaFrho g VF fracFaR ncg V. Daraus ergibt sich für die Dichte des Gesteins al rho' fracmV fracmVF RsF fracmV Rs approx RsS. % rho' RsF RsS
Ein Geologe wägt Mondgestein einmal normal und misst mO dann einmal komplett in Wasser eingetaucht und misst msO. Wie gross ist die Dichte des Gesteins?
Solution:
Geg m m textWasser Rightarrow rho R m' msO ms % GesDichterho' sikgpcm % Die Massifferenz zwischen den beiden Wägungen beträgt al Delta m DmF m - ms Dm. Das entspricht einer Verminderung der Gewichtskraft um al sscFA Delta m g FaF Dm ncg Fa was gerade der Auftriebskraft entsprechen muss. Das Volumen des Steins welches auch das verdrängte Volumen des Wasser ist ist folglich al V fracsscFArho g fracFaFrho g VF fracFaR ncg V. Daraus ergibt sich für die Dichte des Gesteins al rho' fracmV fracmVF RsF fracmV Rs approx RsS. % rho' RsF RsS
Contained in these collections
| Title | Creator | Matched on |
|---|---|---|
| Density of a Moon rock | uz | tags |
| Metal identity | uz | tags |
| Iceberg | uz | tags |
Physical Quantity
Dichte \(\varrho\)
a.k.a. Massendichte
Loading Wikipedia summary…
Verhältnis von Masse zu Volumen
\(\varrho = \dfrac{m}{V}\)
Unit
Kilogramm pro Kubikmeter (\(\rm \frac{kg}{m^3}\))
Metric
Coherent

