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Platin schmelzen

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We associate a certain number of points with each exercise.
When you click an exercise into a collection, this number will be taken as points for the exercise, kind of "by default".
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That being said... How many "default points" should you associate with an exercise upon creation?
As with difficulty, there is no straight forward and generally accepted way.
But as a guideline, we tend to give as many points by default as there are mathematical steps to do in the exercise.
Again, very vague... But the number should kind of represent the "work" required.

About difficulty...

We associate a certain difficulty with each exercise.
When you click an exercise into a collection, this number will be taken as difficulty for the exercise, kind of "by default".
But once the exercise is on the collection, you can edit its difficulty in the collection independently, without any effect on the "difficulty by default" here.
Why we use chess pieces? Well... we like chess, we like playing around with

\LaTeX

-fonts, we wanted symbols that need less space than six stars in a table-column... But in your layouts, you are of course free to indicate the difficulty of the exercise the way you want.

That being said... How "difficult" is an exercise? It depends on many factors, like what was being taught etc.
In physics exercises, we try to follow this pattern:

Level 1 - One formula (one you would find in a reference book) is enough to solve the exercise. Example exercise

Level 2 - Two formulas are needed, it's possible to compute an "in-between" solution, i.e. no algebraic equation needed. Example exercise

Level 3 - "Chain-computations" like on level 2, but 3+ calculations. Still, no equations, i.e. you are not forced to solve it in an algebraic manner. Example exercise

Level 4 - Exercise needs to be solved by algebraic equations, not possible to calculate numerical "in-between" results. Example exercise

Level 5 -
Level 6 -

Exercise

https://texercises.com/exercise/platin-schmelzen/

Question

Solution

Short

Video

\LaTeX

Need help? Yes, please!

The following quantities appear in the problem: Masse

m

/ Volumen

V

/ Wärme

Q

/ spezifische latente Wärme

L

/ Dichte

\varrho

The following formulas must be used to solve the exercise:

\varrho = \dfrac{m}{V} \quad

Q = m \cdot L_{\scriptscriptstyle\rm f} \quad

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Exercise:
Um .centiliter festes Platin bei der Schmelztemperatur vorlieg joulepergram zu schmelzen sind .kWh Wär-mener-gie nötig. Welche Dichte hat Platin gemäss diesen Daten?

Solution:
newqtyV.cubicmeter newqtyQ.kWh convtoJ.eQ newqtyLejouleperkilogram Geg V .centiliter V sscLf joulepergram L Q .kWh QC GesDichterhosikilogrampercubicmeter Mit der angegebenen Wärmeenergie kann man solqtymfracQsscLfQCn/Lnkg m fracQsscLf fracQsscLf m Platin schmelzen. Falls diese Masse gerade das angegebene Volumen einnimmt so beträgt die Dichte von Platin: solqtyRmn/Vnkilogrampercubicmeter rho fracmV fracfracQsscLfV fracQsscLf V fracmV R rho fracQsscLf V R

Meta Information

$\LaTeX$ -Code

Contained in these collections:

Latente Wärme und Dichte by TeXercises

4 | 9

Asked Quantity: Dichte

\varrho

in Kilogramm pro Kubikmeter

\rm \frac{kg}{m^3}

Attributes & Decorations

Tags	kalorik, platin, schmelzen, schmelztemperatur, schmelzwärme, thermodynamik, wärmelehre
Content image
Difficulty	(2, default)
Points	5 (default)
Language	(Deutsch)
Type	Calculative / Quantity
Creator	uz
Decoration
File
Link