Potential in Triangle
About points...
We associate a certain number of points with each exercise.
When you click an exercise into a collection, this number will be taken as points for the exercise, kind of "by default".
But once the exercise is on the collection, you can edit the number of points for the exercise in the collection independently, without any effect on "points by default" as represented by the number here.
That being said... How many "default points" should you associate with an exercise upon creation?
As with difficulty, there is no straight forward and generally accepted way.
But as a guideline, we tend to give as many points by default as there are mathematical steps to do in the exercise.
Again, very vague... But the number should kind of represent the "work" required.
When you click an exercise into a collection, this number will be taken as points for the exercise, kind of "by default".
But once the exercise is on the collection, you can edit the number of points for the exercise in the collection independently, without any effect on "points by default" as represented by the number here.
That being said... How many "default points" should you associate with an exercise upon creation?
As with difficulty, there is no straight forward and generally accepted way.
But as a guideline, we tend to give as many points by default as there are mathematical steps to do in the exercise.
Again, very vague... But the number should kind of represent the "work" required.
About difficulty...
We associate a certain difficulty with each exercise.
When you click an exercise into a collection, this number will be taken as difficulty for the exercise, kind of "by default".
But once the exercise is on the collection, you can edit its difficulty in the collection independently, without any effect on the "difficulty by default" here.
Why we use chess pieces? Well... we like chess, we like playing around with \(\LaTeX\)-fonts, we wanted symbols that need less space than six stars in a table-column... But in your layouts, you are of course free to indicate the difficulty of the exercise the way you want.
That being said... How "difficult" is an exercise? It depends on many factors, like what was being taught etc.
In physics exercises, we try to follow this pattern:
Level 1 - One formula (one you would find in a reference book) is enough to solve the exercise. Example exercise
Level 2 - Two formulas are needed, it's possible to compute an "in-between" solution, i.e. no algebraic equation needed. Example exercise
Level 3 - "Chain-computations" like on level 2, but 3+ calculations. Still, no equations, i.e. you are not forced to solve it in an algebraic manner. Example exercise
Level 4 - Exercise needs to be solved by algebraic equations, not possible to calculate numerical "in-between" results. Example exercise
Level 5 -
Level 6 -
When you click an exercise into a collection, this number will be taken as difficulty for the exercise, kind of "by default".
But once the exercise is on the collection, you can edit its difficulty in the collection independently, without any effect on the "difficulty by default" here.
Why we use chess pieces? Well... we like chess, we like playing around with \(\LaTeX\)-fonts, we wanted symbols that need less space than six stars in a table-column... But in your layouts, you are of course free to indicate the difficulty of the exercise the way you want.
That being said... How "difficult" is an exercise? It depends on many factors, like what was being taught etc.
In physics exercises, we try to follow this pattern:
Level 1 - One formula (one you would find in a reference book) is enough to solve the exercise. Example exercise
Level 2 - Two formulas are needed, it's possible to compute an "in-between" solution, i.e. no algebraic equation needed. Example exercise
Level 3 - "Chain-computations" like on level 2, but 3+ calculations. Still, no equations, i.e. you are not forced to solve it in an algebraic manner. Example exercise
Level 4 - Exercise needs to be solved by algebraic equations, not possible to calculate numerical "in-between" results. Example exercise
Level 5 -
Level 6 -
Question
Solution
Short
Video
\(\LaTeX\)
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Don't forget to subscribe to our channel, like the videos and leave comments!
Exercise:
A negative qaO and a positive qbO po charge are placed at two corners of an equilateral triangle with sides aO long. Calculate the potential difference between the third corner and the midpo of the triangle.
Solution:
The distance of the third corner C to each charge is equal to the side a of the equilateral triangle. The potential at C can therefore be written as phi_C phi_-a + phi_+a k_C fracq_Aa + k_C fracq_Ba frack_Ca q_A + q_B The distance r_M between a corner and the midpo of the triangle corresponds to two thirds of the height h: r_M frac h frac fracsqrt a fracsqrt a The potential at the midpo is therefore phi_M phi_-r_M + phi_+r_M frack_Cr_M q_A + q_B fracsqrt k_Ca q_A + q_B For the potential difference we find that Delta phi phi_C - phi_M k_Cq_A+q_Bleftfraca-fracsqrt aright VF nckctimesfrac-sqrtqa+qba resultVP
A negative qaO and a positive qbO po charge are placed at two corners of an equilateral triangle with sides aO long. Calculate the potential difference between the third corner and the midpo of the triangle.
Solution:
The distance of the third corner C to each charge is equal to the side a of the equilateral triangle. The potential at C can therefore be written as phi_C phi_-a + phi_+a k_C fracq_Aa + k_C fracq_Ba frack_Ca q_A + q_B The distance r_M between a corner and the midpo of the triangle corresponds to two thirds of the height h: r_M frac h frac fracsqrt a fracsqrt a The potential at the midpo is therefore phi_M phi_-r_M + phi_+r_M frack_Cr_M q_A + q_B fracsqrt k_Ca q_A + q_B For the potential difference we find that Delta phi phi_C - phi_M k_Cq_A+q_Bleftfraca-fracsqrt aright VF nckctimesfrac-sqrtqa+qba resultVP
Meta Information
Exercise:
A negative qaO and a positive qbO po charge are placed at two corners of an equilateral triangle with sides aO long. Calculate the potential difference between the third corner and the midpo of the triangle.
Solution:
The distance of the third corner C to each charge is equal to the side a of the equilateral triangle. The potential at C can therefore be written as phi_C phi_-a + phi_+a k_C fracq_Aa + k_C fracq_Ba frack_Ca q_A + q_B The distance r_M between a corner and the midpo of the triangle corresponds to two thirds of the height h: r_M frac h frac fracsqrt a fracsqrt a The potential at the midpo is therefore phi_M phi_-r_M + phi_+r_M frack_Cr_M q_A + q_B fracsqrt k_Ca q_A + q_B For the potential difference we find that Delta phi phi_C - phi_M k_Cq_A+q_Bleftfraca-fracsqrt aright VF nckctimesfrac-sqrtqa+qba resultVP
A negative qaO and a positive qbO po charge are placed at two corners of an equilateral triangle with sides aO long. Calculate the potential difference between the third corner and the midpo of the triangle.
Solution:
The distance of the third corner C to each charge is equal to the side a of the equilateral triangle. The potential at C can therefore be written as phi_C phi_-a + phi_+a k_C fracq_Aa + k_C fracq_Ba frack_Ca q_A + q_B The distance r_M between a corner and the midpo of the triangle corresponds to two thirds of the height h: r_M frac h frac fracsqrt a fracsqrt a The potential at the midpo is therefore phi_M phi_-r_M + phi_+r_M frack_Cr_M q_A + q_B fracsqrt k_Ca q_A + q_B For the potential difference we find that Delta phi phi_C - phi_M k_Cq_A+q_Bleftfraca-fracsqrt aright VF nckctimesfrac-sqrtqa+qba resultVP
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