Projectile Launcher
About points...
We associate a certain number of points with each exercise.
When you click an exercise into a collection, this number will be taken as points for the exercise, kind of "by default".
But once the exercise is on the collection, you can edit the number of points for the exercise in the collection independently, without any effect on "points by default" as represented by the number here.
That being said... How many "default points" should you associate with an exercise upon creation?
As with difficulty, there is no straight forward and generally accepted way.
But as a guideline, we tend to give as many points by default as there are mathematical steps to do in the exercise.
Again, very vague... But the number should kind of represent the "work" required.
When you click an exercise into a collection, this number will be taken as points for the exercise, kind of "by default".
But once the exercise is on the collection, you can edit the number of points for the exercise in the collection independently, without any effect on "points by default" as represented by the number here.
That being said... How many "default points" should you associate with an exercise upon creation?
As with difficulty, there is no straight forward and generally accepted way.
But as a guideline, we tend to give as many points by default as there are mathematical steps to do in the exercise.
Again, very vague... But the number should kind of represent the "work" required.
About difficulty...
We associate a certain difficulty with each exercise.
When you click an exercise into a collection, this number will be taken as difficulty for the exercise, kind of "by default".
But once the exercise is on the collection, you can edit its difficulty in the collection independently, without any effect on the "difficulty by default" here.
Why we use chess pieces? Well... we like chess, we like playing around with \(\LaTeX\)-fonts, we wanted symbols that need less space than six stars in a table-column... But in your layouts, you are of course free to indicate the difficulty of the exercise the way you want.
That being said... How "difficult" is an exercise? It depends on many factors, like what was being taught etc.
In physics exercises, we try to follow this pattern:
Level 1 - One formula (one you would find in a reference book) is enough to solve the exercise. Example exercise
Level 2 - Two formulas are needed, it's possible to compute an "in-between" solution, i.e. no algebraic equation needed. Example exercise
Level 3 - "Chain-computations" like on level 2, but 3+ calculations. Still, no equations, i.e. you are not forced to solve it in an algebraic manner. Example exercise
Level 4 - Exercise needs to be solved by algebraic equations, not possible to calculate numerical "in-between" results. Example exercise
Level 5 -
Level 6 -
When you click an exercise into a collection, this number will be taken as difficulty for the exercise, kind of "by default".
But once the exercise is on the collection, you can edit its difficulty in the collection independently, without any effect on the "difficulty by default" here.
Why we use chess pieces? Well... we like chess, we like playing around with \(\LaTeX\)-fonts, we wanted symbols that need less space than six stars in a table-column... But in your layouts, you are of course free to indicate the difficulty of the exercise the way you want.
That being said... How "difficult" is an exercise? It depends on many factors, like what was being taught etc.
In physics exercises, we try to follow this pattern:
Level 1 - One formula (one you would find in a reference book) is enough to solve the exercise. Example exercise
Level 2 - Two formulas are needed, it's possible to compute an "in-between" solution, i.e. no algebraic equation needed. Example exercise
Level 3 - "Chain-computations" like on level 2, but 3+ calculations. Still, no equations, i.e. you are not forced to solve it in an algebraic manner. Example exercise
Level 4 - Exercise needs to be solved by algebraic equations, not possible to calculate numerical "in-between" results. Example exercise
Level 5 -
Level 6 -
Question
Solution
Short
Video
\(\LaTeX\)
Need help? Yes, please!
The following quantities appear in the problem:
Länge \(\ell\) / Masse \(m\) / elektrische Stromstärke \(I\) / Magnetische Flussdichte \(B\) / Kraft \(F\) / Geschwindigkeit \(v\) / Strecke \(s\) / Beschleunigung \(a\) /
The following formulas must be used to solve the exercise:
\(s = \dfrac{v^2-v_0^2}{2a} \quad \) \(F = \ell I B \quad \) \(F = ma \quad \)
No explanation / solution video to this exercise has yet been created.
Visit our YouTube-Channel to see solutions to other exercises.
Don't forget to subscribe to our channel, like the videos and leave comments!
Visit our YouTube-Channel to see solutions to other exercises.
Don't forget to subscribe to our channel, like the videos and leave comments!
Exercise:
A sort of projectile launcher is built in the following way: A large current moves in a closed loop composed of fixed rails a power supply and a very light almost frictionless bar touching the rails. A magnetic field is perpicular to the plane of the circuit. If the bar has length cm a mass of .g and is placed in a field of .T what constant current flow is needed to accelerate the bar from rest to meterpersecond in a distance of .m? In what direction must the magnetic field po?
Solution:
newqtylocm newqtyllon m newqtymo.g newqtymmon kg newqtyB.T newqtyv newqtyst.m % boxGegeben ell lo l m mo m B B v v s st boxGesucht textElectric current flow IsiA The acceleration needed to reach the given velocity in the given distance is: solqtyafracv^svn**/*stns a af fracqtyv^ st a. The force required to accelerate an object with the given mass to the above calculated value is: solqtyFfracmv^smn*anN F ma Ff m a F. Hence the current in the wire must be: solqtyIfracmv^ell sBFn/Bn*lnA I fracFBell fracfracmv^sBell If fracFB l I. boxbox I If ITT
A sort of projectile launcher is built in the following way: A large current moves in a closed loop composed of fixed rails a power supply and a very light almost frictionless bar touching the rails. A magnetic field is perpicular to the plane of the circuit. If the bar has length cm a mass of .g and is placed in a field of .T what constant current flow is needed to accelerate the bar from rest to meterpersecond in a distance of .m? In what direction must the magnetic field po?
Solution:
newqtylocm newqtyllon m newqtymo.g newqtymmon kg newqtyB.T newqtyv newqtyst.m % boxGegeben ell lo l m mo m B B v v s st boxGesucht textElectric current flow IsiA The acceleration needed to reach the given velocity in the given distance is: solqtyafracv^svn**/*stns a af fracqtyv^ st a. The force required to accelerate an object with the given mass to the above calculated value is: solqtyFfracmv^smn*anN F ma Ff m a F. Hence the current in the wire must be: solqtyIfracmv^ell sBFn/Bn*lnA I fracFBell fracfracmv^sBell If fracFB l I. boxbox I If ITT
Meta Information
Exercise:
A sort of projectile launcher is built in the following way: A large current moves in a closed loop composed of fixed rails a power supply and a very light almost frictionless bar touching the rails. A magnetic field is perpicular to the plane of the circuit. If the bar has length cm a mass of .g and is placed in a field of .T what constant current flow is needed to accelerate the bar from rest to meterpersecond in a distance of .m? In what direction must the magnetic field po?
Solution:
newqtylocm newqtyllon m newqtymo.g newqtymmon kg newqtyB.T newqtyv newqtyst.m % boxGegeben ell lo l m mo m B B v v s st boxGesucht textElectric current flow IsiA The acceleration needed to reach the given velocity in the given distance is: solqtyafracv^svn**/*stns a af fracqtyv^ st a. The force required to accelerate an object with the given mass to the above calculated value is: solqtyFfracmv^smn*anN F ma Ff m a F. Hence the current in the wire must be: solqtyIfracmv^ell sBFn/Bn*lnA I fracFBell fracfracmv^sBell If fracFB l I. boxbox I If ITT
A sort of projectile launcher is built in the following way: A large current moves in a closed loop composed of fixed rails a power supply and a very light almost frictionless bar touching the rails. A magnetic field is perpicular to the plane of the circuit. If the bar has length cm a mass of .g and is placed in a field of .T what constant current flow is needed to accelerate the bar from rest to meterpersecond in a distance of .m? In what direction must the magnetic field po?
Solution:
newqtylocm newqtyllon m newqtymo.g newqtymmon kg newqtyB.T newqtyv newqtyst.m % boxGegeben ell lo l m mo m B B v v s st boxGesucht textElectric current flow IsiA The acceleration needed to reach the given velocity in the given distance is: solqtyafracv^svn**/*stns a af fracqtyv^ st a. The force required to accelerate an object with the given mass to the above calculated value is: solqtyFfracmv^smn*anN F ma Ff m a F. Hence the current in the wire must be: solqtyIfracmv^ell sBFn/Bn*lnA I fracFBell fracfracmv^sBell If fracFB l I. boxbox I If ITT
Contained in these collections:
-
Lorentzkraft auf Leiter by uz
-
Railgun by TeXercises
-
Biot-Savart-Kraft by pw
Asked Quantity:
elektrische Stromstärke \(I\)
in
Ampere \(\rm A\)
Physical Quantity
Unit