Punkt auf Strecke
About points...
We associate a certain number of points with each exercise.
When you click an exercise into a collection, this number will be taken as points for the exercise, kind of "by default".
But once the exercise is on the collection, you can edit the number of points for the exercise in the collection independently, without any effect on "points by default" as represented by the number here.
That being said... How many "default points" should you associate with an exercise upon creation?
As with difficulty, there is no straight forward and generally accepted way.
But as a guideline, we tend to give as many points by default as there are mathematical steps to do in the exercise.
Again, very vague... But the number should kind of represent the "work" required.
When you click an exercise into a collection, this number will be taken as points for the exercise, kind of "by default".
But once the exercise is on the collection, you can edit the number of points for the exercise in the collection independently, without any effect on "points by default" as represented by the number here.
That being said... How many "default points" should you associate with an exercise upon creation?
As with difficulty, there is no straight forward and generally accepted way.
But as a guideline, we tend to give as many points by default as there are mathematical steps to do in the exercise.
Again, very vague... But the number should kind of represent the "work" required.
About difficulty...
We associate a certain difficulty with each exercise.
When you click an exercise into a collection, this number will be taken as difficulty for the exercise, kind of "by default".
But once the exercise is on the collection, you can edit its difficulty in the collection independently, without any effect on the "difficulty by default" here.
Why we use chess pieces? Well... we like chess, we like playing around with \(\LaTeX\)-fonts, we wanted symbols that need less space than six stars in a table-column... But in your layouts, you are of course free to indicate the difficulty of the exercise the way you want.
That being said... How "difficult" is an exercise? It depends on many factors, like what was being taught etc.
In physics exercises, we try to follow this pattern:
Level 1 - One formula (one you would find in a reference book) is enough to solve the exercise. Example exercise
Level 2 - Two formulas are needed, it's possible to compute an "in-between" solution, i.e. no algebraic equation needed. Example exercise
Level 3 - "Chain-computations" like on level 2, but 3+ calculations. Still, no equations, i.e. you are not forced to solve it in an algebraic manner. Example exercise
Level 4 - Exercise needs to be solved by algebraic equations, not possible to calculate numerical "in-between" results. Example exercise
Level 5 -
Level 6 -
When you click an exercise into a collection, this number will be taken as difficulty for the exercise, kind of "by default".
But once the exercise is on the collection, you can edit its difficulty in the collection independently, without any effect on the "difficulty by default" here.
Why we use chess pieces? Well... we like chess, we like playing around with \(\LaTeX\)-fonts, we wanted symbols that need less space than six stars in a table-column... But in your layouts, you are of course free to indicate the difficulty of the exercise the way you want.
That being said... How "difficult" is an exercise? It depends on many factors, like what was being taught etc.
In physics exercises, we try to follow this pattern:
Level 1 - One formula (one you would find in a reference book) is enough to solve the exercise. Example exercise
Level 2 - Two formulas are needed, it's possible to compute an "in-between" solution, i.e. no algebraic equation needed. Example exercise
Level 3 - "Chain-computations" like on level 2, but 3+ calculations. Still, no equations, i.e. you are not forced to solve it in an algebraic manner. Example exercise
Level 4 - Exercise needs to be solved by algebraic equations, not possible to calculate numerical "in-between" results. Example exercise
Level 5 -
Level 6 -
Question
Solution
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Video
\(\LaTeX\)
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Exercise:
Das Quadrat ABCD ist gegeben. Auf der Strecke von A nach E liegt ein Punkt F derat dass die Dreiecke ABF un BCF flächengleich sind. Wie weit ist F von A entfernt ? BC und BAE ^circ. center tikzpicturescale. %draw rectangle ; coordinatelabelleft:A A at ; coordinatelabelright:B B at strecke; coordinatelabelleft:D D at strecke; coordinatelabelright:C C at streckestrecke; %coordinatelabelabove:E E at strecke*.strecke; coordinatelabelright:strecke strecke at streckestrecke*.; %drawgray thick -- strecke*.strecke; % AE- Strecke drawthick A--B--C--D--A; filldrawcolorred fillred!!white --. arc:winkel:.--cycle; nodeblack at .: alpha winkel^circ; draw -- ++winkel:length coordinate Ende; nodeabove right at Ende E; tikzpicture center
Solution:
Da die Dreiecke gleich lange Grundseiten AB bzw. BC haben müssen für gleich grosse Flächen auch die Höhen gleich lang sein. F ist also von AB genau so weit entfernt wie von BC und liegt somit auf der Diagonalen BD und damit im Schnittpunkt AE und BD Winkel gamma ausrechnen im Dreieck ABF: displaymath split gamma & - alpha - fracbeta gamma & fpeval- winkel - split displaymath Sinussatz: displaymath split fracAFfracbeta & fracABsingamma AF & fracAB*sinfracbetasingamma AF & fracAB*sinfracbetasin-alpha-fracbeta AF & round-modeplaces round-precisionfpevalstrecke*sin*pi/ / sin- winkel - *pi/ split displaymath center tikzpicturescale. coordinatelabelleft:A A at ; coordinatelabelright:B B at strecke; coordinatelabelleft:D D at strecke; coordinatelabelright:C C at streckestrecke; %coordinatelabelabove:E E at strecke*.strecke; coordinatelabelright:strecke strecke at streckestrecke*.; %drawgray thick -- strecke*.strecke; % AE- Strecke %drawgray thick A -- E; drawgray thick B -- D;% AE- Strecke drawthick A--B--C--D--A; % Zeichne einen langen Strahl von in Richtung ° draw -- ++winkel:length coordinate E; nodeabove right at E E; coordinate P at ersection of A--E and B--D; fillgreen P circle pt; % Kleiner Punkt am Schnittpunkt nodebelow right at P F; drawblue thick A--P; filldrawcolorred fillred!!white --. arc:winkel:.--cycle; nodeblack at .: alpha winkel^circ; tikzpicture center
Das Quadrat ABCD ist gegeben. Auf der Strecke von A nach E liegt ein Punkt F derat dass die Dreiecke ABF un BCF flächengleich sind. Wie weit ist F von A entfernt ? BC und BAE ^circ. center tikzpicturescale. %draw rectangle ; coordinatelabelleft:A A at ; coordinatelabelright:B B at strecke; coordinatelabelleft:D D at strecke; coordinatelabelright:C C at streckestrecke; %coordinatelabelabove:E E at strecke*.strecke; coordinatelabelright:strecke strecke at streckestrecke*.; %drawgray thick -- strecke*.strecke; % AE- Strecke drawthick A--B--C--D--A; filldrawcolorred fillred!!white --. arc:winkel:.--cycle; nodeblack at .: alpha winkel^circ; draw -- ++winkel:length coordinate Ende; nodeabove right at Ende E; tikzpicture center
Solution:
Da die Dreiecke gleich lange Grundseiten AB bzw. BC haben müssen für gleich grosse Flächen auch die Höhen gleich lang sein. F ist also von AB genau so weit entfernt wie von BC und liegt somit auf der Diagonalen BD und damit im Schnittpunkt AE und BD Winkel gamma ausrechnen im Dreieck ABF: displaymath split gamma & - alpha - fracbeta gamma & fpeval- winkel - split displaymath Sinussatz: displaymath split fracAFfracbeta & fracABsingamma AF & fracAB*sinfracbetasingamma AF & fracAB*sinfracbetasin-alpha-fracbeta AF & round-modeplaces round-precisionfpevalstrecke*sin*pi/ / sin- winkel - *pi/ split displaymath center tikzpicturescale. coordinatelabelleft:A A at ; coordinatelabelright:B B at strecke; coordinatelabelleft:D D at strecke; coordinatelabelright:C C at streckestrecke; %coordinatelabelabove:E E at strecke*.strecke; coordinatelabelright:strecke strecke at streckestrecke*.; %drawgray thick -- strecke*.strecke; % AE- Strecke %drawgray thick A -- E; drawgray thick B -- D;% AE- Strecke drawthick A--B--C--D--A; % Zeichne einen langen Strahl von in Richtung ° draw -- ++winkel:length coordinate E; nodeabove right at E E; coordinate P at ersection of A--E and B--D; fillgreen P circle pt; % Kleiner Punkt am Schnittpunkt nodebelow right at P F; drawblue thick A--P; filldrawcolorred fillred!!white --. arc:winkel:.--cycle; nodeblack at .: alpha winkel^circ; tikzpicture center
Meta Information
Exercise:
Das Quadrat ABCD ist gegeben. Auf der Strecke von A nach E liegt ein Punkt F derat dass die Dreiecke ABF un BCF flächengleich sind. Wie weit ist F von A entfernt ? BC und BAE ^circ. center tikzpicturescale. %draw rectangle ; coordinatelabelleft:A A at ; coordinatelabelright:B B at strecke; coordinatelabelleft:D D at strecke; coordinatelabelright:C C at streckestrecke; %coordinatelabelabove:E E at strecke*.strecke; coordinatelabelright:strecke strecke at streckestrecke*.; %drawgray thick -- strecke*.strecke; % AE- Strecke drawthick A--B--C--D--A; filldrawcolorred fillred!!white --. arc:winkel:.--cycle; nodeblack at .: alpha winkel^circ; draw -- ++winkel:length coordinate Ende; nodeabove right at Ende E; tikzpicture center
Solution:
Da die Dreiecke gleich lange Grundseiten AB bzw. BC haben müssen für gleich grosse Flächen auch die Höhen gleich lang sein. F ist also von AB genau so weit entfernt wie von BC und liegt somit auf der Diagonalen BD und damit im Schnittpunkt AE und BD Winkel gamma ausrechnen im Dreieck ABF: displaymath split gamma & - alpha - fracbeta gamma & fpeval- winkel - split displaymath Sinussatz: displaymath split fracAFfracbeta & fracABsingamma AF & fracAB*sinfracbetasingamma AF & fracAB*sinfracbetasin-alpha-fracbeta AF & round-modeplaces round-precisionfpevalstrecke*sin*pi/ / sin- winkel - *pi/ split displaymath center tikzpicturescale. coordinatelabelleft:A A at ; coordinatelabelright:B B at strecke; coordinatelabelleft:D D at strecke; coordinatelabelright:C C at streckestrecke; %coordinatelabelabove:E E at strecke*.strecke; coordinatelabelright:strecke strecke at streckestrecke*.; %drawgray thick -- strecke*.strecke; % AE- Strecke %drawgray thick A -- E; drawgray thick B -- D;% AE- Strecke drawthick A--B--C--D--A; % Zeichne einen langen Strahl von in Richtung ° draw -- ++winkel:length coordinate E; nodeabove right at E E; coordinate P at ersection of A--E and B--D; fillgreen P circle pt; % Kleiner Punkt am Schnittpunkt nodebelow right at P F; drawblue thick A--P; filldrawcolorred fillred!!white --. arc:winkel:.--cycle; nodeblack at .: alpha winkel^circ; tikzpicture center
Das Quadrat ABCD ist gegeben. Auf der Strecke von A nach E liegt ein Punkt F derat dass die Dreiecke ABF un BCF flächengleich sind. Wie weit ist F von A entfernt ? BC und BAE ^circ. center tikzpicturescale. %draw rectangle ; coordinatelabelleft:A A at ; coordinatelabelright:B B at strecke; coordinatelabelleft:D D at strecke; coordinatelabelright:C C at streckestrecke; %coordinatelabelabove:E E at strecke*.strecke; coordinatelabelright:strecke strecke at streckestrecke*.; %drawgray thick -- strecke*.strecke; % AE- Strecke drawthick A--B--C--D--A; filldrawcolorred fillred!!white --. arc:winkel:.--cycle; nodeblack at .: alpha winkel^circ; draw -- ++winkel:length coordinate Ende; nodeabove right at Ende E; tikzpicture center
Solution:
Da die Dreiecke gleich lange Grundseiten AB bzw. BC haben müssen für gleich grosse Flächen auch die Höhen gleich lang sein. F ist also von AB genau so weit entfernt wie von BC und liegt somit auf der Diagonalen BD und damit im Schnittpunkt AE und BD Winkel gamma ausrechnen im Dreieck ABF: displaymath split gamma & - alpha - fracbeta gamma & fpeval- winkel - split displaymath Sinussatz: displaymath split fracAFfracbeta & fracABsingamma AF & fracAB*sinfracbetasingamma AF & fracAB*sinfracbetasin-alpha-fracbeta AF & round-modeplaces round-precisionfpevalstrecke*sin*pi/ / sin- winkel - *pi/ split displaymath center tikzpicturescale. coordinatelabelleft:A A at ; coordinatelabelright:B B at strecke; coordinatelabelleft:D D at strecke; coordinatelabelright:C C at streckestrecke; %coordinatelabelabove:E E at strecke*.strecke; coordinatelabelright:strecke strecke at streckestrecke*.; %drawgray thick -- strecke*.strecke; % AE- Strecke %drawgray thick A -- E; drawgray thick B -- D;% AE- Strecke drawthick A--B--C--D--A; % Zeichne einen langen Strahl von in Richtung ° draw -- ++winkel:length coordinate E; nodeabove right at E E; coordinate P at ersection of A--E and B--D; fillgreen P circle pt; % Kleiner Punkt am Schnittpunkt nodebelow right at P F; drawblue thick A--P; filldrawcolorred fillred!!white --. arc:winkel:.--cycle; nodeblack at .: alpha winkel^circ; tikzpicture center
Contained in these collections
| Title | Creator | Matched on |
|---|---|---|
| Parallelogramm | uz | tags |
| Inkreisradius | uz | tags |
| Dreieck | uz | tags |
| Gleichschenkliges Trapes | uz | tags |
| Umkreisradius | uz | tags |
Similar exercises (11)
| Title | Creator | Matched on |
|---|---|---|
| Parallelogramm | uz | tags |
| Inkreisradius | uz | tags |
| Dreieck | uz | tags |
| Gleichschenkliges Trapes | uz | tags |
| Umkreisradius | uz | tags |
| Erdsatellit | uz | tags |
| Winkel | uz | tags |
| Winkelhalbierende | uz | tags |
| Sinus-, Cosinussatz II | rk | tags |
| Sinus-, Cosinussatz I | rk | tags |
| Höhe des Leuchtturms | rk | tags |

