Exercise
https://texercises.com/exercise/railroad-cars-collide/
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The following quantities appear in the problem: Impuls \(p\) /
The following formulas must be used to solve the exercise: \(\sum p_{\scriptscriptstyle\rm tot} \stackrel{!}{=} \sum p_{\scriptscriptstyle\rm tot}' \quad \)
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Exercise:
A .t railroad car mathcalA travelling at a speed of .kilometerperhour strikes an identical car mathcalB at rest. If the cars lock together as a result of the collision what is their common speed just afterwards?

Solution:
newqtym.ekg newqtyve % The linear momentum before and after the collision remains the same i.e. the linear momentum of one vehicle before the collision is the same as the linear momentum of both together after the collision. ImpulsSchritte PGleichungp_ p_' + p_' PGleichungm_v_ m_v_' + m_v_' PGleichungmv_ mv' + mv' AlgebraSchritte MGleichungmv' mv_ MGleichungv' fracv_ PHYSMATH Thus the their common speed is solqtywfracv_ven/ al v' wf fracve wTTTT wTTT. We can see that for two identical railroad cars this speed does not dep on their mass.
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\(\LaTeX\)-Code
Exercise:
A .t railroad car mathcalA travelling at a speed of .kilometerperhour strikes an identical car mathcalB at rest. If the cars lock together as a result of the collision what is their common speed just afterwards?

Solution:
newqtym.ekg newqtyve % The linear momentum before and after the collision remains the same i.e. the linear momentum of one vehicle before the collision is the same as the linear momentum of both together after the collision. ImpulsSchritte PGleichungp_ p_' + p_' PGleichungm_v_ m_v_' + m_v_' PGleichungmv_ mv' + mv' AlgebraSchritte MGleichungmv' mv_ MGleichungv' fracv_ PHYSMATH Thus the their common speed is solqtywfracv_ven/ al v' wf fracve wTTTT wTTT. We can see that for two identical railroad cars this speed does not dep on their mass.
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Momentum
Tags
combination, conservation, law, linear, mechanics, momentum, physics
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(4, default)
Points
2 (default)
Language
ENG (English)
Type
Calculative / Quantity
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