Ring of endomorphisms
About points...
We associate a certain number of points with each exercise.
When you click an exercise into a collection, this number will be taken as points for the exercise, kind of "by default".
But once the exercise is on the collection, you can edit the number of points for the exercise in the collection independently, without any effect on "points by default" as represented by the number here.
That being said... How many "default points" should you associate with an exercise upon creation?
As with difficulty, there is no straight forward and generally accepted way.
But as a guideline, we tend to give as many points by default as there are mathematical steps to do in the exercise.
Again, very vague... But the number should kind of represent the "work" required.
When you click an exercise into a collection, this number will be taken as points for the exercise, kind of "by default".
But once the exercise is on the collection, you can edit the number of points for the exercise in the collection independently, without any effect on "points by default" as represented by the number here.
That being said... How many "default points" should you associate with an exercise upon creation?
As with difficulty, there is no straight forward and generally accepted way.
But as a guideline, we tend to give as many points by default as there are mathematical steps to do in the exercise.
Again, very vague... But the number should kind of represent the "work" required.
About difficulty...
We associate a certain difficulty with each exercise.
When you click an exercise into a collection, this number will be taken as difficulty for the exercise, kind of "by default".
But once the exercise is on the collection, you can edit its difficulty in the collection independently, without any effect on the "difficulty by default" here.
Why we use chess pieces? Well... we like chess, we like playing around with \(\LaTeX\)-fonts, we wanted symbols that need less space than six stars in a table-column... But in your layouts, you are of course free to indicate the difficulty of the exercise the way you want.
That being said... How "difficult" is an exercise? It depends on many factors, like what was being taught etc.
In physics exercises, we try to follow this pattern:
Level 1 - One formula (one you would find in a reference book) is enough to solve the exercise. Example exercise
Level 2 - Two formulas are needed, it's possible to compute an "in-between" solution, i.e. no algebraic equation needed. Example exercise
Level 3 - "Chain-computations" like on level 2, but 3+ calculations. Still, no equations, i.e. you are not forced to solve it in an algebraic manner. Example exercise
Level 4 - Exercise needs to be solved by algebraic equations, not possible to calculate numerical "in-between" results. Example exercise
Level 5 -
Level 6 -
When you click an exercise into a collection, this number will be taken as difficulty for the exercise, kind of "by default".
But once the exercise is on the collection, you can edit its difficulty in the collection independently, without any effect on the "difficulty by default" here.
Why we use chess pieces? Well... we like chess, we like playing around with \(\LaTeX\)-fonts, we wanted symbols that need less space than six stars in a table-column... But in your layouts, you are of course free to indicate the difficulty of the exercise the way you want.
That being said... How "difficult" is an exercise? It depends on many factors, like what was being taught etc.
In physics exercises, we try to follow this pattern:
Level 1 - One formula (one you would find in a reference book) is enough to solve the exercise. Example exercise
Level 2 - Two formulas are needed, it's possible to compute an "in-between" solution, i.e. no algebraic equation needed. Example exercise
Level 3 - "Chain-computations" like on level 2, but 3+ calculations. Still, no equations, i.e. you are not forced to solve it in an algebraic manner. Example exercise
Level 4 - Exercise needs to be solved by algebraic equations, not possible to calculate numerical "in-between" results. Example exercise
Level 5 -
Level 6 -
Question
Solution
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\(\LaTeX\)
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Exercise:
Let V be a vector space over K. Then textEndV:textHomVV is a ring with a unity. This ring is in general not commutative. The multiplication product in textEndV is given by composition T_ T_ : T_circ T_ forall T_ T_in textHomVV. The unity is textid_V. Moreover if V is finite dimensional and textdimVn and mathcalBv_...v_n is basis for V then Psi_mathcalB^mathcalB: textHomVVlongrightarrow M_ntimes nK is an isomorphism of rings.
Solution:
Proof. The multiplication T_ T_ : T_circ T_ is associative T_ T_ T_T_circ T_circ T_T_circ T_circ T_T_ T_ T_. also T textid_V Tcirc textid_V T textid_V T textid_Vcirc T T. T T_+T_Tcirc T_+T_Tcirc T_ + Tcirc T_ etc. Now if V is finite dimensional and mathcalB is a basis for V then Psi_mathcalB^mathcalBT_circ T_T_circ T__mathcalB^mathcalBT__mathcalB^mathcalB T__mathcalB^mathcalB Psi_mathcalB^mathcalBT_ Psi_mathcalB^mathcalBT_.
Let V be a vector space over K. Then textEndV:textHomVV is a ring with a unity. This ring is in general not commutative. The multiplication product in textEndV is given by composition T_ T_ : T_circ T_ forall T_ T_in textHomVV. The unity is textid_V. Moreover if V is finite dimensional and textdimVn and mathcalBv_...v_n is basis for V then Psi_mathcalB^mathcalB: textHomVVlongrightarrow M_ntimes nK is an isomorphism of rings.
Solution:
Proof. The multiplication T_ T_ : T_circ T_ is associative T_ T_ T_T_circ T_circ T_T_circ T_circ T_T_ T_ T_. also T textid_V Tcirc textid_V T textid_V T textid_Vcirc T T. T T_+T_Tcirc T_+T_Tcirc T_ + Tcirc T_ etc. Now if V is finite dimensional and mathcalB is a basis for V then Psi_mathcalB^mathcalBT_circ T_T_circ T__mathcalB^mathcalBT__mathcalB^mathcalB T__mathcalB^mathcalB Psi_mathcalB^mathcalBT_ Psi_mathcalB^mathcalBT_.
Meta Information
Exercise:
Let V be a vector space over K. Then textEndV:textHomVV is a ring with a unity. This ring is in general not commutative. The multiplication product in textEndV is given by composition T_ T_ : T_circ T_ forall T_ T_in textHomVV. The unity is textid_V. Moreover if V is finite dimensional and textdimVn and mathcalBv_...v_n is basis for V then Psi_mathcalB^mathcalB: textHomVVlongrightarrow M_ntimes nK is an isomorphism of rings.
Solution:
Proof. The multiplication T_ T_ : T_circ T_ is associative T_ T_ T_T_circ T_circ T_T_circ T_circ T_T_ T_ T_. also T textid_V Tcirc textid_V T textid_V T textid_Vcirc T T. T T_+T_Tcirc T_+T_Tcirc T_ + Tcirc T_ etc. Now if V is finite dimensional and mathcalB is a basis for V then Psi_mathcalB^mathcalBT_circ T_T_circ T__mathcalB^mathcalBT__mathcalB^mathcalB T__mathcalB^mathcalB Psi_mathcalB^mathcalBT_ Psi_mathcalB^mathcalBT_.
Let V be a vector space over K. Then textEndV:textHomVV is a ring with a unity. This ring is in general not commutative. The multiplication product in textEndV is given by composition T_ T_ : T_circ T_ forall T_ T_in textHomVV. The unity is textid_V. Moreover if V is finite dimensional and textdimVn and mathcalBv_...v_n is basis for V then Psi_mathcalB^mathcalB: textHomVVlongrightarrow M_ntimes nK is an isomorphism of rings.
Solution:
Proof. The multiplication T_ T_ : T_circ T_ is associative T_ T_ T_T_circ T_circ T_T_circ T_circ T_T_ T_ T_. also T textid_V Tcirc textid_V T textid_V T textid_Vcirc T T. T T_+T_Tcirc T_+T_Tcirc T_ + Tcirc T_ etc. Now if V is finite dimensional and mathcalB is a basis for V then Psi_mathcalB^mathcalBT_circ T_T_circ T__mathcalB^mathcalBT__mathcalB^mathcalB T__mathcalB^mathcalB Psi_mathcalB^mathcalBT_ Psi_mathcalB^mathcalBT_.
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