Rohranpassung
About points...
We associate a certain number of points with each exercise.
When you click an exercise into a collection, this number will be taken as points for the exercise, kind of "by default".
But once the exercise is on the collection, you can edit the number of points for the exercise in the collection independently, without any effect on "points by default" as represented by the number here.
That being said... How many "default points" should you associate with an exercise upon creation?
As with difficulty, there is no straight forward and generally accepted way.
But as a guideline, we tend to give as many points by default as there are mathematical steps to do in the exercise.
Again, very vague... But the number should kind of represent the "work" required.
When you click an exercise into a collection, this number will be taken as points for the exercise, kind of "by default".
But once the exercise is on the collection, you can edit the number of points for the exercise in the collection independently, without any effect on "points by default" as represented by the number here.
That being said... How many "default points" should you associate with an exercise upon creation?
As with difficulty, there is no straight forward and generally accepted way.
But as a guideline, we tend to give as many points by default as there are mathematical steps to do in the exercise.
Again, very vague... But the number should kind of represent the "work" required.
About difficulty...
We associate a certain difficulty with each exercise.
When you click an exercise into a collection, this number will be taken as difficulty for the exercise, kind of "by default".
But once the exercise is on the collection, you can edit its difficulty in the collection independently, without any effect on the "difficulty by default" here.
Why we use chess pieces? Well... we like chess, we like playing around with \(\LaTeX\)-fonts, we wanted symbols that need less space than six stars in a table-column... But in your layouts, you are of course free to indicate the difficulty of the exercise the way you want.
That being said... How "difficult" is an exercise? It depends on many factors, like what was being taught etc.
In physics exercises, we try to follow this pattern:
Level 1 - One formula (one you would find in a reference book) is enough to solve the exercise. Example exercise
Level 2 - Two formulas are needed, it's possible to compute an "in-between" solution, i.e. no algebraic equation needed. Example exercise
Level 3 - "Chain-computations" like on level 2, but 3+ calculations. Still, no equations, i.e. you are not forced to solve it in an algebraic manner. Example exercise
Level 4 - Exercise needs to be solved by algebraic equations, not possible to calculate numerical "in-between" results. Example exercise
Level 5 -
Level 6 -
When you click an exercise into a collection, this number will be taken as difficulty for the exercise, kind of "by default".
But once the exercise is on the collection, you can edit its difficulty in the collection independently, without any effect on the "difficulty by default" here.
Why we use chess pieces? Well... we like chess, we like playing around with \(\LaTeX\)-fonts, we wanted symbols that need less space than six stars in a table-column... But in your layouts, you are of course free to indicate the difficulty of the exercise the way you want.
That being said... How "difficult" is an exercise? It depends on many factors, like what was being taught etc.
In physics exercises, we try to follow this pattern:
Level 1 - One formula (one you would find in a reference book) is enough to solve the exercise. Example exercise
Level 2 - Two formulas are needed, it's possible to compute an "in-between" solution, i.e. no algebraic equation needed. Example exercise
Level 3 - "Chain-computations" like on level 2, but 3+ calculations. Still, no equations, i.e. you are not forced to solve it in an algebraic manner. Example exercise
Level 4 - Exercise needs to be solved by algebraic equations, not possible to calculate numerical "in-between" results. Example exercise
Level 5 -
Level 6 -
Question
Solution
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Video
\(\LaTeX\)
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Exercise:
Der Druck in einem Abschnitt einer horizontalen Röhre mit dem Durchmesser cm betrage kiloPa. Durch die Röhre fliesst Wasser mit einer Geschwindigkeit von .li/s. Wie gross muss der Durchmessern einem verengten Teil der Röhre sein damit der Druck dort kiloPa beträgt?
Solution:
Der Index bezieht sich auf den grösseren Durchmesser und der Index auf den kleineren. Um den Durchmesser im engeren Teil zu ermitteln berechnen wir zuerst mit der Bernoulli-Gleichung die dort vorliege Geschwindigkeit: fracrho_W v_^ +p_ fracrho_W v_^ +p_ myRarrow v_ v_^ + fracDelta prho_W apx . wobei v_ fraVA_ apx . und A_ tfracpi d_^ sind. Nun bestimmen wir mit der Kontinuitätsgleichung die Fläche und aus dieser den Durchmesser des engeren Bereichs. Es gilt: A_ A_fracv_v_ myRarrow d_ d_sqrtfracv_v_ apx .cm.
Der Druck in einem Abschnitt einer horizontalen Röhre mit dem Durchmesser cm betrage kiloPa. Durch die Röhre fliesst Wasser mit einer Geschwindigkeit von .li/s. Wie gross muss der Durchmessern einem verengten Teil der Röhre sein damit der Druck dort kiloPa beträgt?
Solution:
Der Index bezieht sich auf den grösseren Durchmesser und der Index auf den kleineren. Um den Durchmesser im engeren Teil zu ermitteln berechnen wir zuerst mit der Bernoulli-Gleichung die dort vorliege Geschwindigkeit: fracrho_W v_^ +p_ fracrho_W v_^ +p_ myRarrow v_ v_^ + fracDelta prho_W apx . wobei v_ fraVA_ apx . und A_ tfracpi d_^ sind. Nun bestimmen wir mit der Kontinuitätsgleichung die Fläche und aus dieser den Durchmesser des engeren Bereichs. Es gilt: A_ A_fracv_v_ myRarrow d_ d_sqrtfracv_v_ apx .cm.
Meta Information
Exercise:
Der Druck in einem Abschnitt einer horizontalen Röhre mit dem Durchmesser cm betrage kiloPa. Durch die Röhre fliesst Wasser mit einer Geschwindigkeit von .li/s. Wie gross muss der Durchmessern einem verengten Teil der Röhre sein damit der Druck dort kiloPa beträgt?
Solution:
Der Index bezieht sich auf den grösseren Durchmesser und der Index auf den kleineren. Um den Durchmesser im engeren Teil zu ermitteln berechnen wir zuerst mit der Bernoulli-Gleichung die dort vorliege Geschwindigkeit: fracrho_W v_^ +p_ fracrho_W v_^ +p_ myRarrow v_ v_^ + fracDelta prho_W apx . wobei v_ fraVA_ apx . und A_ tfracpi d_^ sind. Nun bestimmen wir mit der Kontinuitätsgleichung die Fläche und aus dieser den Durchmesser des engeren Bereichs. Es gilt: A_ A_fracv_v_ myRarrow d_ d_sqrtfracv_v_ apx .cm.
Der Druck in einem Abschnitt einer horizontalen Röhre mit dem Durchmesser cm betrage kiloPa. Durch die Röhre fliesst Wasser mit einer Geschwindigkeit von .li/s. Wie gross muss der Durchmessern einem verengten Teil der Röhre sein damit der Druck dort kiloPa beträgt?
Solution:
Der Index bezieht sich auf den grösseren Durchmesser und der Index auf den kleineren. Um den Durchmesser im engeren Teil zu ermitteln berechnen wir zuerst mit der Bernoulli-Gleichung die dort vorliege Geschwindigkeit: fracrho_W v_^ +p_ fracrho_W v_^ +p_ myRarrow v_ v_^ + fracDelta prho_W apx . wobei v_ fraVA_ apx . und A_ tfracpi d_^ sind. Nun bestimmen wir mit der Kontinuitätsgleichung die Fläche und aus dieser den Durchmesser des engeren Bereichs. Es gilt: A_ A_fracv_v_ myRarrow d_ d_sqrtfracv_v_ apx .cm.
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