Rollender Stab
About points...
We associate a certain number of points with each exercise.
When you click an exercise into a collection, this number will be taken as points for the exercise, kind of "by default".
But once the exercise is on the collection, you can edit the number of points for the exercise in the collection independently, without any effect on "points by default" as represented by the number here.
That being said... How many "default points" should you associate with an exercise upon creation?
As with difficulty, there is no straight forward and generally accepted way.
But as a guideline, we tend to give as many points by default as there are mathematical steps to do in the exercise.
Again, very vague... But the number should kind of represent the "work" required.
When you click an exercise into a collection, this number will be taken as points for the exercise, kind of "by default".
But once the exercise is on the collection, you can edit the number of points for the exercise in the collection independently, without any effect on "points by default" as represented by the number here.
That being said... How many "default points" should you associate with an exercise upon creation?
As with difficulty, there is no straight forward and generally accepted way.
But as a guideline, we tend to give as many points by default as there are mathematical steps to do in the exercise.
Again, very vague... But the number should kind of represent the "work" required.
About difficulty...
We associate a certain difficulty with each exercise.
When you click an exercise into a collection, this number will be taken as difficulty for the exercise, kind of "by default".
But once the exercise is on the collection, you can edit its difficulty in the collection independently, without any effect on the "difficulty by default" here.
Why we use chess pieces? Well... we like chess, we like playing around with \(\LaTeX\)-fonts, we wanted symbols that need less space than six stars in a table-column... But in your layouts, you are of course free to indicate the difficulty of the exercise the way you want.
That being said... How "difficult" is an exercise? It depends on many factors, like what was being taught etc.
In physics exercises, we try to follow this pattern:
Level 1 - One formula (one you would find in a reference book) is enough to solve the exercise. Example exercise
Level 2 - Two formulas are needed, it's possible to compute an "in-between" solution, i.e. no algebraic equation needed. Example exercise
Level 3 - "Chain-computations" like on level 2, but 3+ calculations. Still, no equations, i.e. you are not forced to solve it in an algebraic manner. Example exercise
Level 4 - Exercise needs to be solved by algebraic equations, not possible to calculate numerical "in-between" results. Example exercise
Level 5 -
Level 6 -
When you click an exercise into a collection, this number will be taken as difficulty for the exercise, kind of "by default".
But once the exercise is on the collection, you can edit its difficulty in the collection independently, without any effect on the "difficulty by default" here.
Why we use chess pieces? Well... we like chess, we like playing around with \(\LaTeX\)-fonts, we wanted symbols that need less space than six stars in a table-column... But in your layouts, you are of course free to indicate the difficulty of the exercise the way you want.
That being said... How "difficult" is an exercise? It depends on many factors, like what was being taught etc.
In physics exercises, we try to follow this pattern:
Level 1 - One formula (one you would find in a reference book) is enough to solve the exercise. Example exercise
Level 2 - Two formulas are needed, it's possible to compute an "in-between" solution, i.e. no algebraic equation needed. Example exercise
Level 3 - "Chain-computations" like on level 2, but 3+ calculations. Still, no equations, i.e. you are not forced to solve it in an algebraic manner. Example exercise
Level 4 - Exercise needs to be solved by algebraic equations, not possible to calculate numerical "in-between" results. Example exercise
Level 5 -
Level 6 -
Question
Solution
Short
Video
\(\LaTeX\)
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Don't forget to subscribe to our channel, like the videos and leave comments!
Exercise:
Ein Aluminiumstab mit der Masse g liegt reibungsfrei beweglich auf zwei parallelen Metallschienen mit dem Abstand mm zwischen denen sich ein homogenes Magnetfeld befindet. Links wird nun eine Spannung angelegt sodass durch den Stab ein Strom von .A fliesst. Dabei bewegt sich der Stab beschleunigt nach rechts und erreicht nach cm eine Geschwindigkeit von .m/s. Wie gross ist die magnetische Flussdichte zwischen den Schienen und in welche Richtung zeigt das B-Feld? center tikzpicturelatex draw very thick .--.--.; draw very thick -.---.---.; node drawcircle inner sep.pt at tiny +; node drawcircle inner sep.pt at -. tiny -; draw fillgray! .-. rectangle nodemidwayrotate tiny Stab ..; draw -thick .-.--.-. noderight tiny Bewegungsrichtung; draw - thick .-.-- noderight tiny mm ..; tikzpicture center
Solution:
Es gilt: flB I ellm a a berechnen wir wie folgt. sscve^v_^+asRa afracsscve^-s.sim/s^ Wir erhalten: BfracIellm aresmT Das B-Feld zeigt senkrecht in die Zeichenfläche hinein. Alternativer Lösungsweg über: Ekinfl s
Ein Aluminiumstab mit der Masse g liegt reibungsfrei beweglich auf zwei parallelen Metallschienen mit dem Abstand mm zwischen denen sich ein homogenes Magnetfeld befindet. Links wird nun eine Spannung angelegt sodass durch den Stab ein Strom von .A fliesst. Dabei bewegt sich der Stab beschleunigt nach rechts und erreicht nach cm eine Geschwindigkeit von .m/s. Wie gross ist die magnetische Flussdichte zwischen den Schienen und in welche Richtung zeigt das B-Feld? center tikzpicturelatex draw very thick .--.--.; draw very thick -.---.---.; node drawcircle inner sep.pt at tiny +; node drawcircle inner sep.pt at -. tiny -; draw fillgray! .-. rectangle nodemidwayrotate tiny Stab ..; draw -thick .-.--.-. noderight tiny Bewegungsrichtung; draw - thick .-.-- noderight tiny mm ..; tikzpicture center
Solution:
Es gilt: flB I ellm a a berechnen wir wie folgt. sscve^v_^+asRa afracsscve^-s.sim/s^ Wir erhalten: BfracIellm aresmT Das B-Feld zeigt senkrecht in die Zeichenfläche hinein. Alternativer Lösungsweg über: Ekinfl s
Meta Information
Exercise:
Ein Aluminiumstab mit der Masse g liegt reibungsfrei beweglich auf zwei parallelen Metallschienen mit dem Abstand mm zwischen denen sich ein homogenes Magnetfeld befindet. Links wird nun eine Spannung angelegt sodass durch den Stab ein Strom von .A fliesst. Dabei bewegt sich der Stab beschleunigt nach rechts und erreicht nach cm eine Geschwindigkeit von .m/s. Wie gross ist die magnetische Flussdichte zwischen den Schienen und in welche Richtung zeigt das B-Feld? center tikzpicturelatex draw very thick .--.--.; draw very thick -.---.---.; node drawcircle inner sep.pt at tiny +; node drawcircle inner sep.pt at -. tiny -; draw fillgray! .-. rectangle nodemidwayrotate tiny Stab ..; draw -thick .-.--.-. noderight tiny Bewegungsrichtung; draw - thick .-.-- noderight tiny mm ..; tikzpicture center
Solution:
Es gilt: flB I ellm a a berechnen wir wie folgt. sscve^v_^+asRa afracsscve^-s.sim/s^ Wir erhalten: BfracIellm aresmT Das B-Feld zeigt senkrecht in die Zeichenfläche hinein. Alternativer Lösungsweg über: Ekinfl s
Ein Aluminiumstab mit der Masse g liegt reibungsfrei beweglich auf zwei parallelen Metallschienen mit dem Abstand mm zwischen denen sich ein homogenes Magnetfeld befindet. Links wird nun eine Spannung angelegt sodass durch den Stab ein Strom von .A fliesst. Dabei bewegt sich der Stab beschleunigt nach rechts und erreicht nach cm eine Geschwindigkeit von .m/s. Wie gross ist die magnetische Flussdichte zwischen den Schienen und in welche Richtung zeigt das B-Feld? center tikzpicturelatex draw very thick .--.--.; draw very thick -.---.---.; node drawcircle inner sep.pt at tiny +; node drawcircle inner sep.pt at -. tiny -; draw fillgray! .-. rectangle nodemidwayrotate tiny Stab ..; draw -thick .-.--.-. noderight tiny Bewegungsrichtung; draw - thick .-.-- noderight tiny mm ..; tikzpicture center
Solution:
Es gilt: flB I ellm a a berechnen wir wie folgt. sscve^v_^+asRa afracsscve^-s.sim/s^ Wir erhalten: BfracIellm aresmT Das B-Feld zeigt senkrecht in die Zeichenfläche hinein. Alternativer Lösungsweg über: Ekinfl s
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