Same place events
About points...
We associate a certain number of points with each exercise.
When you click an exercise into a collection, this number will be taken as points for the exercise, kind of "by default".
But once the exercise is on the collection, you can edit the number of points for the exercise in the collection independently, without any effect on "points by default" as represented by the number here.
That being said... How many "default points" should you associate with an exercise upon creation?
As with difficulty, there is no straight forward and generally accepted way.
But as a guideline, we tend to give as many points by default as there are mathematical steps to do in the exercise.
Again, very vague... But the number should kind of represent the "work" required.
When you click an exercise into a collection, this number will be taken as points for the exercise, kind of "by default".
But once the exercise is on the collection, you can edit the number of points for the exercise in the collection independently, without any effect on "points by default" as represented by the number here.
That being said... How many "default points" should you associate with an exercise upon creation?
As with difficulty, there is no straight forward and generally accepted way.
But as a guideline, we tend to give as many points by default as there are mathematical steps to do in the exercise.
Again, very vague... But the number should kind of represent the "work" required.
About difficulty...
We associate a certain difficulty with each exercise.
When you click an exercise into a collection, this number will be taken as difficulty for the exercise, kind of "by default".
But once the exercise is on the collection, you can edit its difficulty in the collection independently, without any effect on the "difficulty by default" here.
Why we use chess pieces? Well... we like chess, we like playing around with \(\LaTeX\)-fonts, we wanted symbols that need less space than six stars in a table-column... But in your layouts, you are of course free to indicate the difficulty of the exercise the way you want.
That being said... How "difficult" is an exercise? It depends on many factors, like what was being taught etc.
In physics exercises, we try to follow this pattern:
Level 1 - One formula (one you would find in a reference book) is enough to solve the exercise. Example exercise
Level 2 - Two formulas are needed, it's possible to compute an "in-between" solution, i.e. no algebraic equation needed. Example exercise
Level 3 - "Chain-computations" like on level 2, but 3+ calculations. Still, no equations, i.e. you are not forced to solve it in an algebraic manner. Example exercise
Level 4 - Exercise needs to be solved by algebraic equations, not possible to calculate numerical "in-between" results. Example exercise
Level 5 -
Level 6 -
When you click an exercise into a collection, this number will be taken as difficulty for the exercise, kind of "by default".
But once the exercise is on the collection, you can edit its difficulty in the collection independently, without any effect on the "difficulty by default" here.
Why we use chess pieces? Well... we like chess, we like playing around with \(\LaTeX\)-fonts, we wanted symbols that need less space than six stars in a table-column... But in your layouts, you are of course free to indicate the difficulty of the exercise the way you want.
That being said... How "difficult" is an exercise? It depends on many factors, like what was being taught etc.
In physics exercises, we try to follow this pattern:
Level 1 - One formula (one you would find in a reference book) is enough to solve the exercise. Example exercise
Level 2 - Two formulas are needed, it's possible to compute an "in-between" solution, i.e. no algebraic equation needed. Example exercise
Level 3 - "Chain-computations" like on level 2, but 3+ calculations. Still, no equations, i.e. you are not forced to solve it in an algebraic manner. Example exercise
Level 4 - Exercise needs to be solved by algebraic equations, not possible to calculate numerical "in-between" results. Example exercise
Level 5 -
Level 6 -
Question
Solution
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Exercise:
Two events occur at the same place in a certain inertial frame and are separated by a time erval of s. What is the spatial separation between these two events in an inertial frame in which the events are separated by a time erval of s?
Solution:
center tikzpicture scope foreach y in ... drawthin colorblack!!white y--y; foreach x in ... drawthin colorblack!!white x--x; drawthick colorgreen!!black-stealth -.--. nodeabove x; drawthick colorgreen!!black-stealth -.--. noderight ct; drawthick colorred .--. nodeabove same place; filldrawcolorblue . circle .cm; filldrawcolorblue . circle .cm; scope scopexshiftcm defbta. defgam. foreach y in ... drawthin colorblack!!white -.*bta+y--*bta+y; foreach x in ... drawthin colorblack!!white -.*bta+x--*bta+x; drawthick colorgreen!!black-stealth -.-.*bta--*bta nodeabove x'; drawthick colorgreen!!black-stealth -.*bta-.--*bta noderight ct'; drawthin dashed colorgreen!!black-stealth -.--. nodeabove x; drawthin dashed colorgreen!!black-stealth -.--. noderight ct; drawcolorred dashed .--.; drawcolorred dashed .--.; filldrawcolorblue . circle .cm; filldrawcolorblue . circle .cm; scope tikzpicture center The s of the Lorentz transformation are: Delta x' gamma Delta x - v Delta t Delta t' gamma leftDelta t - fracv Delta xc^ right Given data of the exercise are: Delta x & Delta x' Delta t s & Delta t' s Second of the Lorentz transformation leads to: Delta t' gamma leftDelta t - fracv Delta xc^ right gamma leftDelta t - right gamma fracDelta t'Delta t fracss . beta sqrt-fracgamma^ sqrt-frac.^ . v beta c .c v The spatial difference between the two events is in the second frame of reference mathcalS' is therefore: Delta x' gamma Delta x - v Delta t -gamma v Delta t -. . ncc s -.em The minus sign means that the second event is located before the first event on the x'-axis of system mathcalS' as can be seen in the sketch above.
Two events occur at the same place in a certain inertial frame and are separated by a time erval of s. What is the spatial separation between these two events in an inertial frame in which the events are separated by a time erval of s?
Solution:
center tikzpicture scope foreach y in ... drawthin colorblack!!white y--y; foreach x in ... drawthin colorblack!!white x--x; drawthick colorgreen!!black-stealth -.--. nodeabove x; drawthick colorgreen!!black-stealth -.--. noderight ct; drawthick colorred .--. nodeabove same place; filldrawcolorblue . circle .cm; filldrawcolorblue . circle .cm; scope scopexshiftcm defbta. defgam. foreach y in ... drawthin colorblack!!white -.*bta+y--*bta+y; foreach x in ... drawthin colorblack!!white -.*bta+x--*bta+x; drawthick colorgreen!!black-stealth -.-.*bta--*bta nodeabove x'; drawthick colorgreen!!black-stealth -.*bta-.--*bta noderight ct'; drawthin dashed colorgreen!!black-stealth -.--. nodeabove x; drawthin dashed colorgreen!!black-stealth -.--. noderight ct; drawcolorred dashed .--.; drawcolorred dashed .--.; filldrawcolorblue . circle .cm; filldrawcolorblue . circle .cm; scope tikzpicture center The s of the Lorentz transformation are: Delta x' gamma Delta x - v Delta t Delta t' gamma leftDelta t - fracv Delta xc^ right Given data of the exercise are: Delta x & Delta x' Delta t s & Delta t' s Second of the Lorentz transformation leads to: Delta t' gamma leftDelta t - fracv Delta xc^ right gamma leftDelta t - right gamma fracDelta t'Delta t fracss . beta sqrt-fracgamma^ sqrt-frac.^ . v beta c .c v The spatial difference between the two events is in the second frame of reference mathcalS' is therefore: Delta x' gamma Delta x - v Delta t -gamma v Delta t -. . ncc s -.em The minus sign means that the second event is located before the first event on the x'-axis of system mathcalS' as can be seen in the sketch above.
Meta Information
Exercise:
Two events occur at the same place in a certain inertial frame and are separated by a time erval of s. What is the spatial separation between these two events in an inertial frame in which the events are separated by a time erval of s?
Solution:
center tikzpicture scope foreach y in ... drawthin colorblack!!white y--y; foreach x in ... drawthin colorblack!!white x--x; drawthick colorgreen!!black-stealth -.--. nodeabove x; drawthick colorgreen!!black-stealth -.--. noderight ct; drawthick colorred .--. nodeabove same place; filldrawcolorblue . circle .cm; filldrawcolorblue . circle .cm; scope scopexshiftcm defbta. defgam. foreach y in ... drawthin colorblack!!white -.*bta+y--*bta+y; foreach x in ... drawthin colorblack!!white -.*bta+x--*bta+x; drawthick colorgreen!!black-stealth -.-.*bta--*bta nodeabove x'; drawthick colorgreen!!black-stealth -.*bta-.--*bta noderight ct'; drawthin dashed colorgreen!!black-stealth -.--. nodeabove x; drawthin dashed colorgreen!!black-stealth -.--. noderight ct; drawcolorred dashed .--.; drawcolorred dashed .--.; filldrawcolorblue . circle .cm; filldrawcolorblue . circle .cm; scope tikzpicture center The s of the Lorentz transformation are: Delta x' gamma Delta x - v Delta t Delta t' gamma leftDelta t - fracv Delta xc^ right Given data of the exercise are: Delta x & Delta x' Delta t s & Delta t' s Second of the Lorentz transformation leads to: Delta t' gamma leftDelta t - fracv Delta xc^ right gamma leftDelta t - right gamma fracDelta t'Delta t fracss . beta sqrt-fracgamma^ sqrt-frac.^ . v beta c .c v The spatial difference between the two events is in the second frame of reference mathcalS' is therefore: Delta x' gamma Delta x - v Delta t -gamma v Delta t -. . ncc s -.em The minus sign means that the second event is located before the first event on the x'-axis of system mathcalS' as can be seen in the sketch above.
Two events occur at the same place in a certain inertial frame and are separated by a time erval of s. What is the spatial separation between these two events in an inertial frame in which the events are separated by a time erval of s?
Solution:
center tikzpicture scope foreach y in ... drawthin colorblack!!white y--y; foreach x in ... drawthin colorblack!!white x--x; drawthick colorgreen!!black-stealth -.--. nodeabove x; drawthick colorgreen!!black-stealth -.--. noderight ct; drawthick colorred .--. nodeabove same place; filldrawcolorblue . circle .cm; filldrawcolorblue . circle .cm; scope scopexshiftcm defbta. defgam. foreach y in ... drawthin colorblack!!white -.*bta+y--*bta+y; foreach x in ... drawthin colorblack!!white -.*bta+x--*bta+x; drawthick colorgreen!!black-stealth -.-.*bta--*bta nodeabove x'; drawthick colorgreen!!black-stealth -.*bta-.--*bta noderight ct'; drawthin dashed colorgreen!!black-stealth -.--. nodeabove x; drawthin dashed colorgreen!!black-stealth -.--. noderight ct; drawcolorred dashed .--.; drawcolorred dashed .--.; filldrawcolorblue . circle .cm; filldrawcolorblue . circle .cm; scope tikzpicture center The s of the Lorentz transformation are: Delta x' gamma Delta x - v Delta t Delta t' gamma leftDelta t - fracv Delta xc^ right Given data of the exercise are: Delta x & Delta x' Delta t s & Delta t' s Second of the Lorentz transformation leads to: Delta t' gamma leftDelta t - fracv Delta xc^ right gamma leftDelta t - right gamma fracDelta t'Delta t fracss . beta sqrt-fracgamma^ sqrt-frac.^ . v beta c .c v The spatial difference between the two events is in the second frame of reference mathcalS' is therefore: Delta x' gamma Delta x - v Delta t -gamma v Delta t -. . ncc s -.em The minus sign means that the second event is located before the first event on the x'-axis of system mathcalS' as can be seen in the sketch above.
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