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The following quantities appear in the problem: elektrische Stromstärke \(I\) / elektrische Spannung \(U\) / elektrischer Widerstand \(R\) /
The following formulas must be used to solve the exercise: \(\sum I = 0 \quad \) \(\sum U = 0 \quad \) \(U=RI \quad \) \(\frac{1}{R} = \frac{1}{R_1} + \frac{1}{R_2} \quad \) \(R = R_1 + R_2 \quad \)
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Exercise:
Berechne für die folge Schaltung den Ersatzwiderstand R_ den Gesamtstrom I_ den Strom I_ und alle Teilspannungen U_i i. Die Quellenspannung beträgt U_V die Widerstandswerte R_ohm R_ohm R_ ohm. center circuitikzeuropean draw tobattery invert lU_ toRl^R_ ++. coordinate X to ++. toRl^R_ ++ to ++-. to ++. to ++- to cycle ; draw X to ++-. toRl^R_ ++ to ++.; circuitikz center center tabularxcm|l|X|X|X|X| hline & i & i & i & i hline U_i/siV & num & & & hline I_i/siA & & & cellcolorblack & cellcolorblack hline R_i/siohm & & num & num & num hline tabularx center

Solution:
center tabularxcm|l|X|X|X|X| hline & i & i & i & i hline U_i/siV & num & num & num & num hline I_i/siA & num. & num. & cellcolorblack & cellcolorblack hline R_i/siohm & num & num & num & num hline tabularx center
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Exercise:
Berechne für die folge Schaltung den Ersatzwiderstand R_ den Gesamtstrom I_ den Strom I_ und alle Teilspannungen U_i i. Die Quellenspannung beträgt U_V die Widerstandswerte R_ohm R_ohm R_ ohm. center circuitikzeuropean draw tobattery invert lU_ toRl^R_ ++. coordinate X to ++. toRl^R_ ++ to ++-. to ++. to ++- to cycle ; draw X to ++-. toRl^R_ ++ to ++.; circuitikz center center tabularxcm|l|X|X|X|X| hline & i & i & i & i hline U_i/siV & num & & & hline I_i/siA & & & cellcolorblack & cellcolorblack hline R_i/siohm & & num & num & num hline tabularx center

Solution:
center tabularxcm|l|X|X|X|X| hline & i & i & i & i hline U_i/siV & num & num & num & num hline I_i/siA & num. & num. & cellcolorblack & cellcolorblack hline R_i/siohm & num & num & num & num hline tabularx center
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