Exercise
https://texercises.com/exercise/simple-double-capacitor/
Question
Solution
Short
Video
\(\LaTeX\)
No explanation / solution video to this exercise has yet been created.

Visit our YouTube-Channel to see solutions to other exercises.
Don't forget to subscribe to our channel, like the videos and leave comments!
Exercise:
A double capacitor consists of two fixed outer plates and two connected inner plates. The inner plates can be moved from left to right see figure which causes a change to the distances a and b between the two parallel plate capacitors C_ and C_. Show that the capacitance of the two capacitors in series does not dep on the position of the inner plates. center includegraphicswidth.textwidth#image_path:basic-doublcapacitor# center

Solution:
The two capacitors are C_ varepsilon_ fracAa C_ varepsilon_ fracAb The da+b of the two distances is constant. We can therefore write a x d b -x d with xin. The series capacitance is given by sscCs leftfracC_+fracC_right^- leftfracx dvarepsilon_ A+frac-x dvarepsilon_ Aright^- varepsilon_fracAdleftx+-xright^- varepsilon_fracAd It turns out that the capacitance is indepent of the position of the inner plates and corresponds to a parallel plate capacitor with the same plate area and a distance equal to the of the two distances a and b.
Report An Error
You are on texercises.com.
reCaptcha will only work on our main-domain \(\TeX\)ercises.com!
Meta Information
\(\LaTeX\)-Code
Exercise:
A double capacitor consists of two fixed outer plates and two connected inner plates. The inner plates can be moved from left to right see figure which causes a change to the distances a and b between the two parallel plate capacitors C_ and C_. Show that the capacitance of the two capacitors in series does not dep on the position of the inner plates. center includegraphicswidth.textwidth#image_path:basic-doublcapacitor# center

Solution:
The two capacitors are C_ varepsilon_ fracAa C_ varepsilon_ fracAb The da+b of the two distances is constant. We can therefore write a x d b -x d with xin. The series capacitance is given by sscCs leftfracC_+fracC_right^- leftfracx dvarepsilon_ A+frac-x dvarepsilon_ Aright^- varepsilon_fracAdleftx+-xright^- varepsilon_fracAd It turns out that the capacitance is indepent of the position of the inner plates and corresponds to a parallel plate capacitor with the same plate area and a distance equal to the of the two distances a and b.
Contained in these collections

Similar exercises (13)
Title Matched on
Advanced Double Capacitor tags
Variable Distance Parallel Plate Capacitor tags
Parallel Plate Capacitor tags
Variable Capacitor tags
Spherical Capacitor tags
more (8 more)
Attributes & Decorations
Branches
Electrostatics
Tags
capacitance, capacitor, electrostatic, parallel plate capacitor, series circuit
Difficulty
(2, default)
Points
0 (default)
Language
ENG (English)
Type
Proof
Decoration
Content image