Speed Increase
About points...
We associate a certain number of points with each exercise.
When you click an exercise into a collection, this number will be taken as points for the exercise, kind of "by default".
But once the exercise is on the collection, you can edit the number of points for the exercise in the collection independently, without any effect on "points by default" as represented by the number here.
That being said... How many "default points" should you associate with an exercise upon creation?
As with difficulty, there is no straight forward and generally accepted way.
But as a guideline, we tend to give as many points by default as there are mathematical steps to do in the exercise.
Again, very vague... But the number should kind of represent the "work" required.
When you click an exercise into a collection, this number will be taken as points for the exercise, kind of "by default".
But once the exercise is on the collection, you can edit the number of points for the exercise in the collection independently, without any effect on "points by default" as represented by the number here.
That being said... How many "default points" should you associate with an exercise upon creation?
As with difficulty, there is no straight forward and generally accepted way.
But as a guideline, we tend to give as many points by default as there are mathematical steps to do in the exercise.
Again, very vague... But the number should kind of represent the "work" required.
About difficulty...
We associate a certain difficulty with each exercise.
When you click an exercise into a collection, this number will be taken as difficulty for the exercise, kind of "by default".
But once the exercise is on the collection, you can edit its difficulty in the collection independently, without any effect on the "difficulty by default" here.
Why we use chess pieces? Well... we like chess, we like playing around with \(\LaTeX\)-fonts, we wanted symbols that need less space than six stars in a table-column... But in your layouts, you are of course free to indicate the difficulty of the exercise the way you want.
That being said... How "difficult" is an exercise? It depends on many factors, like what was being taught etc.
In physics exercises, we try to follow this pattern:
Level 1 - One formula (one you would find in a reference book) is enough to solve the exercise. Example exercise
Level 2 - Two formulas are needed, it's possible to compute an "in-between" solution, i.e. no algebraic equation needed. Example exercise
Level 3 - "Chain-computations" like on level 2, but 3+ calculations. Still, no equations, i.e. you are not forced to solve it in an algebraic manner. Example exercise
Level 4 - Exercise needs to be solved by algebraic equations, not possible to calculate numerical "in-between" results. Example exercise
Level 5 -
Level 6 -
When you click an exercise into a collection, this number will be taken as difficulty for the exercise, kind of "by default".
But once the exercise is on the collection, you can edit its difficulty in the collection independently, without any effect on the "difficulty by default" here.
Why we use chess pieces? Well... we like chess, we like playing around with \(\LaTeX\)-fonts, we wanted symbols that need less space than six stars in a table-column... But in your layouts, you are of course free to indicate the difficulty of the exercise the way you want.
That being said... How "difficult" is an exercise? It depends on many factors, like what was being taught etc.
In physics exercises, we try to follow this pattern:
Level 1 - One formula (one you would find in a reference book) is enough to solve the exercise. Example exercise
Level 2 - Two formulas are needed, it's possible to compute an "in-between" solution, i.e. no algebraic equation needed. Example exercise
Level 3 - "Chain-computations" like on level 2, but 3+ calculations. Still, no equations, i.e. you are not forced to solve it in an algebraic manner. Example exercise
Level 4 - Exercise needs to be solved by algebraic equations, not possible to calculate numerical "in-between" results. Example exercise
Level 5 -
Level 6 -
Question
Solution
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Exercise:
Electrons with an initial speed of viO are accelerated to vfO. Calculate the potential difference required for this increase in speed.
Solution:
When an electron is accelerated from the initial speed v_i to the final speed v_f its kinetic energy increases by Delta sscEkinfrac m v_f^ - frac m v_i^ fracmleftv_f^-v_i^right It follows for the acceleration voltage Delta phi fracDeltasscEkinq dVF fracmeqeleftvf^-vi^right dVapproxresultdVP Be aware that the increase in kinetic energy cannot be expressed as frac mDelta v^: Delta v^ leftv_f-v_iright^ v_f^ - v_f v_i + v_i^ &neq v_f^ - v_i^ quadtextfor v_i neq
Electrons with an initial speed of viO are accelerated to vfO. Calculate the potential difference required for this increase in speed.
Solution:
When an electron is accelerated from the initial speed v_i to the final speed v_f its kinetic energy increases by Delta sscEkinfrac m v_f^ - frac m v_i^ fracmleftv_f^-v_i^right It follows for the acceleration voltage Delta phi fracDeltasscEkinq dVF fracmeqeleftvf^-vi^right dVapproxresultdVP Be aware that the increase in kinetic energy cannot be expressed as frac mDelta v^: Delta v^ leftv_f-v_iright^ v_f^ - v_f v_i + v_i^ &neq v_f^ - v_i^ quadtextfor v_i neq
Meta Information
Exercise:
Electrons with an initial speed of viO are accelerated to vfO. Calculate the potential difference required for this increase in speed.
Solution:
When an electron is accelerated from the initial speed v_i to the final speed v_f its kinetic energy increases by Delta sscEkinfrac m v_f^ - frac m v_i^ fracmleftv_f^-v_i^right It follows for the acceleration voltage Delta phi fracDeltasscEkinq dVF fracmeqeleftvf^-vi^right dVapproxresultdVP Be aware that the increase in kinetic energy cannot be expressed as frac mDelta v^: Delta v^ leftv_f-v_iright^ v_f^ - v_f v_i + v_i^ &neq v_f^ - v_i^ quadtextfor v_i neq
Electrons with an initial speed of viO are accelerated to vfO. Calculate the potential difference required for this increase in speed.
Solution:
When an electron is accelerated from the initial speed v_i to the final speed v_f its kinetic energy increases by Delta sscEkinfrac m v_f^ - frac m v_i^ fracmleftv_f^-v_i^right It follows for the acceleration voltage Delta phi fracDeltasscEkinq dVF fracmeqeleftvf^-vi^right dVapproxresultdVP Be aware that the increase in kinetic energy cannot be expressed as frac mDelta v^: Delta v^ leftv_f-v_iright^ v_f^ - v_f v_i + v_i^ &neq v_f^ - v_i^ quadtextfor v_i neq
Contained in these collections:
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Acceleration Voltage by by
Asked Quantity:
elektrische Spannung \(U\)
in
Volt \(\rm V\)
Physical Quantity
Unit