Sprungbrett die Zweite
About points...
We associate a certain number of points with each exercise.
When you click an exercise into a collection, this number will be taken as points for the exercise, kind of "by default".
But once the exercise is on the collection, you can edit the number of points for the exercise in the collection independently, without any effect on "points by default" as represented by the number here.
That being said... How many "default points" should you associate with an exercise upon creation?
As with difficulty, there is no straight forward and generally accepted way.
But as a guideline, we tend to give as many points by default as there are mathematical steps to do in the exercise.
Again, very vague... But the number should kind of represent the "work" required.
When you click an exercise into a collection, this number will be taken as points for the exercise, kind of "by default".
But once the exercise is on the collection, you can edit the number of points for the exercise in the collection independently, without any effect on "points by default" as represented by the number here.
That being said... How many "default points" should you associate with an exercise upon creation?
As with difficulty, there is no straight forward and generally accepted way.
But as a guideline, we tend to give as many points by default as there are mathematical steps to do in the exercise.
Again, very vague... But the number should kind of represent the "work" required.
About difficulty...
We associate a certain difficulty with each exercise.
When you click an exercise into a collection, this number will be taken as difficulty for the exercise, kind of "by default".
But once the exercise is on the collection, you can edit its difficulty in the collection independently, without any effect on the "difficulty by default" here.
Why we use chess pieces? Well... we like chess, we like playing around with \(\LaTeX\)-fonts, we wanted symbols that need less space than six stars in a table-column... But in your layouts, you are of course free to indicate the difficulty of the exercise the way you want.
That being said... How "difficult" is an exercise? It depends on many factors, like what was being taught etc.
In physics exercises, we try to follow this pattern:
Level 1 - One formula (one you would find in a reference book) is enough to solve the exercise. Example exercise
Level 2 - Two formulas are needed, it's possible to compute an "in-between" solution, i.e. no algebraic equation needed. Example exercise
Level 3 - "Chain-computations" like on level 2, but 3+ calculations. Still, no equations, i.e. you are not forced to solve it in an algebraic manner. Example exercise
Level 4 - Exercise needs to be solved by algebraic equations, not possible to calculate numerical "in-between" results. Example exercise
Level 5 -
Level 6 -
When you click an exercise into a collection, this number will be taken as difficulty for the exercise, kind of "by default".
But once the exercise is on the collection, you can edit its difficulty in the collection independently, without any effect on the "difficulty by default" here.
Why we use chess pieces? Well... we like chess, we like playing around with \(\LaTeX\)-fonts, we wanted symbols that need less space than six stars in a table-column... But in your layouts, you are of course free to indicate the difficulty of the exercise the way you want.
That being said... How "difficult" is an exercise? It depends on many factors, like what was being taught etc.
In physics exercises, we try to follow this pattern:
Level 1 - One formula (one you would find in a reference book) is enough to solve the exercise. Example exercise
Level 2 - Two formulas are needed, it's possible to compute an "in-between" solution, i.e. no algebraic equation needed. Example exercise
Level 3 - "Chain-computations" like on level 2, but 3+ calculations. Still, no equations, i.e. you are not forced to solve it in an algebraic manner. Example exercise
Level 4 - Exercise needs to be solved by algebraic equations, not possible to calculate numerical "in-between" results. Example exercise
Level 5 -
Level 6 -
Question
Solution
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Video
\(\LaTeX\)
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Don't forget to subscribe to our channel, like the videos and leave comments!
Exercise:
Ein Sprungbrett von .m Länge und kg Masse wird am linken Rand bei A nach unten und cm rechts davon bei B nach oben gedrückt. Wie gross sind die Kräfte bei A und B aufs Brett wenn ganz vorne rechts auf dem Sprungbrett bei C ein Kind von kg steht?
Solution:
Es bietet sich an den Drehpunkt bei A zu wählen und den Drehsinn im Uhrzeigersinn. Dann gilt: F_g_Brr_Br - F_N_Br_B + F_g_Cr_C Damit erhalten wir für die Normalkraft bei B: F_N_B fracF_g_Brr_Br + F_g_Cr_Cr_B apx N. Für das Kräftegleichgewicht gilt: F_N_A F_N_B - F_g_Br - F_g_C apx N.
Ein Sprungbrett von .m Länge und kg Masse wird am linken Rand bei A nach unten und cm rechts davon bei B nach oben gedrückt. Wie gross sind die Kräfte bei A und B aufs Brett wenn ganz vorne rechts auf dem Sprungbrett bei C ein Kind von kg steht?
Solution:
Es bietet sich an den Drehpunkt bei A zu wählen und den Drehsinn im Uhrzeigersinn. Dann gilt: F_g_Brr_Br - F_N_Br_B + F_g_Cr_C Damit erhalten wir für die Normalkraft bei B: F_N_B fracF_g_Brr_Br + F_g_Cr_Cr_B apx N. Für das Kräftegleichgewicht gilt: F_N_A F_N_B - F_g_Br - F_g_C apx N.
Meta Information
Exercise:
Ein Sprungbrett von .m Länge und kg Masse wird am linken Rand bei A nach unten und cm rechts davon bei B nach oben gedrückt. Wie gross sind die Kräfte bei A und B aufs Brett wenn ganz vorne rechts auf dem Sprungbrett bei C ein Kind von kg steht?
Solution:
Es bietet sich an den Drehpunkt bei A zu wählen und den Drehsinn im Uhrzeigersinn. Dann gilt: F_g_Brr_Br - F_N_Br_B + F_g_Cr_C Damit erhalten wir für die Normalkraft bei B: F_N_B fracF_g_Brr_Br + F_g_Cr_Cr_B apx N. Für das Kräftegleichgewicht gilt: F_N_A F_N_B - F_g_Br - F_g_C apx N.
Ein Sprungbrett von .m Länge und kg Masse wird am linken Rand bei A nach unten und cm rechts davon bei B nach oben gedrückt. Wie gross sind die Kräfte bei A und B aufs Brett wenn ganz vorne rechts auf dem Sprungbrett bei C ein Kind von kg steht?
Solution:
Es bietet sich an den Drehpunkt bei A zu wählen und den Drehsinn im Uhrzeigersinn. Dann gilt: F_g_Brr_Br - F_N_Br_B + F_g_Cr_C Damit erhalten wir für die Normalkraft bei B: F_N_B fracF_g_Brr_Br + F_g_Cr_Cr_B apx N. Für das Kräftegleichgewicht gilt: F_N_A F_N_B - F_g_Br - F_g_C apx N.
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Tischplatte oder Sprungbrett by TeXercises