Stahlseil um die Erde
About points...
We associate a certain number of points with each exercise.
When you click an exercise into a collection, this number will be taken as points for the exercise, kind of "by default".
But once the exercise is on the collection, you can edit the number of points for the exercise in the collection independently, without any effect on "points by default" as represented by the number here.
That being said... How many "default points" should you associate with an exercise upon creation?
As with difficulty, there is no straight forward and generally accepted way.
But as a guideline, we tend to give as many points by default as there are mathematical steps to do in the exercise.
Again, very vague... But the number should kind of represent the "work" required.
When you click an exercise into a collection, this number will be taken as points for the exercise, kind of "by default".
But once the exercise is on the collection, you can edit the number of points for the exercise in the collection independently, without any effect on "points by default" as represented by the number here.
That being said... How many "default points" should you associate with an exercise upon creation?
As with difficulty, there is no straight forward and generally accepted way.
But as a guideline, we tend to give as many points by default as there are mathematical steps to do in the exercise.
Again, very vague... But the number should kind of represent the "work" required.
About difficulty...
We associate a certain difficulty with each exercise.
When you click an exercise into a collection, this number will be taken as difficulty for the exercise, kind of "by default".
But once the exercise is on the collection, you can edit its difficulty in the collection independently, without any effect on the "difficulty by default" here.
Why we use chess pieces? Well... we like chess, we like playing around with \(\LaTeX\)-fonts, we wanted symbols that need less space than six stars in a table-column... But in your layouts, you are of course free to indicate the difficulty of the exercise the way you want.
That being said... How "difficult" is an exercise? It depends on many factors, like what was being taught etc.
In physics exercises, we try to follow this pattern:
Level 1 - One formula (one you would find in a reference book) is enough to solve the exercise. Example exercise
Level 2 - Two formulas are needed, it's possible to compute an "in-between" solution, i.e. no algebraic equation needed. Example exercise
Level 3 - "Chain-computations" like on level 2, but 3+ calculations. Still, no equations, i.e. you are not forced to solve it in an algebraic manner. Example exercise
Level 4 - Exercise needs to be solved by algebraic equations, not possible to calculate numerical "in-between" results. Example exercise
Level 5 -
Level 6 -
When you click an exercise into a collection, this number will be taken as difficulty for the exercise, kind of "by default".
But once the exercise is on the collection, you can edit its difficulty in the collection independently, without any effect on the "difficulty by default" here.
Why we use chess pieces? Well... we like chess, we like playing around with \(\LaTeX\)-fonts, we wanted symbols that need less space than six stars in a table-column... But in your layouts, you are of course free to indicate the difficulty of the exercise the way you want.
That being said... How "difficult" is an exercise? It depends on many factors, like what was being taught etc.
In physics exercises, we try to follow this pattern:
Level 1 - One formula (one you would find in a reference book) is enough to solve the exercise. Example exercise
Level 2 - Two formulas are needed, it's possible to compute an "in-between" solution, i.e. no algebraic equation needed. Example exercise
Level 3 - "Chain-computations" like on level 2, but 3+ calculations. Still, no equations, i.e. you are not forced to solve it in an algebraic manner. Example exercise
Level 4 - Exercise needs to be solved by algebraic equations, not possible to calculate numerical "in-between" results. Example exercise
Level 5 -
Level 6 -
Question
Solution
Short
Video
\(\LaTeX\)
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Exercise:
Um den Erdäquator werde bei degreeCelsius ein Stahlseil Formelbuchper-modereciprocalperkelvin gespannt. Wie gross ist bei degreeCelsius der Abstand zur Erdoberfläche?
Solution:
pmrec AnzahlStellen newqtyDTcelsius newqtyrE.em newqtya.perkelvin % Geg Deltatheta DT sscrE rE alpha a % GesAbstandDelta r sim % Das Stahlband hat bei celsius einen Umfang von solqtyuEpi ssc rE*pi*rEnm al ssc uE uEf pi rE uE. Bei DT dehnt sich dieser auf solqtyupi ssc rE + alpha DeltathetauEn*+an*DTnm al u ssc uE +alpha Deltatheta uf uE qty+a DT u aus. Somit ist der neue Radius des Stahlseils solqtyrssc rE qty+ alpha Deltathetaun/*pim al r fracupi rf fracupi r. Der Abstand zur Erdoberfläche ist folglich solqtyDrsscrEalphaDeltathetarEn*an*DTnm al Delta r r - sscrE Drf r - rE Dr % Delta r Drf TecDr AnzahlStellen pmfrac Hinweis: Man kann auch argumentieren dass sich der Radius und die Radiusveränderung stets proportional zum Umfang verhält d.h. r sim u und deshalb einfach die Radiusveränderung mit der Längenausdehnungsformel berechnet werden kann.
Um den Erdäquator werde bei degreeCelsius ein Stahlseil Formelbuchper-modereciprocalperkelvin gespannt. Wie gross ist bei degreeCelsius der Abstand zur Erdoberfläche?
Solution:
pmrec AnzahlStellen newqtyDTcelsius newqtyrE.em newqtya.perkelvin % Geg Deltatheta DT sscrE rE alpha a % GesAbstandDelta r sim % Das Stahlband hat bei celsius einen Umfang von solqtyuEpi ssc rE*pi*rEnm al ssc uE uEf pi rE uE. Bei DT dehnt sich dieser auf solqtyupi ssc rE + alpha DeltathetauEn*+an*DTnm al u ssc uE +alpha Deltatheta uf uE qty+a DT u aus. Somit ist der neue Radius des Stahlseils solqtyrssc rE qty+ alpha Deltathetaun/*pim al r fracupi rf fracupi r. Der Abstand zur Erdoberfläche ist folglich solqtyDrsscrEalphaDeltathetarEn*an*DTnm al Delta r r - sscrE Drf r - rE Dr % Delta r Drf TecDr AnzahlStellen pmfrac Hinweis: Man kann auch argumentieren dass sich der Radius und die Radiusveränderung stets proportional zum Umfang verhält d.h. r sim u und deshalb einfach die Radiusveränderung mit der Längenausdehnungsformel berechnet werden kann.
Meta Information
Exercise:
Um den Erdäquator werde bei degreeCelsius ein Stahlseil Formelbuchper-modereciprocalperkelvin gespannt. Wie gross ist bei degreeCelsius der Abstand zur Erdoberfläche?
Solution:
pmrec AnzahlStellen newqtyDTcelsius newqtyrE.em newqtya.perkelvin % Geg Deltatheta DT sscrE rE alpha a % GesAbstandDelta r sim % Das Stahlband hat bei celsius einen Umfang von solqtyuEpi ssc rE*pi*rEnm al ssc uE uEf pi rE uE. Bei DT dehnt sich dieser auf solqtyupi ssc rE + alpha DeltathetauEn*+an*DTnm al u ssc uE +alpha Deltatheta uf uE qty+a DT u aus. Somit ist der neue Radius des Stahlseils solqtyrssc rE qty+ alpha Deltathetaun/*pim al r fracupi rf fracupi r. Der Abstand zur Erdoberfläche ist folglich solqtyDrsscrEalphaDeltathetarEn*an*DTnm al Delta r r - sscrE Drf r - rE Dr % Delta r Drf TecDr AnzahlStellen pmfrac Hinweis: Man kann auch argumentieren dass sich der Radius und die Radiusveränderung stets proportional zum Umfang verhält d.h. r sim u und deshalb einfach die Radiusveränderung mit der Längenausdehnungsformel berechnet werden kann.
Um den Erdäquator werde bei degreeCelsius ein Stahlseil Formelbuchper-modereciprocalperkelvin gespannt. Wie gross ist bei degreeCelsius der Abstand zur Erdoberfläche?
Solution:
pmrec AnzahlStellen newqtyDTcelsius newqtyrE.em newqtya.perkelvin % Geg Deltatheta DT sscrE rE alpha a % GesAbstandDelta r sim % Das Stahlband hat bei celsius einen Umfang von solqtyuEpi ssc rE*pi*rEnm al ssc uE uEf pi rE uE. Bei DT dehnt sich dieser auf solqtyupi ssc rE + alpha DeltathetauEn*+an*DTnm al u ssc uE +alpha Deltatheta uf uE qty+a DT u aus. Somit ist der neue Radius des Stahlseils solqtyrssc rE qty+ alpha Deltathetaun/*pim al r fracupi rf fracupi r. Der Abstand zur Erdoberfläche ist folglich solqtyDrsscrEalphaDeltathetarEn*an*DTnm al Delta r r - sscrE Drf r - rE Dr % Delta r Drf TecDr AnzahlStellen pmfrac Hinweis: Man kann auch argumentieren dass sich der Radius und die Radiusveränderung stets proportional zum Umfang verhält d.h. r sim u und deshalb einfach die Radiusveränderung mit der Längenausdehnungsformel berechnet werden kann.
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Thermische Ausdehnung by pw